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SELECTing using DATE_FORMAT

I have been trying to run this MySQL query using PHP:

SELECT id, trans_type, remote_addr, DATE_FORMAT(tim e, '%M %e, %Y %r') as time
FROM transactions WHERE client_id = " . $client_id . " ORDER BY time asc

and I am getting this error message:

MySQL Error number: 1064: You have an error in your SQL syntax near 'ORDER BY time asc' at line 2

I added the "as time" in hopes it wasn't seeing the 'DATE_FORMAT()' field as the time field.

Does anyone have any advice?

Thanks in advance,

Rick Barnes
Jul 17 '05 #1
2 3076
Rick wrote:
I have been trying to run this MySQL query using PHP:

SELECT id, trans_type, remote_addr, DATE_FORMAT(tim e, '%M %e, %Y %r')
as time
FROM transactions WHERE client_id = " . $client_id . " ORDER BY time asc

and I am getting this error message:

MySQL Error number: 1064: You have an error in your SQL syntax near
'ORDER BY time asc' at line 2

I added the "as time" in hopes it wasn't seeing the 'DATE_FORMAT()' field
as the time field.

Does anyone have any advice?

Thanks in advance,

Rick Barnes


Sorry I just noticed this only happens when there are no records...this error occurs before I can
check the value of the returned query handle...how can this be avoided without running 2 queries?
One to check for any records and the other to run if there are any? I currently use:

"$result = mysql_query($qu ery)or die("MySQL Error number: " . mysql_errno() . ": " . mysql_error().
"\n");

Should I leave this out so I can test the returned handle's value ($result)?

TIA,

RB
Jul 17 '05 #2
time is an SQL reserved word

try:

SELECT id, trans_type, remote_addr, DATE_FORMAT(tim e, '%M %e, %Y %r')
as my_time
FROM transactions WHERE client_id = " . $client_id . " ORDER BY my_time asc

Hope this helps
Richard

Rick wrote:
Rick wrote:
I have been trying to run this MySQL query using PHP:

SELECT id, trans_type, remote_addr, DATE_FORMAT(tim e, '%M %e, %Y
%r') as time
FROM transactions WHERE client_id = " . $client_id . " ORDER BY time asc

and I am getting this error message:

MySQL Error number: 1064: You have an error in your SQL syntax near
'ORDER BY time asc' at line 2

I added the "as time" in hopes it wasn't seeing the
'DATE_FORMAT()' field as the time field.

Does anyone have any advice?

Thanks in advance,

Rick Barnes

Sorry I just noticed this only happens when there are no records...this
error occurs before I can check the value of the returned query
handle...how can this be avoided without running 2 queries? One to check
for any records and the other to run if there are any? I currently use:

"$result = mysql_query($qu ery)or die("MySQL Error number: " .
mysql_errno() . ": " . mysql_error(). "\n");

Should I leave this out so I can test the returned handle's value
($result)?

TIA,

RB

Jul 17 '05 #3

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