Help with XSL to make HTML table

[Virginia Kirkendall]

Hi: I'm new with this & need help creating a XSL table that looks
like the following:
---------------------------------------------------------
| | | | | |
|Title |CrossCut |Institution |START |END |
| | | | | |
| | |PI | | |
| | | | | |
|Project| | | | |
|Summary| | | | |
---------------------------------------------------------

XML :

<Programs>
<Title>DETECTIN G AND BLOCKING</Title>
<CrossCut>BAS E</CrossCut>
<PI>John Jones</PI>
<Institution>IN STITUTE</Institution>
<Project_Summar y>build an effective</Project_Summary >
<Start>2004-09-15T00:00:00</Start>
<End>2006-09-14T00:00:00</End>
</Programs>
<Programs>
<Title>NETWORKS </Title>
<CrossCut>BAS E</CrossCut>
<PI>Mary QuiteContrary</PI>
<Institution>BO STON UNIVERSITY</Institution>
<Project_Summar y>This application describes an
important</Project_Summary >
<Start>2004-08-15T00:00:00</Start>
<End>2007-08-14T00:00:00</End>
</Programs>
<Programs>
<Title>NETWORKS </Title>
<CrossCut>BAS E</CrossCut>
<PI>Harry Pit</PI>
<Institution>Un iversity</Institution>
<Project_Summar y>This application describes an
important</Project_Summary >
<Start>2004-08-15T00:00:00</Start>
<End>2007-08-14T00:00:00</End>
</Programs>
The desired effect will be to sorta group by Title (see that two
titles are same) with subsequent details spanning the row.

Thanks very much for any help I could really use it-- Ginger

[William Park]

Virginia Kirkendall <vk*********@ho tmail.com> wrote:

Hi: I'm new with this & need help creating a XSL table that looks
like the following:
---------------------------------------------------------
| | | | | |
|Title |CrossCut |Institution |START |END |
| | | | | |
| | |PI | | |
| | | | | |
|Project| | | | |
|Summary| | | | |
---------------------------------------------------------

XML :

<Programs>
<Title>DETECTIN G AND BLOCKING</Title>
<CrossCut>BAS E</CrossCut>
<PI>John Jones</PI>
<Institution>IN STITUTE</Institution>
<Project_Summar y>build an effective</Project_Summary >
<Start>2004-09-15T00:00:00</Start>
<End>2006-09-14T00:00:00</End>
</Programs>
<Programs>
<Title>NETWORKS </Title>
<CrossCut>BAS E</CrossCut>
<PI>Mary QuiteContrary</PI>
<Institution>BO STON UNIVERSITY</Institution>
<Project_Summar y>This application describes an
important</Project_Summary >
<Start>2004-08-15T00:00:00</Start>
<End>2007-08-14T00:00:00</End>
</Programs>
<Programs>
<Title>NETWORKS </Title>
<CrossCut>BAS E</CrossCut>
<PI>Harry Pit</PI>
<Institution>Un iversity</Institution>
<Project_Summar y>This application describes an
important</Project_Summary >
<Start>2004-08-15T00:00:00</Start>
<End>2007-08-14T00:00:00</End>
</Programs>
The desired effect will be to sorta group by Title (see that two
titles are same) with subsequent details spanning the row.

Thanks very much for any help I could really use it-- Ginger

Get a patched Bash shell with Expat XML parser interface,
http://freshmeat.net/projects/bashdiff/
help xml
help basp

First, parsing of your XML text would go something like

start () {
if [[ ${XML_ELEMENT_S TACK[1]} == Programs ]]; then
unset Title Crosscut Pi Institution Project_Summary Start End
fi
}
data () {
case ${XML_ELEMENT_S TACK[1]} in
Title|CrossCut| PI|Institution| Project_Summary |Start|End)
strcat ${XML_ELEMENT_S TACK[1]} "$1" ;;
esac
}
end () {
if [[ ${XML_ELEMENT_S TACK[1]} == Programs ]]; then
cat <<+ EOF
Title={$Title}
CrossCut={$Cros sCut}
PI={$PI}
Institution={$I nstitution}
Project_Summary ={$Project_Summ ary}
Start={$Start}
End={$End}
EOF
fi
}
xml -s start -d data -e end "`< file.xml`"

You should get

Title={DETECTIN G AND BLOCKING}
CrossCut={BASE}
PI={John Jones}
Institution={IN STITUTE}
Project_Summary ={build an effective}
Start={2004-09-15T00:00:00}
End={2006-09-14T00:00:00}

for the first <Programs>... </Programs> section. Now, if you consider

cat <<+ EOF
...
EOF

as HTML template, with '...' replaced by your table template, then your
solution becomes self-evident. If you have HTML code in a file, then
you can use my BASP (Bash Server Pages) engine.

For that, your template would go something like

<table> ...
<td><% echo -n $Title %></td>
<td><% echo -n $CrossCut %></td>
...
</table>

and you would print it, like

basp "`< template.html`"

--
William Park <op**********@y ahoo.ca>
Open Geometry Consulting, Toronto, Canada

[William Park]

William Park <op**********@y ahoo.ca> wrote:

start () {
if [[ ${XML_ELEMENT_S TACK[1]} == Programs ]]; then
unset Title Crosscut Pi Institution Project_Summary Start End
Typo... should be 'CrossCut' and 'PI'.
fi
}
For that, your template would go something like

<table> ...
<td><% echo -n $Title %></td>
<td><% echo -n $CrossCut %></td>

You can use shortcut, ala ASP,
<td><%=$Title%> </td>
...

