javasript problem - submiting

[Bartosz Wegrzyn]

Please look at my code.
I do validation of my form before I submit it.

I want to be able to to press one form button without running validating
script.
I just want to go directly to my php script.

I tried to do this
onclick="docume nt.form1.submit ()" but than the button value is not posted
and my php script is not working.

Also I tried to remove the onSubmit handler on my form and than I add this
to all my 3 buttons that will run with validation.
<input type="button" name="select" value="save" on click="return
check(this);doc ument.form1.sub mit()"It is not working I get error that Java
does not support that object or method.Also the value save is not
submitted.Is there any way to fix this

[Jeff Thies]

> Please look at my code.

I do validation of my form before I submit it.
Do this instead:

<form onsubmit="retur n checkForm()" ...>

Have checkForm return true if all is good and return false if there is
an error.

This will let you use a normal submit button and will let the form
work if javascript is disabled.

Jeff

I want to be able to to press one form button without running validating
script.
I just want to go directly to my php script.

I tried to do this
onclick="docume nt.form1.submit ()" but than the button value is not posted
and my php script is not working.

Also I tried to remove the onSubmit handler on my form and than I add this
to all my 3 buttons that will run with validation.

<input type="button" name="select" value="save" on click="return
check(this);doc ument.form1.sub mit()"It is not working I get error that Java
does not support that object or method.Also the value save is not
submitted.Is there any way to fix this

[Jeff Thies]

Jeff Thies wrote:

Please look at my code.
I do validation of my form before I submit it.
Do this instead:

<form onsubmit="retur n checkForm()" ...>

I've reread your post and I think I misunderstood what you wanted. I
think you want a submit button that bypasses the onsubmit validation

Try this

<form onsubmit="retur n checkForm()" ...>
<input type="submit" value="normal" >
<input type="submit" value="bypass" onclick="bypass ='1'">
var bypass;
function checkForm(){
if(bypass){retu rn true;}
....
normal form check code ...

Jeff


Have checkForm return true if all is good and return false if there is
an error.

This will let you use a normal submit button and will let the form
work if javascript is disabled.

Jeff

I want to be able to to press one form button without running validating
script.
I just want to go directly to my php script.

I tried to do this
onclick="docume nt.form1.submit ()" but than the button value is not posted
and my php script is not working.

Also I tried to remove the onSubmit handler on my form and than I add this
to all my 3 buttons that will run with validation.

<input type="button" name="select" value="save" on click="return
check(this);doc ument.form1.sub mit()"It is not working I get error that Java
does not support that object or method.Also the value save is not
submitted.Is there any way to fix this

[Bartosz Wegrzyn]

I like the idea,but I am having problems with passing the bypass value to
the script.

I have onclick="bypass ='1'"
and in my script I have

var bypass
if (bypass) {return true;}

my function...

shoutnot it be
if (bypass==1) {return true;}

Because this is not working.

Bart,


















"Jeff Thies" <cy*******@spri ntmail.com> wrote in message
news:3F******** *******@sprintm ail.com...

Jeff Thies wrote:

Please look at my code.
I do validation of my form before I submit it.

Do this instead:

<form onsubmit="retur n checkForm()" ...>

I've reread your post and I think I misunderstood what you wanted. I
think you want a submit button that bypasses the onsubmit validation

Try this

<form onsubmit="retur n checkForm()" ...>
<input type="submit" value="normal" >
<input type="submit" value="bypass" onclick="bypass ='1'">
var bypass;
function checkForm(){
if(bypass){retu rn true;}
...
normal form check code ...

Jeff

Have checkForm return true if all is good and return false if there is
an error.

This will let you use a normal submit button and will let the form
work if javascript is disabled.

Jeff

I want to be able to to press one form button without running validating script.
I just want to go directly to my php script.

I tried to do this
onclick="docume nt.form1.submit ()" but than the button value is not posted and my php script is not working.

Also I tried to remove the onSubmit handler on my form and than I add this to all my 3 buttons that will run with validation.

