I'd like to use regular expressions to remove extraneous Carriage Return
Line Feeds (CrLf) from a textarea before the form is submitted.
I'd like to remove all trailing CrLf's and convert all instances of 3
consectutive CrLf's to just 2.
I first escape() the textarea and match "%0D%0A" (i.e. CrLf).
Here's what I've been testing; watch for word-wrap:
<html>
<head>
<title>fix_crlf .htm</title>
<script type="text/javascript">
function fix() {
var form = document.forms[0];
var body = escape(form.Bod y.value);
// try to remove all trailing CrLf's
body = body.replace(/\%0D\%0A$/g,"");
// try to convert all 3 CrLf's to 2
body = body.replace(/\%0D\%0A\%0D\%0 A\%0D\%0A/g,"\%0D\%0A\%0D \%0A");
body = unescape(body);
// update the form field to see if it worked -- NOT!
form.Body.value = body;
}
</script>
</head>
<body>
<form>
<textarea name="Body" rows="30"></textarea>
<input type="button" value="fix()" onclick="fix()" >
</form>
</body>
</html>
I thought the "g" would handle multiple instances (of both cases) or do I
have to do a "for" loop?
Can anyone advise me? Thanks in advance.
Note: JavaScript will be enabled as this is for a browser-based application
that requires it.
5  16069 
McKirahan wrote: I'd like to use regular expressions to remove extraneous Carriage
Return Line Feeds (CrLf) from a textarea before the form is submitted.
I'd like to remove all trailing CrLf's and convert all instances of 3
consectutive CrLf's to just 2.
<snip />
strData = strData.replace (/(\r\n\s*){2,}/g, "\r\n\r\n") ;
The above finds 2 or more CrLfs with optional whitespace between them
and replaces it all with 2 CrLfs. If you're not bothered about the
chance of whitespace then:
strData = strData.replace (/(\r\n){3,}/g, "\r\n\r\n") ;
Note: JavaScript will be enabled as this is for a browser-based
application that requires it.
For robustness do it after the form is submitted, i.e. on the server
--
Andrew Urquhart
- FAQ: http://jibbering.com/faq
- Archive: http://groups.google.com/groups?grou...ang.javascript
- Reply: www.andrewu.co.uk/about/contact/
"Andrew Urquhart" <re***@website. in.sig> wrote in message
news:5nq2c.1680 $re1.1203@newsf e1-win... McKirahan wrote: I'd like to use regular expressions to remove extraneous Carriage
Return Line Feeds (CrLf) from a textarea before the form is submitted.
I'd like to remove all trailing CrLf's and convert all instances of 3
consectutive CrLf's to just 2.
<snip />
strData = strData.replace (/(\r\n\s*){2,}/g, "\r\n\r\n") ;
The above finds 2 or more CrLfs with optional whitespace between them
and replaces it all with 2 CrLfs. If you're not bothered about the
chance of whitespace then:
strData = strData.replace (/(\r\n){3,}/g, "\r\n\r\n") ;
Thank you very much for your reply.
But how would I remove all trailing (and leading) CrLf's?
Thanks again.
"McKirahan" <Ne**@McKirahan .com> wrote in message
news:juq2c.1917 09$uV3.791436@a ttbi_s51... "Andrew Urquhart" <re***@website. in.sig> wrote in message
news:5nq2c.1680 $re1.1203@newsf e1-win... McKirahan wrote: I'd like to use regular expressions to remove extraneous Carriage
Return Line Feeds (CrLf) from a textarea before the form is submitted.
I'd like to remove all trailing CrLf's and convert all instances of 3
consectutive CrLf's to just 2.
<snip />
strData = strData.replace (/(\r\n\s*){2,}/g, "\r\n\r\n") ;
The above finds 2 or more CrLfs with optional whitespace between them
and replaces it all with 2 CrLfs. If you're not bothered about the
chance of whitespace then:
strData = strData.replace (/(\r\n){3,}/g, "\r\n\r\n") ;
Thank you very much for your reply.
But how would I remove all trailing (and leading) CrLf's?
Thanks again.
Perhaps it would be?
strData = strData.replace (/^(\r\n\s*)/g, "");
strData = strData.replace (/(\r\n\s*)$/g, "");
"Andrew Urquhart" <re***@website. in.sig> wrote in message
news:U%q2c.2496 $54.1875@newsfe 1-win... McKirahan wrote: "McKirahan" <Ne**@McKirahan .com> wrote in message
news:juq2c.1917 09$uV3.791436@a ttbi_s51... But how would I remove all trailing (and leading) CrLf's?
Perhaps it would be?
strData = strData.replace (/^(\r\n\s*)/g, "");
strData = strData.replace (/(\r\n\s*)$/g, "");
strData = strData.replace (/^[\r\n]+|[\r\n]+$/g, "");
--
Andrew Urquhart
- FAQ: http://jibbering.com/faq
- Archive: http://groups.google.com/groups?grou...ang.javascript
- Reply: www.andrewu.co.uk/about/contact/
Thanks, Andrew.
I recently bought a copy of O'Reilly's "Mastering Regular Expressions" which
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