Hello,
I setting up my mysql-server and php on IIS6 and it works almost fine.
But I got the next error:
Warning: mysql_numrows() : supplied argument is not a valid MySQL result
resource in file.php on line 46.
But I'am sure that the code is good, because I have use the code very much.
Create a connection is working, mysql_query is working but
mysql_Numrows($ query) is not working:
$query = mysql_query("SE LECT * FROM users");
if (mysql_Numrows( $query)>0)
{
code!!!
}
I have seen this error before, but I can't remember the solution anymore.
I think(I now it almost sure) that it has to do with the installation of PHP
or MYSQL.
PHP-version 4.3.7(mysql is built-in)
MYSQL 4.0.20d
I hope that somebody can help me to fix this problem.
So I can go further with my website!
Willem
2  4239 
$query = mysql_query("SE LECT * FROM users") or die(mysql_error ());
Before calling the mysql_num_rows( ) function, make sure ur sql query has be
executed correctly. if (mysql_num_rows ($query)>0)
{
code!!!
}
ccton
--
www.vicdir.com
"Willem Berendsen" <wi****@schoppe nsnieder.nl> дÈëÓʼþ
news:cc******** **@reader10.wxs .nl... Hello,
I setting up my mysql-server and php on IIS6 and it works almost fine.
But I got the next error:
Warning: mysql_numrows() : supplied argument is not a valid MySQL result
resource in file.php on line 46.
But I'am sure that the code is good, because I have use the code very
much. Create a connection is working, mysql_query is working but
mysql_Numrows($ query) is not working:
$query = mysql_query("SE LECT * FROM users");
if (mysql_Numrows( $query)>0)
{
code!!!
}
I have seen this error before, but I can't remember the solution anymore.
I think(I now it almost sure) that it has to do with the installation of
PHP or MYSQL.
PHP-version 4.3.7(mysql is built-in)
MYSQL 4.0.20d
I hope that somebody can help me to fix this problem.
So I can go further with my website!
Willem
Thanks!
I forgot to select the right database!
Now its working fine!
Willem
"CryingClin ton" <Cr***********@ hotmail.com> schreef in bericht
news:cc******** ***@mail.cn99.c om... $query = mysql_query("SE LECT * FROM users") or die(mysql_error ());
Before calling the mysql_num_rows( ) function, make sure ur sql query has
be executed correctly.
if (mysql_num_rows ($query)>0)
{
code!!!
}
ccton
--
www.vicdir.com
"Willem Berendsen" <wi****@schoppe nsnieder.nl> дÈëÓʼþ
news:cc******** **@reader10.wxs .nl... Hello,
I setting up my mysql-server and php on IIS6 and it works almost fine.
But I got the next error:
Warning: mysql_numrows() : supplied argument is not a valid MySQL result
resource in file.php on line 46.
But I'am sure that the code is good, because I have use the code very
much. Create a connection is working, mysql_query is working but
mysql_Numrows($ query) is not working:
$query = mysql_query("SE LECT * FROM users");
if (mysql_Numrows( $query)>0)
{
code!!!
}
I have seen this error before, but I can't remember the solution
anymore. I think(I now it almost sure) that it has to do with the installation of
PHP or MYSQL.
PHP-version 4.3.7(mysql is built-in)
MYSQL 4.0.20d
I hope that somebody can help me to fix this problem.
So I can go further with my website!
Willem
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