Integrated Query Question

cover

I have a table with 50 fields that receive input depending on whether
that input came in from a 'shaker' form or a 'conveyor' form. Input
from the 'conveyor' form might populate 25 fields while input from the
'shaker' form will populate another 20-25 fields but not the same
fields (however there are about 10 common fields to both). I'd
thought about using two tables (one for 'conveyor' and the other for
'shaker') but thought I'd try just the single table for now.

My query question: My pull down allows for selection of various areas
and also what type of equipment; i.e. 'shaker' or 'conveyor'. I have
the code started within a single query to cover the 'conveyor' 25
specific fields of data if the user selected 'conveyor' on their query
but what about if they'd selected 'shaker'? How do I write that
particular portion of code to return those different 20-25 fields?
Almost one for 'else if' but I don't know that this would work either.
Seems as though I'm looking for a conditional or compound query.

thanks,
Chris

The following code passes variable data from two pull downs on another
form (area and equiptype) to what I hope will be a single integrated
form below. Again, conveyor code example follows with needed shaker
code I'd like to integrate into a single query below that if that's
possible: Would something like what follows work?
---------------------------------------------------------------------

$DBhost = "localhost" ;
$DBuser = "dobey";
$DBpass = "#321@#2123 4";
$DBname = "equipment" ;
$table = "equipment_tbl" ;

$area = $_POST['area'];
$equiptype = $_POST['equiptype'];

mysql_connect($ DBhost, $DBuser, $DBpass) or die("Unable to connect to
host $DBhost");

mysql_select_db ($DBname) or die("Unable to select database $DBname");

$query =
"SELECT area, equiptype, equipname, motorsize, motorframe,
beltspec, beltspeed
FROM $table
WHERE 1 = 1 ";
if($area != "All") $query .= "and area = '".$area."'" ;
if($equiptype != "CONVEYOR") $query .= "and equiptype =
"'.$equiptype." '";
$result = mysql_query($qu ery);

$number = mysql_numrows($ result);

print "<h2>There are $number CONVEYOR records in the Equipment
Database:</h2>
<table cellpadding=5>
<tr bgcolor=black>
<td> area</td></td>
<td> equip type</td></td>
<td> equip name</td></td>
<td> motor size</td></td>
<td> motor frame</td></td>
<td> belt spec</td>
<td> belt speed</td></td>";
for($i=0; $i<$number; $i++) {
$area = mysql_result($r esult,$i,"area" );
$equiptype = mysql_result($r esult,$i,"equip type");
$equipname = mysql_result($r esult,$i,"equip name");
$motorsize = mysql_result($r esult,$i,"motor size");
$motorframe = mysql_result($r esult,$i,"motor frame");
$beltspec = mysql_result($r esult,$i,"belts pec");
$beltspeed = mysql_result($r esult,$i,"belts peed");
/* print even-numbered rows with a grey background,
odd-numbered with a white background */
if ($i%2 == 0) {
print "<tr bgcolor=lightgr ey>";
} else {
print "<tr>";
}
print "<td>$area</td>
<td>$equiptyp e</td>
<td>$equipnam e</td>
<td>$motorsiz e</td>
<td>$motorframe </td>
<td>$beltspec </td>
<td>$beltspee d</td>";
}
print "</table>";

// OTHERWISE IF SHAKER HAS BEEN SELECTED:

$query =
"SELECT area, equiptype, equipname, motorsize, motorframe,
shakerstroke, shaker_rpm
FROM $table
WHERE 1 = 1 ";
if($area != "All") $query .= "and area = '".$area."'" ;
if($equiptype != "SHAKER") $query .= "and equiptype =
"'.$equiptype." '";
$result = mysql_query($qu ery);

$number = mysql_numrows($ result);

