Regular Expression help

[Chris Kettenbach]

Does anyone know of a regualr expression to validate US and Canadian Postal
Codes?
I want to be able to accept ##### or #####-#### or Canadian A#A #A# that is
alpha,number,al pha number,alpha,nu mber.

I am new to regular expressions. The US 5 digit part is easy, but I get
stuck after that.

var pattern = new RegExp(/\\d{5}/)

Any ideas? Thanks everybody.

Chris

[Julian Turner]

Chris Kettenbach wrote:

Does anyone know of a regualr expression to validate US and Canadian Postal
Codes?
I want to be able to accept ##### or #####-#### or Canadian A#A #A# that is
alpha,number,al pha number,alpha,nu mber.

I am new to regular expressions. The US 5 digit part is easy, but I get
stuck after that.

var pattern = new RegExp(/\\d{5}/)

Any ideas? Thanks everybody.

Chris

Firstly there are two ways of creating a RegExp, and your example mixes
the two up.

The first is:-

r=new RegExp("Pattern ", "Optional Switches g and i");

The second is a Regular Expression Literal

r=/Pattern/Optional Switches;

Note that with the first the Pattern must be in a string, and needs to
use escapes for backslashes \\

In terms of your requirement, I am sure others will have better
suggestions but you could try the following:-

var r=/^(\d{5}|\d{5}-\d{4}|[A-Za-z]\d[A-Za-z] \d[A-Za-z]\d)$/;

Same as:-

var r=new RegExp("^(\\d{5 }|\\d{5}-\\d{4}|[A-Za-z]\\d[A-Za-z]
\\d[A-Za-z]\\d)$");

Note that the ^ will prohibit any leading characters, and $ will
prohibit any trailing characters, the | is an alternative marker, and I
assume only one space between A#A #A#

Hope this helps.

Julian

[Chris Kettenbach]

Beautiful. Thanks for your help.

"Julian Turner" <ju****@baconbu tty.com> wrote in message
news:11******** **************@ g47g2000cwa.goo glegroups.com.. .

Chris Kettenbach wrote:

Does anyone know of a regualr expression to validate US and Canadian
Postal
Codes?
I want to be able to accept ##### or #####-#### or Canadian A#A #A# that
is
alpha,number,al pha number,alpha,nu mber.

I am new to regular expressions. The US 5 digit part is easy, but I get
stuck after that.

var pattern = new RegExp(/\\d{5}/)

Any ideas? Thanks everybody.

Chris

Firstly there are two ways of creating a RegExp, and your example mixes
the two up.

The first is:-

r=new RegExp("Pattern ", "Optional Switches g and i");

The second is a Regular Expression Literal

r=/Pattern/Optional Switches;

Note that with the first the Pattern must be in a string, and needs to
use escapes for backslashes \\

In terms of your requirement, I am sure others will have better
suggestions but you could try the following:-

var r=/^(\d{5}|\d{5}-\d{4}|[A-Za-z]\d[A-Za-z] \d[A-Za-z]\d)$/;

Same as:-

var r=new RegExp("^(\\d{5 }|\\d{5}-\\d{4}|[A-Za-z]\\d[A-Za-z]
\\d[A-Za-z]\\d)$");

Note that the ^ will prohibit any leading characters, and $ will
prohibit any trailing characters, the | is an alternative marker, and I
assume only one space between A#A #A#

Hope this helps.

Julian

[Michael Winter]

On 20/10/2005 16:35, Julian Turner wrote:

[snip]

var r=/^(\d{5}|\d{5}-\d{4}|[A-Za-z]\d[A-Za-z] \d[A-Za-z]\d)$/;

Only slightly improved:

/^(\d{5}(-\d{4})?|[a-z]\d[a-z] \d[a-z]\d)$/i

The space prevents the Canadian postal code pattern from being reduced.

[snip]

Mike

--
Michael Winter
Prefix subject with [News] before replying by e-mail.

[Stephen Chalmers]

Chris Kettenbach <c_**********@h otmail.com> wrote in message news:yO******** *************** *******@giganew s.com...

Does anyone know of a regualr expression to validate US and Canadian Postal
Codes?
I want to be able to accept ##### or #####-#### or Canadian A#A #A# that is
alpha,number,al pha number,alpha,nu mber.

I am new to regular expressions. The US 5 digit part is easy, but I get
stuck after that.

Rather than using one catch-all expression, it may be better practice to
validate postcodes against the specified region.
--
S.C.