javascript - regular expression - foreign characters

[Smash]

i have this function:

------------------------------------------------------------
function isAlfaNumeric(v nos,space) {
if (space==false) {
validRegExp = /^[a-zA-Z0-9]{0,}$/;
}
else {
validRegExp = /^[a-zA-Z0-9\s]{0,}$/;
}
return vnos.search(val idRegExp)
}
-------------------------------------------------------------

the function is checking if the string "vnos" contains any non-alfanumeric
characters... it works fine except it returns true if the string contains
my country characters like ž,š.....i tried to do the following

validRegExp = /^[a-zA-Z0-9žš]{0,}$/; and also

validRegExp = /^[a-zA-Z0-9\ž\š]{0,}$/; but result was the same

Does anyone know how to check for foreign characters in string using regular
expression??

[Evertjan.]

Smash wrote on 20 jan 2004 in comp.lang.javas cript:

function isAlfaNumeric(v nos,space) {
if (space==false) {
validRegExp = /^[a-zA-Z0-9]{0,}$/;
}
else {
validRegExp = /^[a-zA-Z0-9\s]{0,}$/;
}
return vnos.search(val idRegExp)
}
-------------------------------------------------------------

the function is checking if the string "vnos" contains any
non-alfanumeric characters... it works fine except it returns true if
the string contains my country characters like z,s.....i tried to do
the following

validRegExp = /^[a-zA-Z0-9zs]{0,}$/; and also

validRegExp = /^[a-zA-Z0-9\z\s]{0,}$/; but result was the same

for {0,} use +
for 0-9 use \d
\s is all kinds of whitespace, like tabs etc.
use test, if you test for a string

try this:

<SCRIPT>
function isAlfaNumeric(s ,sp) {
r = /^[a-zA-Z\džš]+$/;
rs = /^[a-zA-Z\džš\s]+$/;
return (sp)? rs.test(s) : r.test(s);
};

alert(isAlfaNum eric("12astš",t rue));
alert(isAlfaNum eric("34astš",f alse));
alert(isAlfaNum eric("56as tš",true));
alert(isAlfaNum eric("78as tš",false));
</SCRIPT>

If you want to accept empty strings as true, use:

r = /^[a-zA-Z\džš]*$/;
rs = /^[a-zA-Z\džš\s]*$/;

this on works the other way around, accepts empty strings:

<SCRIPT>
function isAlfaNumeric(s ,sp) {
r = /[^a-zA-Z\džš]/;
rs = /[^a-zA-Z\džš\s]/;
return ! ((sp)? rs.test(s) : r.test(s));
};

alert(isAlfaNum eric("12astš",t rue));
alert(isAlfaNum eric("34astš",f alse));
alert(isAlfaNum eric("56as tš",true));
alert(isAlfaNum eric("78as tš",false));
</SCRIPT>

--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

[Lasse Reichstein Nielsen]

sm*****@email.s i (Smash) writes:

Does anyone know how to check for foreign characters in string using regular
expression??

I think the safest is to use the \w esacpe, which matches "word characters".
That includes letters, international included, digits and the underscore.
If you can live with that:

if (space==false) {
validRegExp = /^[\w]*$/;
}
else {
validRegExp = /^[\w\s]*$/;
}

/L
--
Lasse Reichstein Nielsen - lr*@hotpop.com
DHTML Death Colors: <URL:http://www.infimum.dk/HTML/rasterTriangleD OM.html>
'Faith without judgement merely degrades the spirit divine.'

[Dr John Stockton]

JRS: In article <72************ *************@p osting.google.c om>, seen
in news:comp.lang. javascript, Smash <sm*****@email. si> posted at Tue, 20
Jan 2004 00:37:31 :-

function isAlfaNumeric(v nos,space) {
if (space==false) {
if (!space) { // or if (space) and swap the rest

Does anyone know how to check for foreign characters in string using regular
expression??

"Foreign" does not mean "non-Anglo"; Americans & British are foreigners
too.

AIUI, a string can contain any Unicode character, and there are tens of
thousands of those, a large proportion of which are letters in some
language or other. Therefore, to test fully for letters outside A-Za-z,
one needs in some form or another either a list of *all* letters or a
list of *all* non-letters, or both.

I don't know Slovenian; but I guess that it has a relatively small
number of non-Anglo letters; those could be listed and tested for, but
that would not be entirely helpful to a Scandinavian visitor.

