In a .Net application, given a C++ dll with methods called by a C# GUI
Assume (x&y) is FALS
the following code in the C++ dll, when called from the C# interface
bool theMethod(unsigned int x)
unsigned int y = 0x2
if (x&y) // FALSE
printf("True")
if (x&y
return true
els
return false
1. Does NOT print the text "True
2. Does return TRU
While the following code
theMethod(unsigned int x
unsigned int y = 0x2
if (x&y) // FALSE
printf("True")
if (x&y
printf("")
return true
els
printf("")
return false
1. Does NOT print the text "True
2. Does return FALS
Question
Why is this happening? 9 1362
Correction to the code fragment
Bothe versions of "theMethod" return "bool
bool theMethod(unsigned int x
...
----- Honus wrote: ----
In a .Net application, given a C++ dll with methods called by a C# GUI
Assume (x&y) is FALS
the following code in the C++ dll, when called from the C# interface
bool theMethod(unsigned int x)
unsigned int y = 0x2
if (x&y) // FALSE
printf("True")
if (x&y
return true
els
return false
1. Does NOT print the text "True
2. Does return TRU
While the following code
bool theMethod(unsigned int x
unsigned int y = 0x2
if (x&y) // FALSE
printf("True")
if (x&y
printf("")
return true
els
printf("")
return false
1. Does NOT print the text "True
2. Does return FALS
Question
Why is this happening?
Correction to the code fragment
Bothe versions of "theMethod" return "bool
bool theMethod(unsigned int x
...
----- Honus wrote: ----
In a .Net application, given a C++ dll with methods called by a C# GUI
Assume (x&y) is FALS
the following code in the C++ dll, when called from the C# interface
bool theMethod(unsigned int x)
unsigned int y = 0x2
if (x&y) // FALSE
printf("True")
if (x&y
return true
els
return false
1. Does NOT print the text "True
2. Does return TRU
While the following code
bool theMethod(unsigned int x
unsigned int y = 0x2
if (x&y) // FALSE
printf("True")
if (x&y
printf("")
return true
els
printf("")
return false
1. Does NOT print the text "True
2. Does return FALS
Question
Why is this happening?
> if (x&y)
Since I work in VB, I may not be best person to suggest this
but shouldn't there be two ampersands (&&)?
--
Pozdrav,
Josip Medved, MCSD http://www.jmedved.com
Josip Medved <jm*****@jmedved.com> wrote: if (x&y)
Since I work in VB, I may not be best person to suggest this but shouldn't there be two ampersands (&&)?
No - x&y does a bitwise AND operation.
--
Jon Skeet - <sk***@pobox.com> http://www.pobox.com/~skeet
If replying to the group, please do not mail me too
> > Since I work in VB, I may not be best person to suggest this but shouldn't there be two ampersands (&&)?
No - x&y does a bitwise AND operation.
true.
but from source code it seems to me that he is trying to perform
logical AND operation since he is checking for true and false.
--
Pozdrav,
Josip Medved, MCSD http://www.jmedved.com
Josip Medved <jm*****@jmedved.com> wrote: Since I work in VB, I may not be best person to suggest this but shouldn't there be two ampersands (&&)?
No - x&y does a bitwise AND operation.
true. but from source code it seems to me that he is trying to perform logical AND operation since he is checking for true and false.
In C/C++, any non-zero value is regarded as true. So basically,
if (x&y)
evaluates to true if both x and y are non-zero.
--
Jon Skeet - <sk***@pobox.com> http://www.pobox.com/~skeet
If replying to the group, please do not mail me too
Hi Jon
How about when x = 1 and y = 2? The bitwise AND of these is zero, so surely
the statement should evaluate to false.
Also, pre-empting a reply by the OP, I took it that his issue is the
apparent inconsistency of the result, not that it evaluates to one true or
false for given values of x and y.
Charles
"Jon Skeet [C# MVP]" <sk***@pobox.com> wrote in message
news:MP************************@msnews.microsoft.c om... Josip Medved <jm*****@jmedved.com> wrote: > Since I work in VB, I may not be best person to suggest this > but shouldn't there be two ampersands (&&)?
No - x&y does a bitwise AND operation.
true. but from source code it seems to me that he is trying to perform logical AND operation since he is checking for true and false.
In C/C++, any non-zero value is regarded as true. So basically,
if (x&y)
evaluates to true if both x and y are non-zero.
-- Jon Skeet - <sk***@pobox.com> http://www.pobox.com/~skeet If replying to the group, please do not mail me too
Charles Law <bl***@nowhere.com> wrote: How about when x = 1 and y = 2? The bitwise AND of these is zero, so surely the statement should evaluate to false.
Apologies - yes, indeed it should. I'm half asleep :)
Also, pre-empting a reply by the OP, I took it that his issue is the apparent inconsistency of the result, not that it evaluates to one true or false for given values of x and y.
Indeed.
--
Jon Skeet - <sk***@pobox.com> http://www.pobox.com/~skeet
If replying to the group, please do not mail me too
Howdy
For some reason, after my initial posting of this query, I was unable to see it (or any responses). In the code example cited, the values of the unsigned ints will always be either 1 or 0. So the test works by returning true if either value is set to 1. There is no condition where a value will be equal to 2
However, as noted, the basic issue I have is: Why is the return value (at least as interpreted by the calling, C# method), dependent upon a bogus printf statement, rather than what the statement actually evaluates to
No one seems to have an answer to that question, and quite frankly, it makes me quite skeptical of the entire development environment (not that it takes much to arouse my skepticism where Microsoft is concerned)
----- Jon Skeet [C# MVP] wrote: ----
Charles Law <bl***@nowhere.com> wrote How about when x = 1 and y = 2? The bitwise AND of these is zero, so surel the statement should evaluate to false
Apologies - yes, indeed it should. I'm half asleep :
Also, pre-empting a reply by the OP, I took it that his issue is th apparent inconsistency of the result, not that it evaluates to one true o false for given values of x and y
Indeed
--
Jon Skeet - <sk***@pobox.com http://www.pobox.com/~skee
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