html within php works, but php within html doesnt

[mantrid]

Below are two different ways of writing the same script. The top one works
but the bottom one displays nothing in the list. Can anyone see why?

<?php
echo "<select name='subcat' style='WIDTH: 95%'><option value=''>Select
one</option>";
while($noticia = mysql_fetch_arr ay($quer)) {
echo "<option value='$noticia[TopicID]'>$noticia[Topic]</option>";
}
echo "</select>";
?>

<select name="subcat" style="WIDTH: 95%">
<option value="">Select one</option>
<?php while($noticia = mysql_fetch_arr ay($quer)) { ?>
<option value="<?php $noticia[TopicID]; ?>"><?php $noticia[Topic];
?></option>
<?php } ?>
</select>

Ian

[Andy Hassall]

On Sat, 02 Sep 2006 13:19:38 GMT, "mantrid" <ia********@vir gin.netwrote:

><option value="<?php $noticia[TopicID]; ?>"><?php $noticia[Topic];
?></option>

You haven't done anything in those PHP blocks; you need "print" or "echo".

--
Andy Hassall :: an**@andyh.co.u k :: http://www.andyh.co.uk
http://www.andyhsoftware.co.uk/space :: disk and FTP usage analysis tool

[mantrid]

DOOH!
Knew it was somethin simple
Cheers

"Andy Hassall" <an**@andyh.co. ukwrote in message
news:gh******** *************** *********@4ax.c om...

On Sat, 02 Sep 2006 13:19:38 GMT, "mantrid" <ia********@vir gin.netwrote:

<option value="<?php $noticia[TopicID]; ?>"><?php $noticia[Topic];
?></option>

You haven't done anything in those PHP blocks; you need "print" or

"echo".

>
--
Andy Hassall :: an**@andyh.co.u k :: http://www.andyh.co.uk
http://www.andyhsoftware.co.uk/space :: disk and FTP usage analysis tool

[Paul]

mantrid wrote:

Below are two different ways of writing the same script. The top one works
but the bottom one displays nothing in the list. Can anyone see why?

<?php
echo "<select name='subcat' style='WIDTH: 95%'><option value=''>Select
one</option>";
while($noticia = mysql_fetch_arr ay($quer)) {
echo "<option value='$noticia[TopicID]'>$noticia[Topic]</option>";
}
echo "</select>";
?>

<select name="subcat" style="WIDTH: 95%">
<option value="">Select one</option>
<?php while($noticia = mysql_fetch_arr ay($quer)) { ?>
<option value="<?php $noticia[TopicID]; ?>"><?php $noticia[Topic];
?></option>
<?php } ?>
</select>

Ian

Because you're not actually doing anything with that code. HTML isn't a
templating language, you can't just plug values in surrounded by php
tags. you have to actually *do* something with the values. Replace the
4th line with this:

<option value="<?php echo $noticia[TopicID]; ?>"><?php echo
$noticia[Topic]; ?></option>

Cheers,
Paul

[Phil]

mantrid wrote, On 3/09/06 1.19 a:

echo "<option value='$noticia[TopicID]'>$noticia[Topic]</option>";

The problem is in the way that you reference the $noticia array. In your
first example, you a double-quoted string, this causes PHP to
automatically grab the value from the array, but in your second example...

<option value="<?php $noticia[TopicID]; ?>"><?php $noticia[Topic];

You don't. You'll need to give it the key of the array as a string, like
$noticia['TopicID']

When using double-quoted strings, something like "$array[key]" will grab
the variable $array['key'], unless you use curly-braces like
"{$array['key']}".

See:
<http://nz.php.net/manual/en/language.types. string.php#lang uage.types.stri ng.parsing.simp le>

-Phil