PHP function question

[Tony]

When writing a function that takes in a variable number of parameters and
processing it using func_get_args or a similar technique, I'm assuming that
one is only able to use the pass by value method of parameter passing. Can
someone confirm or deny this for me?

Below is a trivial example of what I'm talking about. I'm assuming the
function below does nothing useful.

<?php

function squares( )
{
$params=functio n_get_args();
$numparams= func_num_args() ;
for ($i=0;$i<$numpa rams;$i++)
$params[$i]*=$params[$i];
}

?>

[Pedro Graca]

["Followup-To:" header set to comp.lang.php.]
Tony wrote:

When writing a function that takes in a variable number of parameters and
processing it using func_get_args or a similar technique, I'm assuming that
one is only able to use the pass by value method of parameter passing. Can
someone confirm or deny this for me?
I think you're right.
Below is a trivial example of what I'm talking about. I'm assuming the
function below does nothing useful.

<?php

function squares( )
{
$params=functio n_get_args();
$numparams= func_num_args() ;
for ($i=0;$i<$numpa rams;$i++)
$params[$i]*=$params[$i];
}

?>

But you can use the $GLOBALS variable to pretend you're passing by
reference.

Here's a way

<?php
function squares() {
$parms = func_get_args() ;
$nparms = func_num_args() ;
$retval = array(); // return array

for ($i = 0; $i < $nparms; ++$i)
if ($parms[$i]{0} == '$')
$GLOBALS[substr($parms[$i], 1)] *=
$GLOBALS[substr($parms[$i], 1)];
else $retval[] = $parms[$i] * $parms[$i];
return $retval;
}

$a = 6; $b = 7; $c = 8;
$res = squares($a, "$b", '$c');

print_r($res);
echo $c;
?>
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