I understand that string.split() should produce an array from a
string. However when I use the following script the type of the result
is indeed an object but the array elements are undefined. Why?
var strTest = '1,2,3,4';
var aryTest = strTest.split() ;
alert(typeof aryTest + " " + aryTest[2]);
Thanks in advance. 5 1554
On Aug 13, 11:59 am, Steve wrote:
I understand that string.split() should produce an
array from a string. However when I use the
following script the type of the result is indeed
an object but the array elements are undefined. Why?
var strTest = '1,2,3,4';
var aryTest = strTest.split() ;
alert(typeof aryTest + " " + aryTest[2]);
If you do not provide the first ("Separator" ) argument to -
String.prototyp e.split - it will return a one element array with first
(zero index) element containing a string that is equivalent to the
original string. Thus - arryTest[2] - would be expected to result in
the undefined value as the - length - of - arrayTest - will be one and
its only existing 'array index' property is '0'.
var strTest = '1,2,3,4';
var aryTest = strTest.split() ;
alert(typeof aryTest + " *" + aryTest[2]);
Hey, you didn't tell your JavaScript VM where to split! Try this:
var strTest = '1,2,3,4';
var aryTest = strTest.split(' ,');
alert(typeof aryTest + " " + aryTest[2]);
Looks better?
virtuPIC
--
Airspace V - international hangar flying! http://www.airspace-v.com/ggadgets for tools & toys
On Aug 13, 1:26 pm, virtuPIC <WebMas...@airs pace-v.comwrote:
var strTest = '1,2,3,4';
var aryTest = strTest.split() ;
alert(typeof aryTest + " " + aryTest[2]);
Hey, you didn't tell your JavaScript VM where to split! Try this:
var strTest = '1,2,3,4';
var aryTest = strTest.split(' ,');
alert(typeof aryTest + " " + aryTest[2]);
Looks better?
Yes it does.
However according to the material I have read, including the Rhino,
the comma is the default. But I should have thought of that anyway.
Many Thanks,
Steve.
Steve meinte:
On Aug 13, 1:26 pm, virtuPIC <WebMas...@airs pace-v.comwrote:
>>var strTest = '1,2,3,4'; var aryTest = strTest.split() ; alert(typeo f aryTest + " " + aryTest[2]);
Hey, you didn't tell your JavaScript VM where to split! Try this:
var strTest = '1,2,3,4'; var aryTest = strTest.split(' ,'); alert(typeof aryTest + " " + aryTest[2]);
Looks better?
Yes it does.
However according to the material I have read, including the Rhino,
the comma is the default. But I should have thought of that anyway.
Read again. Mozilla doesn't state a "default separator". Instead
"If separator is omitted, the array returned contains one element
consisting of the entire string." [1]
I suppose other ECMAScript derivates behave equally.
Gregor
[1]
<http://developer.mozil la.org/en/docs/Core_JavaScript _1.5_Reference: Objects:String: split>
-- http://photo.gregorkofler.at ::: Landschafts- und Reisefotografie http://web.gregorkofler.com ::: meine JS-Spielwiese http://www.image2d.com ::: Bildagentur für den alpinen Raum
On 2008-08-13, Gregor Kofler <us****@gregork ofler.atwrote:
Steve meinte:
However according to the material I have read, including the Rhino,
the comma is the default. But I should have thought of that anyway.
Read again. Mozilla doesn't state a "default separator". Instead
"If separator is omitted, the array returned contains one element
consisting of the entire string." [1]
I suppose other ECMAScript derivates behave equally.
Probably the OP is thinking of the inverse operation, Array.join()
where Flanagan's O'Reilly book says "if the argument is omitted,
a comma is used."
Regards, Peter Billam
--
Peter Billam www.pjb.com.au www.pjb.com.au/comp/contact.html This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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