<input type="button" name="select" value="save" on click="return
check(this);doc ument.form1.sub mit()"It is not working I get error that Java does not support that object or method.Also the value save is not
submitted.Is there any way to fix this

[Jeff Thies]

Bartosz Wegrzyn wrote:

I like the idea,but I am having problems with passing the bypass value to
the script.

I have onclick="bypass ='1'"
and in my script I have

var bypass
if (bypass) {return true;}

my function...

shoutnot it be
if (bypass==1) {return true;}
Either way. 1 is true, 0 or undefined is false.

Here's my little test page:

<html>
<body>
<script type="text/javascript">
var bypass;
function checkForm(){
if(bypass){aler t('go');return true;}else{
alert('no go');return false;
}
}
</script>
<form onsubmit="retur n checkForm()" action="somewhe re.htm">
<input type="submit" value="normal" >
<input type="submit" value="bypass" onclick="bypass ='1'">
</form>
</body>
</html>

Jeff

Because this is not working.

Bart,

"Jeff Thies" <cy*******@spri ntmail.com> wrote in message
news:3F******** *******@sprintm ail.com...

Jeff Thies wrote:

> Please look at my code.
> I do validation of my form before I submit it.

Do this instead:

<form onsubmit="retur n checkForm()" ...>

I've reread your post and I think I misunderstood what you wanted. I
think you want a submit button that bypasses the onsubmit validation

Try this

<form onsubmit="retur n checkForm()" ...>
<input type="submit" value="normal" >
<input type="submit" value="bypass" onclick="bypass ='1'">
var bypass;
function checkForm(){
if(bypass){retu rn true;}
...
normal form check code ...

Jeff

Have checkForm return true if all is good and return false if there is
an error.

This will let you use a normal submit button and will let the form
work if javascript is disabled.

Jeff

>
> I want to be able to to press one form button without running validating > script.
> I just want to go directly to my php script.
>
> I tried to do this
> onclick="docume nt.form1.submit ()" but than the button value is not posted > and my php script is not working.
>
> Also I tried to remove the onSubmit handler on my form and than I add this > to all my 3 buttons that will run with validation.
>
> <input type="button" name="select" value="save" on click="return
> check(this);doc ument.form1.sub mit()"It is not working I get error that Java > does not support that object or method.Also the value save is not
> submitted.Is there any way to fix this

[Lasse Reichstein Nielsen]

"Bartosz Wegrzyn" <bl*******@lexo n.ws> writes:

I like the idea,but I am having problems with passing the bypass value to
the script.

I have onclick="bypass ='1'"
It really should be
onclick="bypass =true;"
No need to use the string '1' to represent true, when there is a perfectly
good boolean value.
and in my script I have var bypass
The "var bypass" should be outside the function, as a global variable.
You might want to initialize it:
var bypass = false;
It is not important, but it makes the code easier to read (you can see
that it holds a boolean that is initially false).
if (bypass) {return true;}
This should work. The condition of an if statement is converted to a
boolean, and a non-empty string ('1') is converted to true.
The values that are converted to false are
false, null, undefined, "" (empty string), 0, and NaN (not-a-number).
my function...

shoutnot it be
if (bypass==1) {return true;}
No. If you want to compare to the string, it should be
if (bypass == '1') {return true;}
It is just simpler to use
onclick="bypass = true;"
and then just test
if (bypass) {return true;}
Because this is not working.

If it still isn't workig, try inserting an
alert(bypass)
just before the if statement, and see what value it has.

/L
--
Lasse Reichstein Nielsen - lr*@hotpop.com
Art D'HTML: <URL:http://www.infimum.dk/HTML/randomArtSplit. html>
'Faith without judgement merely degrades the spirit divine.'

[Vjekoslav Begovic]

"Bartosz Wegrzyn" <bl*******@lexo n.ws> wrote in message
news:IG******** *************@n ewssrv26.news.p rodigy.com...

Please look at my code.
I do validation of my form before I submit it.

I want to be able to to press one form button without running validating
script.
I just want to go directly to my php script.