print "<h2>There are $number SHAKER records in the Equipment
Database:</h2>
<table cellpadding=5>
<tr bgcolor=black>
<td> area</td></td>
<td> equip type</td></td>
<td> equip name</td></td>
<td> motor size</td></td>
<td> motor frame</td></td>
<td> shaker stroke</td>
<td> shaker RPM</td></td>";
for($i=0; $i<$number; $i++) {
$area = mysql_result($r esult,$i,"area" );
$equiptype = mysql_result($r esult,$i,"equip type");
$equipname = mysql_result($r esult,$i,"equip name");
$motorsize = mysql_result($r esult,$i,"motor size");
$motorframe = mysql_result($r esult,$i,"motor frame");
$shakerstroke = mysql_result($r esult,$i,"shake rstroke");
$shaker_rpm = mysql_result($r esult,$i,"shake r_rpm");
/* print even-numbered rows with a grey background,
odd-numbered with a white background */
if ($i%2 == 0) {
print "<tr bgcolor=lightgr ey>";
} else {
print "<tr>";
}
print "<td>$area</td>
<td>$equiptyp e</td>
<td>$equipnam e</td>
<td>$motorsiz e</td>
<td>$motorframe </td>
<td>$shakerstro ke</td>
<td>$shaker_rpm </td>";
}
print "</table>";

// Close the database connection
mysql_close();
?>

Dec 31 '05 #1

Subscribe Reply

1962

Lüpher Cypher

If I understand correctly, you may have either 'conveyor' or 'shaker'
passed to the script, and depending on that value different columns
should be shown. If that's the case, I'd rather do it like this:

# Common to all queries fields

$commonFields = array("area" => "Area",
"equiptype" => "Equip Type",
"equipname" => "Equip Name",
"motorsize" => "Motor Size",
"motorframe " => "Motor Frame");

# Fields depending on a variable

$varFields = array("CONVEYOR " => array("beltspec " => "Belt Spec",
"beltspeed" => "Belt Speed"),
"SHAKER" => array("shakerst roke" => "Shaker Stroke",
"shaker_rpm " => "Shaker RPM"));

# Get vars

$area = $_POST["area"];
$equiptype = $_POST["equiptype"];

# Build query fields
# This will return an associative array of all fields needed

$queryFields = array_merge($co mmonFields,$var Fields[$equiptype]);

# This will set $fields to "field,field,fi eld,..."

$fields = implode(",",arr ay_keys($queryF ields));

# Build full query

$query = "SELECT $fields FROM $table ".
"WHERE 1=1 AND equiptype='$equ iptype'".
($area != "All" ? " AND area='$area'" : "");
$result = mysql_query($qu ery);

# Output table
echo "<table ...>";
# Header
echo "<tr>";
foreach ($queryFields as $field=>$title) {
echo "<th>$title </th>";
}
echo "</tr>";
# Rows
while ($row = mysql_fetch_ass oc($result)) {
foreach ($queryFields as $field=>$title) {
echo "<td>{$row[$field]}</td>";
}
}
echo "</table ...>";
In case you get more equipment types, you can simply update $varFields
array and leave everything else unchanged - it'll still work :)
The idea is that since you have common and uncommon fields, it's easier
to describe them separately. You can then "choose" which uncommon fields
you want retrieved and merge them with common fields. Having that, you
can use loops to output a table. :)

cover wrote:

I have a table with 50 fields that receive input depending on whether
that input came in from a 'shaker' form or a 'conveyor' form. Input
from the 'conveyor' form might populate 25 fields while input from the
'shaker' form will populate another 20-25 fields but not the same
fields (however there are about 10 common fields to both). I'd
thought about using two tables (one for 'conveyor' and the other for
'shaker') but thought I'd try just the single table for now.

My query question: My pull down allows for selection of various areas
and also what type of equipment; i.e. 'shaker' or 'conveyor'. I have
the code started within a single query to cover the 'conveyor' 25
specific fields of data if the user selected 'conveyor' on their query
but what about if they'd selected 'shaker'? How do I write that
particular portion of code to return those different 20-25 fields?
Almost one for 'else if' but I don't know that this would work either.
Seems as though I'm looking for a conditional or compound query.

thanks,
Chris

The following code passes variable data from two pull downs on another
form (area and equiptype) to what I hope will be a single integrated
form below. Again, conveyor code example follows with needed shaker
code I'd like to integrate into a single query below that if that's
possible: Would something like what follows work?
---------------------------------------------------------------------

$DBhost = "localhost" ;
$DBuser = "dobey";
$DBpass = "#321@#2123 4";
$DBname = "equipment" ;
$table = "equipment_tbl" ;

$area = $_POST['area'];
$equiptype = $_POST['equiptype'];

mysql_connect($ DBhost, $DBuser, $DBpass) or die("Unable to connect to
host $DBhost");

mysql_select_db ($DBname) or die("Unable to select database $DBname");

