Hi,
I am working on online recharge module. Everything is in place but when
you click on submit it does not notify user that the request is getting
processed and he needs to wait for couple of seconds. I need to add a
popup window displaying this message. Can anyone suggest me how to do
this? I just need to open 1 window , sense some event in parent window
and then close the popup window..Kindly please help
I truly apppreciate your help
D
2  1376 
"Devika" <de*********@gm ail.comwrote in
news:11******** **************@ f16g2000cwb.goo glegroups.com:
Hi,
I am working on online recharge module. Everything is in place but
when you click on submit it does not notify user that the request is
getting processed and he needs to wait for couple of seconds. I need
to add a popup window displaying this message. Can anyone suggest me
how to do this? I just need to open 1 window , sense some event in
parent window and then close the popup window..Kindly please help
I would lose the pop-up window entirely, and instead, change/disable
your submit button.
For example, give you submit button an id of "submitButt on".
Then, in your <formtag, add "onsubmit="docu ment.getElement ById
('submitButton' ).value='please wait...';docume nt.getElementBy Id
('submitButton) .disabled=true"
So...
<form action="xxxxxx" method="post" onsubmit="docum ent.getElementB yId
('submitButton' ).value='please wait...';docume nt.getElementBy Id
('submitButton) .disabled=true" >
<input type="submit" value="Submit me!" id="submitButto n" />
</form>
Thansk you sooo much . It helped !
Good Man wrote:
"Devika" <de*********@gm ail.comwrote in
news:11******** **************@ f16g2000cwb.goo glegroups.com:
Hi,
I am working on online recharge module. Everything is in place but
when you click on submit it does not notify user that the request is
getting processed and he needs to wait for couple of seconds. I need
to add a popup window displaying this message. Can anyone suggest me
how to do this? I just need to open 1 window , sense some event in
parent window and then close the popup window..Kindly please help
I would lose the pop-up window entirely, and instead, change/disable
your submit button.
For example, give you submit button an id of "submitButt on".
Then, in your <formtag, add "onsubmit="docu ment.getElement ById
('submitButton' ).value='please wait...';docume nt.getElementBy Id
('submitButton) .disabled=true"
So...
<form action="xxxxxx" method="post" onsubmit="docum ent.getElementB yId
('submitButton' ).value='please wait...';docume nt.getElementBy Id
('submitButton) .disabled=true" >
<input type="submit" value="Submit me!" id="submitButto n" />
</form>
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