Try this:

<form method="get" action="whateve r.php" onsubmit="retur n checkForm()">
<input type="submit" value="normal" >
<input type="button" value="bypass" onclick="this.f orm.submit()">
</form>

Vjekoslav

[Bartosz Wegrzyn]

On Mon, 08 Sep 2003 11:10:48 +0200, Lasse Reichstein Nielsen wrote:

"Bartosz Wegrzyn" <bl*******@lexo n.ws> writes:

I like the idea,but I am having problems with passing the bypass value to
the script.

I have onclick="bypass ='1'"

It really should be
onclick="bypass =true;"
No need to use the string '1' to represent true, when there is a perfectly
good boolean value.

and in my script I have

var bypass

The "var bypass" should be outside the function, as a global variable.
You might want to initialize it:
var bypass = false;
It is not important, but it makes the code easier to read (you can see
that it holds a boolean that is initially false).

if (bypass) {return true;}

This should work. The condition of an if statement is converted to a
boolean, and a non-empty string ('1') is converted to true.
The values that are converted to false are
false, null, undefined, "" (empty string), 0, and NaN (not-a-number).

my function...

shoutnot it be
if (bypass==1) {return true;}

No. If you want to compare to the string, it should be
if (bypass == '1') {return true;}
It is just simpler to use
onclick="bypass = true;"
and then just test
if (bypass) {return true;}

Because this is not working.

If it still isn't workig, try inserting an
alert(bypass)
just before the if statement, and see what value it has.

/L

Thanks its working.

[Bartosz Wegrzyn]

On Mon, 08 Sep 2003 07:39:41 +0000, Jeff Thies wrote:

Bartosz Wegrzyn wrote:

I like the idea,but I am having problems with passing the bypass value to
the script.

I have onclick="bypass ='1'"
and in my script I have

var bypass
if (bypass) {return true;}

my function...

shoutnot it be
if (bypass==1) {return true;}

Either way. 1 is true, 0 or undefined is false.

Here's my little test page:

<html>
<body>
<script type="text/javascript">
var bypass;
function checkForm(){
if(bypass){aler t('go');return true;}else{
alert('no go');return false;
}
}
</script>
<form onsubmit="retur n checkForm()" action="somewhe re.htm">
<input type="submit" value="normal" >
<input type="submit" value="bypass" onclick="bypass ='1'">
</form>
</body>
</html>

Jeff

Because this is not working.

Bart,

"Jeff Thies" <cy*******@spri ntmail.com> wrote in message
news:3F******** *******@sprintm ail.com...

>
>
> Jeff Thies wrote:
> >
> > > Please look at my code.
> > > I do validation of my form before I submit it.
> >
> > Do this instead:
> >
> > <form onsubmit="retur n checkForm()" ...>
>
> I've reread your post and I think I misunderstood what you wanted. I
> think you want a submit button that bypasses the onsubmit validation
>
> Try this
>
> <form onsubmit="retur n checkForm()" ...>
> <input type="submit" value="normal" >
> <input type="submit" value="bypass" onclick="bypass ='1'">
>
>
> var bypass;
> function checkForm(){
> if(bypass){retu rn true;}
> ...
> normal form check code ...
>
> Jeff
>
>
> >
> > Have checkForm return true if all is good and return false if there is
> > an error.
> >
> > This will let you use a normal submit button and will let the form
> > work if javascript is disabled.
> >
> > Jeff
> >
> > >
> > > I want to be able to to press one form button without running

validating

> > > script.
> > > I just want to go directly to my php script.
> > >
> > > I tried to do this
> > > onclick="docume nt.form1.submit ()" but than the button value is not

posted

> > > and my php script is not working.
> > >
> > > Also I tried to remove the onSubmit handler on my form and than I add

this

> > > to all my 3 buttons that will run with validation.
> > >
> > > <input type="button" name="select" value="save" on click="return
> > > check(this);doc ument.form1.sub mit()"It is not working I get error that

Java

> > > does not support that object or method.Also the value save is not
> > > submitted.Is there any way to fix this

Thanks I put the bypass var inside the function.