Get multiple select values from query string?

[johkar]

This script works fine if all form fields have one value, but what do you do
if one of the form fields was a multiple select?

Example: status=blue&sta tus=red

function getParams() {
var index = document.URL.in dexOf('?');
var params = new Array();
if ( index != -1 ) {
var nameValuePairs
=document.URL.s ubstring(index+ 1,document.URL. length).split(' &');
for ( var i=0; i<nameValuePair s.length; i++ ) {
nameVal = nameValuePairs[i].split('=');
params[nameVal[0]] = nameVal[1];

}

} return params;
}

var mystat=unescape (params["status"]);

John

[Oz]

Instead of storing just the value, store the value as an Array. That way a
single param can have multiple values.

change:

for ( var i=0; i<nameValuePair s.length; i++ ) {
nameVal = nameValuePairs[i].split('=');
params[nameVal[0]] = nameVal[1];

}
To:

for ( var i=0; i<nameValuePair s.length; i++ ) {
nameVal = nameValuePairs[i].split('=');
if (params[nameVal[0]] == null) {//param doesn't exist so create a
new array
params[nameVal[0]] = [nameVal[1]];
}else{ //param already exists so add to the array
params[nameVal[0]].push(nameVal[1]);
}
}

"johkar" <no********@lin k.net> wrote in message
news:0e******** *********@newsr ead3.news.pas.e arthlink.net... This script works fine if all form fields have one value, but what do you do if one of the form fields was a multiple select?

Example: status=blue&sta tus=red

function getParams() {
var index = document.URL.in dexOf('?');
var params = new Array();
if ( index != -1 ) {
var nameValuePairs
=document.URL.s ubstring(index+ 1,document.URL. length).split(' &');
for ( var i=0; i<nameValuePair s.length; i++ ) {
nameVal = nameValuePairs[i].split('=');
params[nameVal[0]] = nameVal[1];

}

} return params;
}

var mystat=unescape (params["status"]);

John

[johkar]

Thanks for the reply. Where is the new array declared? What is push, and
what does it do? Support?

John

"Oz" <[e-mail] > wrote in message
news:kc******** ************@co mcast.com...

Instead of storing just the value, store the value as an Array. That way a
single param can have multiple values.

change:

for ( var i=0; i<nameValuePair s.length; i++ ) {
nameVal = nameValuePairs[i].split('=');
params[nameVal[0]] = nameVal[1];

}

To:

for ( var i=0; i<nameValuePair s.length; i++ ) {
nameVal = nameValuePairs[i].split('=');
if (params[nameVal[0]] == null) {//param doesn't exist so create a
new array
params[nameVal[0]] = [nameVal[1]];
}else{ //param already exists so add to the array
params[nameVal[0]].push(nameVal[1]);
}
}

snip

[Mike]

Arrays can be declared a couple of ways

var array = new Array();
or
var array = [ ]; //just short hand

So the first time the param is encountered a the value was stored in an
array in the following line

params[nameVal[0]] = [nameVal[1]]; this could also be written params[nameVal[0]] = new Array(nameVal[1]);
push is a method on Array objects that automatically adds a new entry to the
end of an array. so instead of increasing the number of
members in an array by using:

myArray[myArray.length] = new Object();

you can simply use:

myArray.push(ne w Object());

For complete documentation check out

http://devedge.netscape.com/library/...nce/array.html
http://devedge.netscape.com/library/.../contents.html


"johkar" <no********@lin k.net> wrote in message
news:jt******** ********@newsre ad4.news.pas.ea rthlink.net...

Thanks for the reply. Where is the new array declared? What is push, and
what does it do? Support?

John

"Oz" <[e-mail] > wrote in message
news:kc******** ************@co mcast.com...

Instead of storing just the value, store the value as an Array. That way

a single param can have multiple values.

change:

for ( var i=0; i<nameValuePair s.length; i++ ) {
nameVal = nameValuePairs[i].split('=');
params[nameVal[0]] = nameVal[1];

}

To:

for ( var i=0; i<nameValuePair s.length; i++ ) {
nameVal = nameValuePairs[i].split('=');
if (params[nameVal[0]] == null) {//param doesn't exist so create a new array
params[nameVal[0]] = [nameVal[1]];
}else{ //param already exists so add to the array
params[nameVal[0]].push(nameVal[1]);
}
}

snip

[johkar]

Thanks

[Thomas 'PointedEars' Lahn]

Mike wrote:

So the first time the param is encountered a the value was stored in an
array in the following line

> > params[nameVal[0]] = [nameVal[1]]; this could also be written > > params[nameVal[0]] = new Array(nameVal[1]);

Depends on the implementation of ECMAScript and the value of nameVal[1].
The Array constructor function also takes the number of array elements
as first argument in some implementations . So the Array literal is the
saner way here.

BTW Oz, johkar, Mike: You are top-posting, please read
http://www.netmeister.org/news/learn2quote.html and stop
that.
PointedEars