multiplication math not working ?

[One]

hi group -

I had this in a function - so I've just moved this out of the function
for readabilty.

Can someone please tell me WHY does this not return the result of :
n1 times n2

As I said - I took it out of the function just for readability :
In my php file :

$number_percent ="25";
echo "history['order_total'] is ".$history['order_total']."<br />";
echo "number_per cent is ".$number_perce nt."<br />";
$total=(($histo ry['order_total'])*$number_perce nt);
echo "total is ".$total."< br />";

And here is the output in the browser :
history['order_total'] is $241.47
number_percent is 25
total is 0

WHY ? Any advice or pointers would be much appreciated!

[Rik]

One <da**********@g mail.comwrote:

hi group -

I had this in a function - so I've just moved this out of the function
for readabilty.

Can someone please tell me WHY does this not return the result of :
n1 times n2

As I said - I took it out of the function just for readability :
In my php file :

$number_percent ="25";
echo "history['order_total'] is ".$history['order_total']."<br />";
echo "number_per cent is ".$number_perce nt."<br />";
$total=(($histo ry['order_total'])*$number_perce nt);
echo "total is ".$total."< br />";

And here is the output in the browser :
history['order_total'] is $241.47
number_percent is 25
total is 0

WHY ? Any advice or pointers would be much appreciated!

Because '$241.47' is not a number, it's a string representation of a
currency. PHP doesn't know anything about that, 'currency' is not a type..
When performing math on it, PHP will try to make a number out of it, and
encounters '$' as the first character. This is not something it
recognizes, and it will default to 0. And 0 * 25 = 0.

You might want to remove the currency symbol from the string, and just add
it back when you have to echo/print the total.

Also, I'd think if $number_percent = 25, you might want $total =
$history['order_total'] * (1+($number_per cent/100));
--
Rik Wasmus

[Jerry Stuckle]

One wrote:

hi group -

I had this in a function - so I've just moved this out of the function
for readabilty.

Can someone please tell me WHY does this not return the result of :
n1 times n2

As I said - I took it out of the function just for readability :
In my php file :

$number_percent ="25";
echo "history['order_total'] is ".$history['order_total']."<br />";
echo "number_per cent is ".$number_perce nt."<br />";
$total=(($histo ry['order_total'])*$number_perce nt);
echo "total is ".$total."< br />";

And here is the output in the browser :
history['order_total'] is $241.47
number_percent is 25
total is 0

WHY ? Any advice or pointers would be much appreciated!

$number_percent is a string containing 25, not the numeric value 25.
When you use a string in a calculation it's numeric value is zero.

Try
$number_percent =25;

instead (and ensure that $history['order_total'] is also numeric).
--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
js*******@attgl obal.net
=============== ===

[One]

Because '$241.47' is not a number, it's a string representation of a

currency. PHP doesn't know anything about that, 'currency' is not a type.
When performing math on it, PHP will try to make a number out of it, and
encounters '$' as the first character. This is not something it
recognizes, and it will default to 0. And 0 * 25 = 0.

You might want to remove the currency symbol from the string, and just add
it back when you have to echo/print the total.

Also, I'd think if $number_percent = 25, you might want $total =
$history['order_total'] * (1+($number_per cent/100));

Hi Rik - thank you the reply.

I used string replace to remove the dollar sign, then I simply
multiplied the two numbers, and it is still calculating as zero.
Can I cast this variable to an int ??

Input :
$number_percent ="25";
echo "history['order_total'] is ".$history['order_total']."<br />";
$removeit=str_r eplace('$' ,'', $history['order_total']);
echo "strip the $ sign ".$removeit."<b r />";
$total = ($removeit * (1+($number_per cent/100)));
echo "<br />total is ".$total."< br />";

Output :
history['order_total'] is $241.47
strip the $ sign 241.47
total is 0
:-(

[One]

On Feb 7, 11:34 am, Jerry Stuckle <jstuck...@attg lobal.netwrote:

$number_percent is a string containing 25, not the numeric value 25.
When you use a string in a calculation it's numeric value is zero.

Try
$number_percent =25;

instead (and ensure that $history['order_total'] is also numeric).

Hi Jerry - thanks much for trying.
Same result :
Input :
$number_percent =25;
echo "history['order_total'] is ".$history['order_total']."<br />";
$removeit=str_r eplace('$' ,'', $history['order_total']);
echo "strip the $ sign ".$removeit."<b r />";
$total = ($removeit * $number_percent );
echo "<br />total is ".$total."< br />";

Output :
history['order_total'] is $241.47
strip the $ sign 241.47
total is 0

This is bonkers - I'm *sure* I have done this type of thing in the
past without issue. :-(

[Rik]

One <da**********@g mail.comwrote:

On Feb 7, 11:34 am, Jerry Stuckle <jstuck...@attg lobal.netwrote:

>$number_percen t is a string containing 25, not the numeric value 25.
When you use a string in a calculation it's numeric value is zero.

Try
$number_percent =25;

instead (and ensure that $history['order_total'] is also numeric).

