vw*******@gmail .com wrote:
Please look at the code below: (I am picking up JS from Crockfold and
a few other online sources too)
It would appear you picked up the bad examples.
*************** *************** *************** *************** ***
function Employee(name){
this.name = name || 'default';
}
function WorkerBee(name, dept){
this.base = Employee; //Not Employee();
this.base(name) ;
Another, less compatible possibility is
Employee.call(t his, name);
this.dept = dept;
}
var test1 = new WorkerBee('test 1', 'Input/Output');
Employee.protot ype.speciality = 'none';
((test1.special ity) ? test1.specialit y : 'undefined').wr iteln(); //
returns 'undefined'
WorkerBee.proto type = new Employee;
This inheritance pattern, which unfortunately originates from the first
versions of Netscape JavaScript References and has survived in numerous
tutorials to date (even the Wikipedia article), is essentially a wrong
one, meaning that it does not do what it is intended to do.
It does *not* insert the prototype object of `Employee'[1],
`Employee.proto type', in the prototype chain of `Workerbee' objects so that
`Workerbee' objects would inherit from `Employee.proto type':
A: (new WorkerBee) --WorkerBee.proto type --Employee.protot ype
Instead, it inserts a new `Employee' object in the prototype chain so that
`WorkerBee' objects inherit from that:
B: (new WorkerBee) --new Employee --Employee.protot ype
That little thing makes a big difference when the `Employee' constructor
adds properties to the object or modifies prototype properties, as here,
because the lookup algorithm finds the dynamically added properties of
*the same object* first.
Unless you need behavior B, use the following pattern to achieve A instead:
function inheritFrom(Con structor)
{
function Dummy() {}
Dummy.prototype = Constructor.pro totype;
return new Dummy();
}
WorkerBee.proto type = inheritFrom(Emp loyee);
The result is the following prototype chain:
A2: (new WorkerBee) --WorkerBee.proto type --(new Dummy)
--Employee.protot ype
Since `Dummy' objects have no properties of their own, they don't interfere
with the property lookup.
NOTE: This isn't exactly news around here.
((test1.special ity) ? test1.specialit y : 'undefined').wr iteln(); //
STILL returns 'undefined'
It's inefficient and harder to maintain to begin with. Consider this instead:
(test1.speciali ty || 'undefined').wr iteln();
But since when has a String object (that the primitive string value is being
converted to here) a writeln() method? Maybe you were looking for
document.writel n(test1.special ity || 'undefined');
BTW: Maybe I'm wrong, but I think the word should be "specialty" .
var test2 = new WorkerBee('test 2', 'Computer Science');
test2.specialit y.writeln(); //NOW this returns 'none'!
^^^^^^^^^^^^^^^ ^^^^^
If this really works chances are you are using some kind of framework that
augments the `String.prototy pe' object, so all bets are off until you post
the (*stripped-down*) code of that method. By default (per Specification)
String objects do not have or inherit a writeln() method.
*************** *************** *************** *************** *************** *************** *****
My questions are follows:
1) How does the base in WorkerBee works? When I call
var test1 = new WorkerBee('test 1', 'Input/Output');
base gets assigned to Employee (as a function) and 'test1' is passed
to Employee as a parameter which return the field "name : 'test1' '"
right?
No. In a constructor, `this' refers to the object that is being constructed
with it; not to the constructor itself. So the newly created `Employee'
object is augmented with a `base' property that is called afterwards.
So If I were to check for the presence of a parameter named Employee
in test1 I would not find anything
Correct aside from the use of the term "parameter" . You mean a *property*.
because what the function of
Employee merely did was pass this statement "name : 'test1' " to the
body of test1. Is this true?
No. Although this has been explained here ad nauseam before --
<http://jibbering.com/faq/#posting>
--, why not use a debugger to find it out for yourself?
<http://jibbering.com/faq/#debugging>
(I did check test1.hasOwnPro perty(Employee) and results = false);
Works as designed. `Employee' is a reference to a Function object.
Object.prototyp e.hasOwnPropert y() expects (of course) as *string value* to
contain the property *name*. If the argument was not of type string, it
would be converted to string. The string representation of `Employee' is
something along "function Employee(...) {\n ...\n}", and there is no
property with *that* name.
But even if you passed "Employee", the method would return `false', for the
reason explained above.
2) IF my understanding of prototype is true, then when I called
WorkerBee.proto type = new Employee;
this would like the function WorkerBee's prototype to an Employee
Object, and this Employee Object's prototype field is linked to
another anonymous object with the field 'speciality' = 'none'.
Roughly speaking that's correct. However, you need to use proper terms: In
ECMAScript implementations , objects have *properties*, not fields. Objects
are *being referred to* (with *references* that are values, and properties
to hold those values), not being linked.
If this were true, how come my second call to find out the speciality
of test1 STILL returned null?
Impossible to say. A `TypeError' exception should have been thrown
("test2.special ity.writeln is not a function"). Either your framework
has interfered, like
String.prototyp e.writeln = function() {
document.write( this);
};
or you don't post exactly the code that you are using, or you are not
testing nearly as thorough as you think.
HTH
PointedEars
___________
[1] For the sake of brevity I am referring to identifiers as objects, even
though they only represent references to objects of which there can be
more than one.
--
Prototype.js was written by people who don't know javascript for people
who don't know javascript. People who don't know javascript are not
the best source of advice on designing systems that use javascript.
-- Richard Cornford, cljs, <f8************ *******@news.de mon.co.uk>
