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JavaScript Style.display not working

25 New Member
I cant get the style.display property to work properly. I have this test html page:
Expand|Select|Wrap|Line Numbers
  1. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
  2. <html xmlns="http://www.w3.org/1999/xhtml">
  3. <head>
  4.     <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
  5.     <title>Test Javascript</title>
  6.  
  7.     <script language="javascript" type="text/javascript">
  8.         window.onload = function () {
  9.             document.getElementById("button").onclick = function () {
  10.                 var text = document.getElementByName("username");
  11.                 var loader = document.getElementById("ajax_laoder");
  12.                 if (loader.style.display == "none") {
  13.                     text.style.display = "none";
  14.                     loader.style.display = "inline";
  15.                 } else {
  16.                     text.style.display = "inline";
  17.                     loader.style.display = "none";
  18.                 }
  19.             }
  20.         }
  21.     </script>
  22.  
  23. </head>
  24.  
  25. <body>
  26.  
  27. <input type="text" name="username" value="Username" class="loginfield" maxlength="60" /><br />
  28. <img src="images/ajax-loader.gif" alt="AJAX Loading" id="ajax_loader" style="display:none" /><br />
  29. <input type="submit" id="button" value="replace" title="Replace" />
Basically, this has a textbox and a hidden gif, and a button called replace. When I click replace, the javascript doesnt do anything.
Oct 2 '10 #1
2 1934
drhowarddrfine
7,435 Recognized Expert Expert
I believe it's getElementsByNa me with an 's' which means it will return an array and not just text.
Oct 2 '10 #2
dgourd
25 New Member
Wow. I completely looked that one over. Thanks a lot dude.
Oct 2 '10 #3

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