Hi Jerry - thanks much for trying.
Same result :
Input :
$number_percent =25;
echo "history['order_total'] is ".$history['order_total']."<br />";
$removeit=str_r eplace('$' ,'', $history['order_total']);
echo "strip the $ sign ".$removeit."<b r />";
$total = ($removeit * $number_percent );
echo "<br />total is ".$total."< br />";

Output :
history['order_total'] is $241.47
strip the $ sign 241.47
total is 0

This is bonkers - I'm *sure* I have done this type of thing in the
past without issue. :-(

This works here:
<?php
$history['order_total'] = '$241.47';
$number_percent ="25";//should be without the quotes indeed, but just to
show PHP can cast this correctly
echo "history['order_total'] is ".$history['order_total']."<br />";
$removeit=str_r eplace('$' ,'', $history['order_total']);
echo "strip the $ sign ".$removeit."<b r />";
$total = ($removeit * (1+($number_per cent/100)));
echo "<br />total is ".$total."< br />";
?>

So I'd say there's something wrong with the exact contents of
$history['order_total'] in your script.

What if you do this (a bit overkill):

$removeit = preg_replace('/[^0-9.]/','',$history['order_total']);

If this doesn't work, I'm very curious what the output of
floatval($histo ry['order_total'])(or floatval($remov eit)) is....
--
Rik Wasmus

[Jerry Stuckle]

One wrote:

On Feb 7, 11:34 am, Jerry Stuckle <jstuck...@attg lobal.netwrote:

>$number_percen t is a string containing 25, not the numeric value 25.
When you use a string in a calculation it's numeric value is zero.

Try
$number_percent =25;

instead (and ensure that $history['order_total'] is also numeric).

Hi Jerry - thanks much for trying.
Same result :
Input :
$number_percent =25;
echo "history['order_total'] is ".$history['order_total']."<br />";
$removeit=str_r eplace('$' ,'', $history['order_total']);
echo "strip the $ sign ".$removeit."<b r />";
$total = ($removeit * $number_percent );
echo "<br />total is ".$total."< br />";

Output :
history['order_total'] is $241.47
strip the $ sign 241.47
total is 0

This is bonkers - I'm *sure* I have done this type of thing in the
past without issue. :-(

Rik caught one and I caught the other (I missed the dollar sign).

Both are string in your setup. Use floatval() to convert your
$history['order_total'] to a floating point number.

--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
js*******@attgl obal.net
=============== ===

[Jerry Stuckle]

One wrote:

On Feb 7, 11:34 am, Jerry Stuckle <jstuck...@attg lobal.netwrote:

>$number_percen t is a string containing 25, not the numeric value 25.
When you use a string in a calculation it's numeric value is zero.

Try
$number_percent =25;

instead (and ensure that $history['order_total'] is also numeric).

Hi Jerry - thanks much for trying.
Same result :
Input :
$number_percent =25;
echo "history['order_total'] is ".$history['order_total']."<br />";
$removeit=str_r eplace('$' ,'', $history['order_total']);
echo "strip the $ sign ".$removeit."<b r />";
$total = ($removeit * $number_percent );
echo "<br />total is ".$total."< br />";

Output :
history['order_total'] is $241.47
strip the $ sign 241.47
total is 0

This is bonkers - I'm *sure* I have done this type of thing in the
past without issue. :-(

Better yet - store the data as a floating point value without the dollar
sign. Then insert the dollar sign when you're ready to print.

--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
js*******@attgl obal.net
=============== ===

[Rik]

Jerry Stuckle <js*******@attg lobal.netwrote:

Better yet - store the data as a floating point value without the dollar
sign. Then insert the dollar sign when you're ready to print.

Indeed, check money_format().
--
Rik Wasmus

[One]

On Feb 7, 1:00 pm, Jerry Stuckle <jstuck...@attg lobal.netwrote:

One wrote:

On Feb 7, 11:34 am, Jerry Stuckle <jstuck...@attg lobal.netwrote:

$number_percent is a string containing 25, not the numeric value 25.
When you use a string in a calculation it's numeric value is zero.

Try
$number_percent =25;

instead (and ensure that $history['order_total'] is also numeric).

Hi Jerry - thanks much for trying.
Same result :
Input :
$number_percent =25;
echo "history['order_total'] is ".$history['order_total']."<br />";
$removeit=str_r eplace('$' ,'', $history['order_total']);
echo "strip the $ sign ".$removeit."<b r />";
$total = ($removeit * $number_percent );
echo "<br />total is ".$total."< br />";

Output :
history['order_total'] is $241.47
strip the $ sign 241.47
total is 0

This is bonkers - I'm *sure* I have done this type of thing in the
past without issue. :-(

Rik caught one and I caught the other (I missed the dollar sign).

Both are string in your setup. Use floatval() to convert your
$history['order_total'] to a floating point number.

Hi guys - thanks SO much for your replies - it is still not working -
I'm using the floatval properly but it is returning a zero :

Input :
echo "history['order_total'] is ".$history['order_total']."<br />";
$removeit=str_r eplace('$' ,'', $history['order_total']);
echo $removeit;
$floatandremove = floatval($remov eit);
echo "<br />floatandremo ve is ".$floatandremo ve;
exit;

Output :
history['order_total'] is $241.47
241.47
floatandremove is 0

This is getting crazy!