$query =
"SELECT area, equiptype, equipname, motorsize, motorframe,
beltspec, beltspeed
FROM $table
WHERE 1 = 1 ";
if($area != "All") $query .= "and area = '".$area."'" ;
if($equiptype != "CONVEYOR") $query .= "and equiptype =
"'.$equiptype." '";
$result = mysql_query($qu ery);

$number = mysql_numrows($ result);

print "<h2>There are $number CONVEYOR records in the Equipment
Database:</h2>
<table cellpadding=5>
<tr bgcolor=black>
<td> area</td></td>
<td> equip type</td></td>
<td> equip name</td></td>
<td> motor size</td></td>
<td> motor frame</td></td>
<td> belt spec</td>
<td> belt speed</td></td>";
for($i=0; $i<$number; $i++) {
$area = mysql_result($r esult,$i,"area" );
$equiptype = mysql_result($r esult,$i,"equip type");
$equipname = mysql_result($r esult,$i,"equip name");
$motorsize = mysql_result($r esult,$i,"motor size");
$motorframe = mysql_result($r esult,$i,"motor frame");
$beltspec = mysql_result($r esult,$i,"belts pec");
$beltspeed = mysql_result($r esult,$i,"belts peed");
/* print even-numbered rows with a grey background,
odd-numbered with a white background */
if ($i%2 == 0) {
print "<tr bgcolor=lightgr ey>";
} else {
print "<tr>";
}
print "<td>$area</td>
<td>$equiptyp e</td>
<td>$equipnam e</td>
<td>$motorsiz e</td>
<td>$motorframe </td>
<td>$beltspec </td>
<td>$beltspee d</td>";
}
print "</table>";

// OTHERWISE IF SHAKER HAS BEEN SELECTED:

$query =
"SELECT area, equiptype, equipname, motorsize, motorframe,
shakerstroke, shaker_rpm
FROM $table
WHERE 1 = 1 ";
if($area != "All") $query .= "and area = '".$area."'" ;
if($equiptype != "SHAKER") $query .= "and equiptype =
"'.$equiptype." '";
$result = mysql_query($qu ery);

$number = mysql_numrows($ result);

print "<h2>There are $number SHAKER records in the Equipment
Database:</h2>
<table cellpadding=5>
<tr bgcolor=black>
<td> area</td></td>
<td> equip type</td></td>
<td> equip name</td></td>
<td> motor size</td></td>
<td> motor frame</td></td>
<td> shaker stroke</td>
<td> shaker RPM</td></td>";
for($i=0; $i<$number; $i++) {
$area = mysql_result($r esult,$i,"area" );
$equiptype = mysql_result($r esult,$i,"equip type");
$equipname = mysql_result($r esult,$i,"equip name");
$motorsize = mysql_result($r esult,$i,"motor size");
$motorframe = mysql_result($r esult,$i,"motor frame");
$shakerstroke = mysql_result($r esult,$i,"shake rstroke");
$shaker_rpm = mysql_result($r esult,$i,"shake r_rpm");
/* print even-numbered rows with a grey background,
odd-numbered with a white background */
if ($i%2 == 0) {
print "<tr bgcolor=lightgr ey>";
} else {
print "<tr>";
}
print "<td>$area</td>
<td>$equiptyp e</td>
<td>$equipnam e</td>
<td>$motorsiz e</td>
<td>$motorframe </td>
<td>$shakerstro ke</td>
<td>$shaker_rpm </td>";
}
print "</table>";

// Close the database connection
mysql_close();
?>

Dec 31 '05 #2

cover

On Sat, 31 Dec 2005 04:07:54 GMT, L?pher Cypher
<lu***********@ verizon.net> wrote:

If I understand correctly, you may have either 'conveyor' or 'shaker'
passed to the script, and depending on that value different columns
should be shown. If that's the case, I'd rather do it like this:

thanks very much - works great. :-)

Jan 2 '06 #3

Jim Michaels

if it's of any interest, you can get rid of the WHERE 1=1
it does nothing and is not needed.

"cover" <co************ ****@yahoo.com> wrote in message
news:0f******** *************** *********@4ax.c om...

$query =
"SELECT area, equiptype, equipname, motorsize, motorframe,
beltspec, beltspeed
FROM $table
WHERE 1 = 1 ";
$query =
"SELECT area, equiptype, equipname, motorsize, motorframe,
shakerstroke, shaker_rpm
FROM $table
WHERE 1 = 1 ";

Jan 3 '06 #4

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