Hi,
Wondered if there was a good one-liner for what I want to do in PHP 4.
I have an array, with an arbitrary number of elements. I'd like to
know if all the elements in the array are empty. If at least one
element is non-empty, then the entire condition is false.
$my_arr = array();
$my_arr[0] = "";
$my_arr[1] = "";
$all_empty = something($my_a rr); // should contain the value TRUE
$my_arr = array();
$my_arr[0] = "";
$my_arr[1] = " hi ";
$my_arr[2] = "";
$all_empty = something($my_a rr); // should contain the value FALSE
Any slick ways to find this out? - Dave 3 34887
Dave Mennenoh wrote: ...good one-liner...
This is what I came up with:
function isEmpty($array) { return (count(array_fi lter($array)) == 0) ? 1 : 0; }
returns 1 if all elements are "" otherwise it returns 0.
-- Dave - www.blurredistinction.com http://www.macromedia.com/support/fo...am_macromedia/
It really depends on what the OP means by "empty." The code above will
return 1 if the array only contains elements that evaluate to false.
Examples of things that evaluate to false: false, "", 0, null. So,
given the array (0, 0, 0) that function will return true.
If your definition of "empty" is really the empty string, you can make
a small change to Dave's function as such:
function isEmpty($array) {
$my_not_empty = create_function ('$v', 'return strlen($v) > 0;');
return (count(array_fi lter($array, $my_not_empty)) == 0) ? 1 : 0;
} la***********@z ipmail.com wrote: Hi,
Wondered if there was a good one-liner for what I want to do in PHP 4. I have an array, with an arbitrary number of elements. I'd like to know if all the elements in the array are empty. If at least one element is non-empty, then the entire condition is false.
function isEmpty($array = array()) {
foreach ($array as $element) {
if (!empty($elemen t)) {
return false;
}
}
return true;
}
Okay, maybe not quite one-liner, but it should do the trick.
Ofcourse, it does depend if you agree with "empty"'s definition of what
empty is.
/Marcin This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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