1. let say my table in MySQL have a column call NUMBER. In this column it would be value 1,2,3. Now i want to make the 1,2,3 as option to user to choose.
what the code should be?
2. is it this code is right?
<Select NAME="field2">
<Option VALUE='NUMBER'> 1</Option>
<Option VALUE='NUMBER>2 </Option>
</Select>
12 2012
If you want to populate these fields from the database, you have to do that differently. But basically, the code you presented should be (for 3 numbers)
(the value= is passed to your form, the value between > and < is displayed to the user).
[HTML]
<Select NAME="field2">
<Option VALUE='1'>Numbe r 1</Option>
<Option VALUE='2'>Numbe r 2</Option>
<Option VALUE='3'>Numbe r 3</Option>
</Select>[/HTML]
Ronald :cool:
If you want to populate these fields from the database, you have to do that differently. But basically, the code you presented should be (for 3 numbers)
(the value= is passed to your form, the value between > and < is displayed to the user).
[HTML]
<Select NAME="field2">
<Option VALUE='1'>Numbe r 1</Option>
<Option VALUE='2'>Numbe r 2</Option>
<Option VALUE='3'>Numbe r 3</Option>
</Select>[/HTML]
Ronald :cool:
thank you for your reply. now i have another question is that i had generate the hyperlink as the code last time i get from this forum.
while($result = mysql_fetch_arr ay( $data ))
{
echo "<tr><td><a href='Informati onPage.php?id={ $result['ID']}'>{$result['ID']}</a></td>
<td>{$result['Name']}</td>
<td>{$result['Brand']}</td>
</tr>";
i want the user click to the ID and then it will go to another page and display the information corresponding to the ID. I am sucess to make the hyperlink.But i dont know the coding to display the information to user when user click to the ID hyperlink.Can u help me?Thank you
You lost me now. Does this last question have to do with:
1. usage of the select (drop-down) list as discussed in his thread, where you want a dynamic link in the drop down box?
2. another (previous) thread you posted and got an answer see how to generate hyperlink for entire number column of number ID ....
3. this is an entirely new question
Please reply.
Ronald :cool:
You lost me now. Does this last question have to do with:
1. usage of the select (drop-down) list as discussed in his thread, where you want a dynamic link in the drop down box?
2. another (previous) thread you posted and got an answer see how to generate hyperlink for entire number column of number ID ....
3. this is an entirely new question
Please reply.
Ronald :cool:
1.no.this does not do with the select list as discussess in this thread
2.this is about the queastion how to generate hyperlink for entire number of ID.
You already have a number of data fields in the table from which you can click. What fields do you want to display on the new page? And do you pass these values from the 'clickable link' ID page to the new page or do you want to pass the ID to the new page and read more data from the MySql database to display at the new page?
Ronald :cool:
the field i want to displa in new page is DateReceive, Quantity, Price, Status and Location. I wan to pass the ID to new page and read more data from MySql database to display at new page.
You already have a number of data fields in the table from which you can click. What fields do you want to display on the new page? And do you pass these values from the 'clickable link' ID page to the new page or do you want to pass the ID to the new page and read more data from the MySql database to display at the new page?
To speed up this discussion I will assume the latter. So your calling table was generated like this:
[php]echo "<tr><td><a href='AnotherPa ge.php?id={$res ult['ID']}'>{$result['ID']}</a></td>
<td>{$result['NamaPeralatan']}</td>
<td>{$result['Motor']}</td>
<td>{$result['Operasi']}</td>
</tr>";
[/php]
The AnotherPage.php looks like this:
[php]
<?php
// check if id is passed to this routine
if (isset($_GET['id']) {
// if yes: remove harmful tags and save the passed id in variable $id
$id = strip_tags($_GE T['id']);
// now you can do your MySql functions (sample)
// connect to server .....
// connect to data base .....
// construct SQL statement
$sql = "SELECT field1, field2, ... from table_name WHERE ID='$id'";
// execute the select
}
else { // id not passed to this function
echo "Id was not passed to this routine";
die;
}
[/php]
Ronald :cool:
You already have a number of data fields in the table from which you can click. What fields do you want to display on the new page? And do you pass these values from the 'clickable link' ID page to the new page or do you want to pass the ID to the new page and read more data from the MySql database to display at the new page?
To speed up this discussion I will assume the latter. So your calling table was generated like this:
[php]echo "<tr><td><a href='AnotherPa ge.php?id={$res ult['ID']}'>{$result['ID']}</a></td>
<td>{$result['NamaPeralatan']}</td>
<td>{$result['Motor']}</td>
<td>{$result['Operasi']}</td>
</tr>";
[/php]
The AnotherPage.php looks like this:
[php]
<?php
// check if id is passed to this routine
if (isset($_GET['id']) {
// if yes: remove harmful tags and save the passed id in variable $id
$id = strip_tags($_GE T['id']);
// now you can do your MySql functions (sample)
// connect to server .....
// connect to data base .....
// construct SQL statement
$sql = "SELECT field1, field2, ... from table_name WHERE ID='$id'";
// execute the select
}
else { // id not passed to this function
echo "Id was not passed to this routine";
die;
}
[/php]
Ronald :cool:
i had try following your step but still the parse error at line
$id = strip_tags($_GE T['id']);
the parse error mention that it was unexpected T_VARIABLE .
i had try following your step but still the parse error at line
$id = strip_tags($_GE T['id']);
the parse error mention that it was unexpected T_VARIABLE .
i am very sorry Ronald. Juz now i make some mistaken in typing and causee error. Now i can can run it already . I think i cant success in my program without ur help. thank you very much .
i am very sorry Ronald. Juz now i make some mistaken in typing and causee error. Now i can can run it already . I think i cant success in my program without ur help. thank you very much .
After following your instruction i had sucess reach what i want to create. now i have another new question is that if i have display a table , how can i create an edit button to edit the content in the table ? Let say below was my table .
$information=my sql_fetch_array ($sql);
echo "<table border='1'>";
echo "<tr><td Name</th><td >Brand</th></tr>";
echo"<tr><td>{$ information1['Name']}</td>
<td>{$informati on1['Brand']}</td>;
echo "</table>";
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