Hey,
My old boss wrote an extensive work tracking system in php for
internal use. He left and the server he is running it on is very
outdated so I have been given the task of transfering it over to a new
server and the latest versions of php, mysql, and apache. That
information is probably not relevant to the question.
His system has some javascript forms. One of which is a drop down
menu that uses the onchange functionality. Here is the code:
echo "<FORM NAME=\"changeda y\" METHOD=\"post\"
ACTION=\"worken tries.php\">\n" ;
echo "<SELECT NAME=\"xselecte d_date\"
onchange=\"mySu bmit('changeday ')\";>\n";
for($i=0;$i<$pa st_days;$i++){ // loop through past X days
echo "<OPTION VALUE='".$dates[$i]."' "; // output option
if ($dates[$i] == $selected_date) {echo "selected"; } // hilight
currently selected
echo ">".$months[$i]."/".$days[$i]; // finish option
} // end of past months loop
echo "</SELECT>\n"; // end of pull down menu
echo "<input type=hidden name=xtech value='".$tech. "'>"; // keep
currently selected tech
echo "</form>\n"; // end of change month form
I realize this is messy code, that is why this has been so hard for me.
My problem is the following:
The selected value in the menu is set to $xselected_date . Then upon a
change the form is submited back to this same php file. At the
begginning of this php script the code then does:
if (isset($xselect ed_date)) {blah blah blah}
But this conditional is never evaluating true. Does the select name
variable not remain declared across the form submit? If not, is there
a way around this.
Thank you in advance for the help, if i need to provide any more
information please let me know.
-Eric