--
William Park <op**********@y ahoo.ca>
Open Geometry Consulting, Toronto, Canada

[Joris Gillis]

> The desired effect will be to sorta group by Title (see that two

titles are same) with subsequent details spanning the row.

Hi,

This is an XSLT solution to your problem ,or at least, what I understand
of it.

<?xml version="1.0" ?>
<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>

<xsl:key name="title" match="Title" use="."/>
<xsl:template match="/">
<html>
<head>
</head>
<body>
<table>
<xsl:for-each
select="//Title[generate-id(.)=generate-id(key('title', .))]">
<!-- Loop through all titles (no duplicates) -->
<xsl:sort select="current ()"/>
<tr>
<th>Title</th>
<th>Crosscut</th>
<th>PI</th>
<th>Institution </th>
<th>Project_Sum mary</th>
<th>Start</th>
<th>End</th>
</tr>
<xsl:apply-templates select="//Programs[Title= current() ]"/>
</xsl:for-each>
</table>
</body></html>
</xsl:template>

<xsl:template match="Programs ">
<tr>
<td><xsl:valu e-of select="Title"/></td>
<td><xsl:valu e-of select="CrossCu t"/></td>
<td><xsl:valu e-of select="PI"/></td>
<td><xsl:valu e-of select="Institu tion"/></td>
<td><xsl:valu e-of select="Project _Summary"/></td>
<td><xsl:valu e-of select="Start"/></td>
<td><xsl:valu e-of select="End"/></td>
</tr>
</xsl:template>

</xsl:stylesheet>

regards,

--
Joris Gillis (http://www.ticalc.org/cgi-bin/acct-v...i?userid=38041)
Ceterum censeo XML omnibus esse utendum

[Virginia Kirkendall]

Thanks so much for your reply. This is getting very close!
Unfortunately, it's not quite there. The row headers do not repeat
for each duplicate title, which is good, but the records do repeat.
I am trying to understand your code & which elements are trying to
group the records, but I am new to this & haven't quite figured it
out. Again, thanks very much for posting your code.

"Joris Gillis" <ro**@pandora.b e> wrote in message news:<op******* *******@news.pa ndora.be>...

The desired effect will be to sorta group by Title (see that two
titles are same) with subsequent details spanning the row.

Hi,

This is an XSLT solution to your problem ,or at least, what I understand
of it.

<?xml version="1.0" ?>
<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>

<xsl:key name="title" match="Title" use="."/>
<xsl:template match="/">
<html>
<head>
</head>
<body>
<table>
<xsl:for-each
select="//Title[generate-id(.)=generate-id(key('title', .))]">
<!-- Loop through all titles (no duplicates) -->
<xsl:sort select="current ()"/>
<tr>
<th>Title</th>
<th>Crosscut</th>
<th>PI</th>
<th>Institution </th>
<th>Project_Sum mary</th>
<th>Start</th>
<th>End</th>
</tr>
<xsl:apply-templates select="//Programs[Title= current() ]"/>
</xsl:for-each>
</table>
</body></html>
</xsl:template>

<xsl:template match="Programs ">
<tr>
<td><xsl:valu e-of select="Title"/></td>
<td><xsl:valu e-of select="CrossCu t"/></td>
<td><xsl:valu e-of select="PI"/></td>
<td><xsl:valu e-of select="Institu tion"/></td>
<td><xsl:valu e-of select="Project _Summary"/></td>
<td><xsl:valu e-of select="Start"/></td>
<td><xsl:valu e-of select="End"/></td>
</tr>
</xsl:template>

</xsl:stylesheet>

regards,

[Joris Gillis]

Hi,

Perhaps this could get you closer to your goal:

<xsl:key name="title" match="Title" use="."/>
<xsl:template match="/">
<html>
<head>
</head>
<body>
<table>
<xsl:for-each select="//Title[generate-id(.)=generate-id(key('title', .))]">
<!-- Loop through all titles (no duplicates) -->
<!-- sort on title -->
<xsl:sort select="current ()"/>
<!-- print table headers -->
<tr>
<th>Title</th>
<th>Crosscut</th>
<th>PI</th>
<th>Institution </th>
<th>Project_Sum mary</th>
<th>Start</th>
<th>End</th>
</tr>
<!-- evaluate all 'Programs' nodes that have a 'Title' child equal to the Title of this iteration of the for-each loop -->
<xsl:apply-templates select="//Programs[Title=current()]"/>
</xsl:for-each>
</table>
</body></html>
</xsl:template>

<xsl:template match="Programs ">
<!-- print a new table row and evaluate the children of the 'Programs' node -->
<tr>
<td><xsl:appl y-templates select="Title"/></td>
<td><xsl:appl y-templates select="CrossCu t"/></td>
<td><xsl:appl y-templates select="PI"/></td>
<td><xsl:appl y-templates select="Institu tion"/></td>
<td><xsl:appl y-templates select="Project _Summary"/></td>
<td><xsl:appl y-templates select="Start"/></td>
<td><xsl:appl y-templates select="End"/></td>
</tr>
</xsl:template>

<xsl:template match="*">
<!-- select the text value of a node unless it's a duplicate of a previous text value-->
<!-- in other words, only unique text values will be returned-->
<xsl:if test="generate-id(//*[.=current()][../Title = current()/../Title ])=generate-id(.)">
<xsl:value-of select="."/>
</xsl:if>
</xsl:template>

regards,
--
Joris Gillis (http://www.ticalc.org/cgi-bin/acct-v...i?userid=38041)
Ceterum censeo XML omnibus esse utendum

[Virginia Kirkendall]

Joris! Thank you. Thank you.

This is great & you've helped me to begin to understand. Many, many thanks,

Ginger