Hi,
I'd like to use regular expression for checking validity of a field.
What would be the expression for :
firstname, lastname, organisation23
so basically, a string + comma then another string + comma then a
alphanumeric string
thanks 10 1626 sa************* @googlemail.com wrote:
Hi,
I'd like to use regular expression for checking validity of a field.
What would be the expression for :
firstname, lastname, organisation23
so basically, a string + comma then another string + comma then a
alphanumeric string
Basically:
^([a-z]+,\s*){2}[a-z0-9]+$/i
Problem here is exotic characters like ç, ö, etc, which are offcourse
totally valid in names, but won't match here. Also spaces (\s), -, ' etc....
Grtz,
--
Rik Wasmus
Thanks Rik,
I don't need to handle those special characters anyway ... lucky me.
however i do need to handle spaces ! I mean spaces should be allowed. sa************* @googlemail.com wrote:
Thanks Rik,
I don't need to handle those special characters anyway ... lucky me.
however i do need to handle spaces ! I mean spaces should be allowed.
^([a-z\s]+,){2}[a-z0-9\s]+$/i
Grtz,
--
Rik Wasmus
Thanks,
I've tried to use it this way :
/^([a-z\s]+,){2}[a-z0-9\s]+$/i.exec(myString )
but whatever the value of myString is, it always return null. Any clue
?
Please ignore my last post.
Your regex, works just great !
thank you very much.
After a few tests I can say it works almost well.
The only thing is that it allows me to enter something like
test, ,test
so basically, spaces should be allowed BUT there should be at least one
character, in other words empty strings should not be allowed. sa************* @googlemail.com wrote:
After a few tests I can say it works almost well.
The only thing is that it allows me to enter something like
test, ,test
so basically, spaces should be allowed BUT there should be at least
one character, in other words empty strings should not be allowed.
Tsssk, get your requirements straight :-).
Here you go:
^(\s*([a-z]+\s*)+,){2}\s*([a-z0-9]+\s*)+$/i
Grtz,
--
Rik Wasmus
JRS: In article <11************ **********@75g2 000cwc.googlegr oups.com>,
dated Mon, 14 Aug 2006 06:19:25 remote, seen in
news:comp.lang. javascript, sa************* @googlemail.com posted :
>I'd like to use regular expression for checking validity of a field. What would be the expression for :
firstname, lastname, organisation23
so basically, a string + comma then another string + comma then a alphanumeric string
Maybe no : better a commaless string + comma then another commaless
string + comma then a string; and ignoring whitespace between elements
if you use, say, .match to get the three elements.
Only of it is impossible for the organisation name to contain a comma
(or other non-alphanumeric) would your description serve,
Consider the case of
St = "James, Smith, Mart-Wal & sons, Inc."
M = St.match(/^([^,]+),\s*([^,]+),\s*(.+$)/)
No match : M = null
Match : M[1]..M[3] are the fields.
<URL:http://www.merlyn.demo n.co.uk/js-valid.htm>
--
© John Stockton, Surrey, UK. ?@merlyn.demon. co.uk Turnpike v4.00 IE 4 ©
<URL:http://www.jibbering.c om/faq/>? JL/RC: FAQ of news:comp.lang. javascript
<URL:http://www.merlyn.demo n.co.uk/js-index.htmjscr maths, dates, sources.
<URL:http://www.merlyn.demo n.co.uk/TP/BP/Delphi/jscr/&c, FAQ items, links.
John,
Your comment is very relevant. I had not thought of that :(
How could I valid non-alphanumeric characters in the third string ?
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