checkboxes

[BjoernJackschina]

HEllo,
I still have always the same problem with a no object form in my
source code.
It is for checking out used radiobuttons or checkboxes.<scr ipt

<!--
function pruefen(){retur n true}
-->
</script>
<script language="JAvaS cript1.1"><!--
function pruefen(f){
var i;
var k=0;
document.forms[f].elements; /* this sould be an object form but I
can't find the syntax-mistake */

for(i=0; i < f.elem.length; i++){

if ('checkbox' == elem[i].type)
{
if(elem[i].checked)
k++;
}
}return true;
}
/* So actually I need k for continue. Maybe it has to give back k ? */

<form onSubmit="retur n pruefen(this)"> </form>

Thank you

[Vjekoslav Begovic]

"BjoernJackschi na" <ja*******@hotm ail.com> wrote in message
news:a2******** *************** ***@posting.goo gle.com...

HEllo,
I still have always the same problem with a no object form in my
source code.
It is for checking out used radiobuttons or checkboxes.<scr ipt

<!--
function pruefen(){retur n true}
-->
</script>
<script language="JAvaS cript1.1"><!--
language attribute is deprecated, type attribute is required
function pruefen(f){
var i;
var k=0;
document.forms[f].elements; /* this sould be an object form but I
can't find the syntax-mistake */
f is object allready since you have "onSubmit="retu rn pruefen(this)". And
"this" means this form. Use:

f.elements
<form onSubmit="retur n pruefen(this)"> </form>

[Michael Winter]

BjoernJackschin a wrote on 02 Dec 2003:

HEllo,
I still have always the same problem with a no object form in my
source code.
It is for checking out used radiobuttons or checkboxes.<scr ipt
My reply to your original contains more elaborate response. Please
read that after this.
<!--
function pruefen(){retur n true}
-->
</script>
<script language="JAvaS cript1.1"><!--
function pruefen(f){
var i;
var k=0;
document.forms[f].elements; /* this sould be an object form but
I can't find the syntax-mistake */
No, it should *not*!! When you use the this operator in an event
handler, it evaluates to an object reference of the element it is in.
For example:

<INPUT id="eg1" type="checkbox" onclick="someFu nction(this)">

someFunction() is passed a reference to an Input (in JS) or
HTMLInputElemen t (in DOM) object with the id, eg1.

<FORM id="eg2" ... onsubmit="someF unction(this)">

someFunction() is passed a reference to a Form (in JS) or
HTMLFormElement (in DOM) object with the id, eg2.

If you had a form, such as this one:

<FORM name="myForm" onsubmit="someF unction(this)">

....and this function:

function someFunction( obj ) {
// Here, obj would be the same as using document.forms['myForm']
}
for(i=0; i < f.elem.length; i++){

if ('checkbox' == elem[i].type)
{
if(elem[i].checked)
k++;
}
}return true;
}
/* So actually I need k for continue. Maybe it has to give back
k ? */
To answer that, you need to tell us (and I said this in my other
reply) what the validator is checking, what is a success condition,
and what is a failure condition. You said that you checked k - for
what? Where will you check it?
<form onSubmit="retur n pruefen(this)"> </form>

Don't forget to read my reply to your original post.

Mike

--
Michael Winter
M.******@blueyo nder.co.uk.invalid (remove ".invalid" to reply)

[BjoernJackschina]

"Vjekoslav Begovic" <vj*******@inet .hr> wrote in message news:<bq******* ***@ls219.htnet .hr>...

"BjoernJackschi na" <ja*******@hotm ail.com> wrote in message
news:a2******** *************** ***@posting.goo gle.com...

HEllo,
I still have always the same problem with a no object form in my
source code.
It is for checking out used radiobuttons or checkboxes.<scr ipt

<!--
function pruefen(){retur n true}
-->
</script>
<script language="JAvaS cript1.1"><!--

language attribute is deprecated, type attribute is required

function pruefen(f){
var i;
var k=0;
document.forms[f].elements; /* this sould be an object form but I
can't find the syntax-mistake */

f is object allready since you have "onSubmit="retu rn pruefen(this)". And
"this" means this form. Use:

f.elements

<form onSubmit="retur n pruefen(this)"> </form>

Hello,
if I use f.elements I have the problem with a part of the for-loop. So
it is to object to ( i=0;i < f.elements.leng th;i++).
What could be the problem. I couldn't find it.

Many thanks

[BjoernJackschina]

Michael Winter <M.******@bluey onder.co.uk.inv alid> wrote in message news:<Xn******* *************** *********@193.3 8.113.46>...

BjoernJackschin a wrote on 02 Dec 2003:

HEllo,
I still have always the same problem with a no object form in my
source code.
It is for checking out used radiobuttons or checkboxes.<scr ipt

My reply to your original contains more elaborate response. Please
read that after this.

<!--
function pruefen(){retur n true}
-->
</script>
<script language="JAvaS cript1.1"><!--
function pruefen(f){
var i;
var k=0;
document.forms[f].elements; /* this sould be an object form but
I can't find the syntax-mistake */

No, it should *not*!! When you use the this operator in an event
handler, it evaluates to an object reference of the element it is in.
For example:

<INPUT id="eg1" type="checkbox" onclick="someFu nction(this)">

someFunction() is passed a reference to an Input (in JS) or
HTMLInputElemen t (in DOM) object with the id, eg1.

<FORM id="eg2" ... onsubmit="someF unction(this)">

someFunction() is passed a reference to a Form (in JS) or
HTMLFormElement (in DOM) object with the id, eg2.

If you had a form, such as this one:

<FORM name="myForm" onsubmit="someF unction(this)">

...and this function:

function someFunction( obj ) {
// Here, obj would be the same as using document.forms['myForm']
}

for(i=0; i < f.elem.length; i++){

if ('checkbox' == elem[i].type)
{
if(elem[i].checked)
k++;
}
}return true;
}
/* So actually I need k for continue. Maybe it has to give back
k ? */

To answer that, you need to tell us (and I said this in my other
reply) what the validator is checking, what is a success condition,
and what is a failure condition. You said that you checked k - for
what? Where will you check it?

<form onSubmit="retur n pruefen(this)"> </form>

Don't forget to read my reply to your original post.

Mike

Hello Mike,
I will test your tipps but I can give you an answer only tomorrow.
Many thanks