String.replace question

[glennremar]

I was tring to write a function to make that took the letters that a
user is searching for and making the first occurrence of it bold in
the results (ignoring the case).

>From reading javascript books and looking at posts in this group, I

thought this would work. Perhaps I misunderstood what $1 is. But in
the results, I am getting a bold $1 with IE6.

How can I determine what the occurrence of the phrase is in the
correct case?

I realize I can write this parsing the string without regular
expressions but I thought this would be cleaner.

var match = new RegExp( escapeCharsForR egExp(typedLett ers), "i");
if (match.test(tex t))
{
text = text.replace(ma tch, '<b>' + '$1' + '</b>' );
}

[glennremar]

I found the answer to my question which none of the texts I had
covered. I should have be using $& instead of $1.

I found the answer at:
http://developer.mozilla.org/en/docs/About_JavaScript

[Lee]

gl********@gmai l.com said:

>
I was tring to write a function to make that took the letters that a
user is searching for and making the first occurrence of it bold in
the results (ignoring the case).

>>From reading javascript books and looking at posts in this group, I

thought this would work. Perhaps I misunderstood what $1 is. But in
the results, I am getting a bold $1 with IE6.

How can I determine what the occurrence of the phrase is in the
correct case?

I realize I can write this parsing the string without regular
expressions but I thought this would be cleaner.

var match = new RegExp( escapeCharsForR egExp(typedLett ers), "i");
if (match.test(tex t))
{
text = text.replace(ma tch, '<b>' + '$1' + '</b>' );
}

$1 is the value of the text that matches the part of the regexp
which is enclosed in the first pair of parentheses. You haven't
shown us your regexp, but I assume it doesn't contain parens.
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