XML to XML newbee help

[Adam]

Hi, Me very confused. I have some XML that I want to convert to a more
basic XML. I have put an example of what I have and what I want, I
have used XSL to convert XML to HTML, but never this way.

The <item numberingtext=" 10.01.01 "> I want in the para tag I
think, but if it has to be it own tag, no worrys.

Any help would be fantastic

Example of what I have:
=============== ==========
<?xml version="1.0" encoding="UTF-8" ?>
<document xmlns:xlink="ht tp://www.w3.org/1999/xlink"
xmlns:html="htt p://www.w3.org/HTML/1998/html4" xml:lang="en"
style="widows: 0; orphans: 0; word-break-inside: normal;
\-ilx-endnote-position: sectionbottom; \-ilx-endnote-style-type:
lower-alpha; \-ilx-footnote-position: pagebottom;
\-ilx-footnote-numbering-policy: continuous;
\-ilx-endnote-numbering-policy: continuous; \-ilx-footnote-style-type:
decimal;\-ilx-block-border-mode: merge;">
<part style="page: pageStyle1;">
<par class="Ahead">D uis autem vel eum iriure dolor in hendrerit in
</par>
<par class="Bhead">v ulputate velit esse consequat</par>
<par class="Normal" style="font-size: 12.0pt;"></par>
<list style="margin-left: 18.0mm; list-style-type: decimal;
\-ilx-list-group: 4; \-ilx-marker-align: left; \-ilx-marker-format:
&quot;%0.%1.%0& quot;; \-ilx-marker-offset: -1020tw;
\-ilx-marker-follow: tab;">
<item numberingtext=" 10.01.01 ">
<par class="MainText " style="\-ilx-tab-stops: &quot;left blank
0tw&quot;;">Lor em ipsum dolor sit amet,
<link xlink:type="sim ple" xlink:show="rep lace"
xlink:actuate=" onRequest" xlink:href="htt p://www.apple.com">
<inline class="Hyperlin k">consectetuer </inline>
</link> adipiscing elit, sed diam nonummy nibh euismod
<inline class="referenc e">tincidunt </inline> ut laoreet dolore
magna aliquam erat volutpat Ut wisi eiim ad minim veniam, quis nostrud
exerci tation ullamcorper suscipit lobortis nisl ut aliquip ex ea
commodo consequat (B-1664-0010). Duis lobortis autem vel eum iriure
dolor in hendrerit in vulputate velit esse
<link xlink:type="sim ple" xlink:show="rep lace"
xlink:actuate=" onRequest" xlink:href="htt p://www.apple.com">
<inline class="Hyperlin k">molestie</inline>
</link> consequat, vel illum dolore eu feugiat nulla facilisis at
vero eros et accumsan et iusto odio dignissim qui blandit praesent
luptatum zzril delenit augue duis dolore te feugait nulla facilisi.
</par>
</item>
</list>
</part>
</document>


=============== ==========
This is what I want:
=============== ==========
<?xml version="1.0" encoding="UTF-8"?>
<root>
<Ahead>Duis autem vel eum iriure dolor in hendrerit in</Ahead>
<Bhead>vulputat e velit esse consequat</Bhead>
<para>10.01.0 1 Lorem ipsum dolor sit amet,
<link href="http://www.apple.com"> consectetuer</link> adipiscing
elit, sed diam nonummy nibh euismod
ut laoreet dolore magna aliquam erat volutpat Ut wisi eiim ad minim
veniam, quis nostrud exerci tation ullamcorper suscipit lobortis nisl
ut aliquip ex ea commodo consequat (B-1664-0010). Duis lobortis autem
vel eum iriure dolor in hendrerit in vulputate velit esse
<link href="http://www.apple.com"> consectetuer</link> consequat, vel
illum dolore eu feugiat nulla facilisis at vero eros et accumsan et
iusto odio dignissim qui blandit praesent luptatum zzril delenit augue
duis dolore te feugait nulla facilisi.
</para>
</root>

[Baldo]

Ehy, ma il 1 Jul 2004 02:29:49 -0700 (ad****@btopenw orld.com
(Adam)) ha detto:

Example of what I have:

please simplify your from-XML and to-XML and i'll help u.

--
baldo

[Adam]

Hi,

I want to convert the XML at the top using XSL to cleaner XML, to then
be used in other aplications.

Can this be done?.
Thanks

Baldo <[e-mail]> wrote in message news:<v6******* *************** **********@4ax. com>...

Ehy, ma il 1 Jul 2004 02:29:49 -0700 (ad****@btopenw orld.com
(Adam)) ha detto:

Example of what I have:

please simplify your from-XML and to-XML and i'll help u.

[Andy Dingley]

ad****@btopenwo rld.com (Adam) wrote in message news:<6e******* *************** ****@posting.go ogle.com>...

Hi, Me very confused. I have some XML that I want to convert to a more
basic XML. I have put an example of what I have and what I want,
Try this:

Notes:
- I'm ingnoring some whitespace issues that are rarely significant.
You'd need to supply a better spec before going there.

- I guess the text of the second link in your example was a typo.

- This is an impossible problem to solve, as a general case from one
example. I can make it work (quite easily) for that one case, but a
couple of examples don't _define_ a mapping (I had to guess at this,
and it's a 50:50 guess between whether to map <item> or <par
class="MainText "> as the output <para>).

As a reductio ad absurdum, I could simply have wrapped your output
example in a <xsl:template > element (literal text and all !) and
called that a valid solution to the stated question. You see the
problem ?
<?xml version="1.0" encoding="UTF-8"?>
<xsl:styleshe et
version="1.0" xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"
xmlns:xlink="ht tp://www.w3.org/1999/xlink"
exclude-result-prefixes="xlink "

<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="link" >
<link href="{@xlink:h ref}" ><xsl:value-of select=".//text()"
/></link>
</xsl:template>

<xsl:template match="par[@class='Normal']" />

<xsl:template
match="par[@class='MainTex t']" >
<para>
<xsl:value-of select="transla te (parent::item/@numberingtext,
' ', ' ')" />
<xsl:apply-templates select="* | text()" />
</para>
</xsl:template>
<xsl:template
match="par[@class and not (@class = 'Normal' or @class =
'MainText')]" >
<xsl:element name="{./@class}" ><xsl:value-of select="text()"
/></xsl:element>
</xsl:template>
<xsl:template match="document/part" >
<root>
<xsl:apply-templates select="*" />
</root>
</xsl:template>

</xsl:stylesheet>

[Adam]

Thank you very much, will give this a go, and let you know how I get on.

Again Thanks
Adam

[Adam]

Hi Andy

Thanks that's fantastic, works just the way I wanted it to do.
Adam