date_format problem

[adamalton]

I am trying to take a date in the format "YYYY-MM-DD" and get from it the month as a word (e.g. July) and the day as a 2 digit number (e.g. 24).

I am trying to use the date_format function, (new as of php 5.2) but I can't get it to work...

[PHP]
$date = "2007-06-22 00:00:00";
//I also tried $date = "2007-06-22"; but that didn't work either
//I also tried adding strtotime($date ); but that didn't help!

$month = date_format($da te , 'F');
$day = date_format($da te, 'd');

print"$month<br >";
print"$day<br>" ;
[/PHP]

[adamalton]

I am running PHP 5.2.1 on mac OS 10.4.8

[ronverdonk]

Try this one
[php]echo date('l, F jS Y', strtotime($date ));[/php]

Ronald :cool:

[Atli]

Hi.

I modified you code so it returns to you the month as 3 letter word and the day as 2 digits, like this:
Sep 05

[PHP]
$date = "2007-06-22 00:00:00";

// get the parts you need from the string
// and turn them into numbers (abs)
$year = abs(substr($dat e, 0, 4));
$month = abs(substr($dat e, 5, 2));
$day = abs(substr($dat e, 8, 2));

// Create the output string
$output = date("M d", mktime(0, 0, 0,$month, $day, $year));

// print
print $output;
[/PHP]

You should check out the date and mktime methods at php.net

Hope this helps.