anyone know how to set up a 'speed bump'.
once someone clicks on an external link on my website, I want a page to come
up that says you are leaving my site, with an OK button. once the OK button
is clicked I want to go to the original link that was clicked on.
any ideas.
17  2497 
<sl****@charter .net> wrote in message
news:44******** **************@ news.astraweb.c om... anyone know how to set up a 'speed bump'.
once someone clicks on an external link on my website, I want a page to
come up that says you are leaving my site, with an OK button. once the OK
button is clicked I want to go to the original link that was clicked on.
any ideas.
It feels like my eyes being removed by chopsticks. sl****@charter. net wrote: anyone know how to set up a 'speed bump'.
once someone clicks on an external link on my website, I want a page to come
up that says you are leaving my site, with an OK button. once the OK button
is clicked I want to go to the original link that was clicked on.
any ideas.
Can't do it. The external link will go to the other server. Your server won't
even know it happened.
And you should ask in alt.html. This isn't a PHP question (since PHP is
server-side only).
--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp. js*******@attgl obal.net
=============== ===
This isn't PHP, but you'd probably want to use JavaScript.
Try something like this (attributes removed for readability):
<html>
<head>
<script>
function speedBump(){
/*---------Code to delay exit--------*/
}
</script>
</head>
<body onunload="speed Bump()">
</body>
</html>
sl****@charter. net wrote: anyone know how to set up a 'speed bump'.
once someone clicks on an external link on my website, I want a page to come
up that says you are leaving my site, with an OK button. once the OK button
is clicked I want to go to the original link that was clicked on.
You're trying to slow down the people who are "leaving" by
second-guessing them? (Metaphors are fun but can mislead: I can
follow an external link without "leaving" your page.) In a world where
people are always in a rush, standing in their way could well earn you
a punch in the nose!
any ideas.
Pub?
--
Jock
I think a better option would to use framing, have your own top frame saying
it aint your website, and maybe a link to go back to your website. An
option?
<sl****@charter .net> wrote in message
news:44******** **************@ news.astraweb.c om... anyone know how to set up a 'speed bump'.
once someone clicks on an external link on my website, I want a page to
come
up that says you are leaving my site, with an OK button. once the OK
button
is clicked I want to go to the original link that was clicked on.
any ideas.
Carved in mystic runes upon the very living rock, the last words of
<sl****@charter .net> of comp.lang.php make plain: anyone know how to set up a 'speed bump'.
once someone clicks on an external link on my website, I want a page
to come up that says you are leaving my site, with an OK button. once
the OK button is clicked I want to go to the original link that was
clicked on.
any ideas.
Yep -- don't do it. It can be done quite easily with PHP, but if I were
on your site and ran into your "speed bump", I doubt I'd be back. If I
clicked the link in the first place, that's where I want to go. Making me
click again is only going to be annoying.
--
Alan Little
Phorm PHP Form Processor http://www.phorm.com/
Carved in mystic runes upon the very living rock, the last words of Alan
Little of comp.lang.php make plain: Carved in mystic runes upon the very living rock, the last words of
<sl****@charter .net> of comp.lang.php make plain:
anyone know how to set up a 'speed bump'.
once someone clicks on an external link on my website, I want a page
to come up that says you are leaving my site, with an OK button.
once the OK button is clicked I want to go to the original link that
was clicked on.
any ideas.
Yep -- don't do it. It can be done quite easily with PHP, but if I
were on your site and ran into your "speed bump", I doubt I'd be back.
If I clicked the link in the first place, that's where I want to go.
Making me click again is only going to be annoying.
Actually, upon further consideration, I can think of a situation where it
might be valid, if you want to make it clear that the visitor is leaving
your site, and you have no connection with the site they're going to. For
example, if you were writing an article on hate groups, and wanted to
link to some of their sites.
So, just write a script that takes a URL in the query string, display
your warning, and output the URL in a link. Then link to that in your
article or whatever.
But if it's just for, "Aww, shucks -- are you sure you want to leave my
excellent site????" -- don't do it. You will be regarded with contempt by
your visitors.
--
Alan Little
Phorm PHP Form Processor http://www.phorm.com/
Alan Little wrote: Carved in mystic runes upon the very living rock, the last words of
Alan Little of comp.lang.php make plain:
Carved in mystic runes upon the very living rock, the last words of
<sl****@charter .net> of comp.lang.php make plain:
anyone know how to set up a 'speed bump'.
once someone clicks on an external link on my website, I want a page
to come up that says you are leaving my site, with an OK button.
once the OK button is clicked I want to go to the original link that
was clicked on.
any ideas.
Yep -- don't do it. It can be done quite easily with PHP, but if I
were on your site and ran into your "speed bump", I doubt I'd be
back. If I clicked the link in the first place, that's where I want
to go. Making me click again is only going to be annoying.
Actually, upon further consideration, I can think of a situation
where it might be valid, if you want to make it clear that the
visitor is leaving your site, and you have no connection with the
site they're going to. For example, if you were writing an article on
hate groups, and wanted to link to some of their sites.
Another valid reason would be a (more or less secure) "logged in" area, and
displaying a warning you're leaving that area.
It could be done in PHP, but it would mean converting all your links, which
is a hassle. A quick temporary solution would be to turn on outbut
buffering, and searsching replacing links with preg_replace(). It's not
something I'd choose as a permanent solution though, it's unneccesary extra
memory and processing compared to doing it correctly.
Grtz,
--
Rik Wasmus sl****@charter. net wrote: anyone know how to set up a 'speed bump'.
once someone clicks on an external link on my website, I want a page to come
up that says you are leaving my site, with an OK button. once the OK button
is clicked I want to go to the original link that was clicked on.
any ideas.
<a href="http://www.google.com/" onClick="alert( 'You are about to leave
this site.')">Go To Google</a>
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