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SetTimeout & How to pass parameters to delayed function

31 New Member
Hi,

Can someone help me with the command format please.

I have a function (called fade) that was 3 parameters:
the first 2 are colours therefore formatted #123456
and the 3rd is a number of milliseconds.

A normal call to the function therefore looks like this:

Expand|Select|Wrap|Line Numbers
  1. fade("#FFFFFF", "#000000", 1000); 
// ie fades from white to black over 1 sec.
this works fine, but I now want to delay the start of the function.

So I tried;
Expand|Select|Wrap|Line Numbers
  1. setTimeout('fade("#FFFFFF", "#000000". 1000)' , 2000);
// to delay start by 2 secs
then realised that I needed to take care of the quotes .. so tried lots! of attempts like:
Expand|Select|Wrap|Line Numbers
  1. setTimeout('fade(\"#FFFFFF\", \"#000000\", 1000)', 2000)
but none of my attempts work.

Could someone guide me please.
Thanks
Dec 29 '07 #1
5 3278
mrhoo
428 Contributor
setTimeout and setInterval will accept a function as the first argument-

setTimeout(func tion(){fade("#F FFFFF", "#000000")} , 1000);
Dec 29 '07 #2
Gretsch
31 New Member
setTimeout and setInterval will accept a function as the first argument-

setTimeout(func tion(){fade("#F FFFFF", "#000000")} , 1000);
Thanks, Unfortunately, it didnt work, but then I noticed the 3rd parm was missing, so I added the 3rd parameter to your suggestion as follows:

setTimeout(func tion(){fade("#F FFFFF", "#000000", 2000)}, 1000);

(I also tried wrapping the 2000 with "s (ie "2000"), but in neither case did it work.?
Dec 29 '07 #3
Gretsch
31 New Member
Correction:
It DOES now work with the 2000 wrapped in "s (ie "2000")

Thanks VERY much for your help. I would never have found this solution without your help!
Dec 29 '07 #4
Gretsch
31 New Member
I am using a function that fades the background between 2 colours over n secs.
It works fine.

I now need to delay the start of the fade - so I tried setTimeout, which (seemingly) allows a delay before the function is called.

eg If I set fade time to 2 secs, and delay_time to 5 secs ... it doesnt seem to work as intended.

Can someone help me understand how setTimeout works.
1) Does it delay the calling of the function for n secs?,
or
2) Does it delay the return from the function?

If 2) above, is there another solution I could use?

Thanks for your help.
Dec 29 '07 #5
acoder
16,027 Recognized Expert Moderator MVP
I've merged your threads because they relate to the same problem.

See if this link helps you to understand setTimeout. If not, post your code (including fade()).
Dec 29 '07 #6

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