There *should* be a javascript function to test whether the current font
has a specific glyph for a given character, or for all those in a
string; but AFAIK there is not.

--
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[Evertjan.]

Dr John Stockton wrote on 20 jan 2004 in comp.lang.javas cript:

There *should* be a javascript function to test whether the current font
has a specific glyph for a given character, or for all those in a
string; but AFAIK there is not.

If we had a Regex syntax for a character above-a/below-a/in-a-range-of
certain char number(s), even without the knowledge of the specific font,
that would be nice.

regex.defineran ge('%3','>#80')
regex.defineran ge('%5','>#0',' <#20')

boolean = /aa\%5+bb[^\%3]?/.test(string)
--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

[Lasse Reichstein Nielsen]

"Evertjan." <ex************ **@interxnl.net > writes:

If we had a Regex syntax for a character above-a/below-a/in-a-range-of
certain char number(s), even without the knowledge of the specific font,
that would be nice.

regex.defineran ge('%3','>#80') regex.defineran ge('%5','>#0',' <#20')

boolean = /aa\%5+bb[^\%3]?/.test(string)

Try:
var boolean = /aa[\x01-\x1f]+bb[^\x81-\uffff]?/.test(string);
It says true for
var string = "aa\n\rbb\u1268 ";
(which is 7 characters long).

/L
--
Lasse Reichstein Nielsen - lr*@hotpop.com
DHTML Death Colors: <URL:http://www.infimum.dk/HTML/rasterTriangleD OM.html>
'Faith without judgement merely degrades the spirit divine.'

[Evertjan.]

Lasse Reichstein Nielsen wrote on 21 jan 2004 in comp.lang.javas cript:

Try:
var boolean = /aa[\x01-\x1f]+bb[^\x81-\uffff]?/.test(string);
It says true for
var string = "aa\n\rbb\u1268 ";
(which is 7 characters long).

[\x01-\x1f] etc

Nice, never thought of that !

--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

[Dr John Stockton]

JRS: In article <8y**********@h otpop.com>, seen in
news:comp.lang. javascript, Lasse Reichstein Nielsen <lr*@hotpop.com >
posted at Tue, 20 Jan 2004 22:47:33 :-

sm*****@email. si (Smash) writes:

Does anyone know how to check for foreign characters in string using regular
expression??

I think the safest is to use the \w esacpe, which matches "word characters".
That includes letters, international included, digits and the underscore.

In MSIE4, it does not match É (E-acute), ä (a-umlait), Å (A-ring); and,
I suppose, others.

A Netscape 1.3 reference page include(s|d) :
Matches any alphanumeric character including the underscore.
Equivalent to [A-Za-z0-9_].

It would be nice to be able to match *any* letter, including non-anglo;
but ISTM that \w is fundamentally matching the characters that normally
appear in identifiers, and there it would be very wrong for that to be
altered.

--
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[Lasse Reichstein Nielsen]

Dr John Stockton <sp**@merlyn.de mon.co.uk> writes:

In MSIE4, it does not match É (E-acute), ä (a-umlait), Å (A-ring); and,
I suppose, others.

Yes, that was me misremembering. Bummer. I would have been nice with
an escape that matches alphanumeric unicode characters, and not just
ASCII ones, and I though ECMAScript had it. That was apparently
just wishful thinking.

/L
--
Lasse Reichstein Nielsen - lr*@hotpop.com
DHTML Death Colors: <URL:http://www.infimum.dk/HTML/rasterTriangleD OM.html>
'Faith without judgement merely degrades the spirit divine.'

[Dr John Stockton]

JRS: In article <pt**********@h otpop.com>, seen in
news:comp.lang. javascript, Lasse Reichstein Nielsen <lr*@hotpop.com >
posted at Wed, 21 Jan 2004 18:24:12 :-

Try:
var boolean = /aa[\x01-\x1f]+bb[^\x81-\uffff]?/.test(string);
It says true for
var string = "aa\n\rbb\u1268 ";
(which is 7 characters long).

But for that approach to do the original job in full, one needs to read
the entire Unicode table and decide which squashed spiders are foreign
letters and which are foreign non-letters.

I've seen AJF's Unicode table in HTML; but I don't recall seeing one
written in ISO-7 and intended for simple machine-reading.

http://ppewww.ph.gla.ac.uk/~flavell/...e/unidata.html

--
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