IE <DIV> layer and z-index question

[wilq]

I got a little problem, maybe You could help me out.

I have one layer that is used to darken all content on page (opacity
50%) to make other layer more visible.

If i show two separate Layers - darkenLayer with z-index:1, and a
other layer with z-index:2 - everything is ok. But i would like to do
something like this:

<DIV id="darken"></DIV>

<DIV id="someDIV">

<TABLE><TR><T D>
<DIV id="someChildDI V"blablalbal

<DIV id="doNotDarken ThisDiv" IMPORTANT DIV</DIV>

</DIV>

</TD></TR></TABLE>
</DIV>
My question is - how to make a DIV - doNotDarkenThis Div to be over the
darken DIV. I tried set higher z-index for doNotDarkenThis Div however
this do not solved problem. I read a few pages, looking alot on google
and still haven't got any clues. In my case 'darken' DIV have to be
position:absolu te, and 'someDIV' too...... Help!

[SAM]

wilq a écrit :

Ok i found a first workaround:

Setting z-index of parent element higher than a darkening element,
then gives all content lower z-index makes it show properly. Here is
code:

Yes that works too.

It's difficult for me to judge since my Fx worked fine with a lot of
options about these z-index and because I have not IE ...

The given code is very tortuous just to get an element correctly Z indexed.
Did you find it in M$ recommendations (FAQ or knowledge base) ?

--
sm

[wilq]

On Feb 14, 2:36*am, SAM <stephanemoriau x.NoAd...@wanad oo.fr.invalid>
wrote:

wilq a écrit :

Ok i found a first workaround:

Setting z-index of parent element higher than a darkening element,
then gives all content lower z-index makes it show properly. Here is
code:

Yes that works too.

It's difficult for me to judge since my Fx worked fine with a lot of
options about these z-index and because I have not IE ...

The given code is very tortuous just to get an element correctly Z indexed..
Did you find it in M$ recommendations (FAQ or knowledge base) ?

--
sm

Huh Your answer was faster than mine "remove post" method :)) In fact
i found that i did not solved problem, just made a "visual" mistake
when trying solve this. Instead i made a somewhat stupid but working
solution: I create one DIV outside of everything and when i want to
make "doNotDarkenThi sDiv" visible - i just copy it all via appendChild
to this temporary DIV. After everything is back to normal i just
copying it back to orginal place. Now i have other problem:

Copying it to temporary layer works well and on every Browsers.

Now I got new problem - I got problem to appendChild it back to
orgiginal DIV ech... This problem sux so hard ;(

[Thomas 'PointedEars' Lahn]

wilq wrote:

I got a little problem, maybe You could help me out.

I have one layer that is used to darken all content on page (opacity
50%) to make other layer more visible.

Nonsensical approach. Use a dark background color and set the `opacity' CSS
property and its proprietary equivalents for the elements to be darkened
accordingly.

That said, your problem is off-topic here as script programming is not
involved at all. Try comp.infosystem s.www.authoring.stylesheets.
PointedEars
--
var bugRiddenCrashP ronePieceOfJunk = (
navigator.userA gent.indexOf('M SIE 5') != -1
&& navigator.userA gent.indexOf('M ac') != -1
) // Plone, register_functi on.js:16

[wilq]

Nonsensical approach. *Use a dark background color and set the `opacity'CSS
property and its proprietary equivalents for the elements to be darkened
accordingly.

That said, your problem is off-topic here as script programming is not
involved at all. *Try comp.infosystem s.www.authoring.stylesheets.

PointedEars
--
var bugRiddenCrashP ronePieceOfJunk = (
* * navigator.userA gent.indexOf('M SIE 5') != -1
* * && navigator.userA gent.indexOf('M ac') != -1
) *// Plone, register_functi on.js:16

It seems that You did not understand all problem that I told about
here - just read one of links that i typed here and You will
understand that solution of mine problem isn't lying in css only (i
really tried to solve it just only via css - IT SHOULD BE solved via
CSS, but IE is kind of bugged program). In fact as I proposed - there
is JS solution for this problem... You can try check it by yourself
using code that I gave ..... Eh.... never mind.