XMLhttp request problem

[sudhaoncyberworld]

Hi all

i am using asp.net v2.0

In one of my page i am calling another page using xml http , this is
working fine but first time only ,

I am sending the request on click of button , when i click the button
second time, it's returning the previous response and it's not even
calling that page again, where could be the problem.

client side (aspx page 1- javascript)

var http=new ActiveXObject(" Msxml2.XMLHTTP" );
http.open("GET" ,"Gensparql.asp x",false);
http.send();
if(http.readySt ate == 4)
{
if(http.respons eText!=null && http.responseTe xt!='' )
{
//my process
}
}

server side (aspx page 2)

Response.Clear( );
Response.Conten tType = "text/xml";
Response.Write( retVal);
Response.End();

//second time returning same previous output and not calling the aspx
page 2
Hope u understand my problem,i am in urgent, Thanks in advance

[knocte]

su************* **@gmail.com escribió:

Hi all

i am using asp.net v2.0

In one of my page i am calling another page using xml http , this is
working fine but first time only ,

I am sending the request on click of button , when i click the button
second time, it's returning the previous response and it's not even
calling that page again, where could be the problem.

client side (aspx page 1- javascript)

var http=new ActiveXObject(" Msxml2.XMLHTTP" );
http.open("GET" ,"Gensparql.asp x",false);
http.send();
if(http.readySt ate == 4)
{
if(http.respons eText!=null && http.responseTe xt!='' )
{
//my process
}
}

server side (aspx page 2)

Response.Clear( );
Response.Conten tType = "text/xml";
Response.Write( retVal);
Response.End();

//second time returning same previous output and not calling the aspx
page 2
Hope u understand my problem,i am in urgent, Thanks in advance

Perhaps you must send HTTP headers informing about how cacheable is the
content. You could write it so as to expire immediately. BTW, don't use
only ActiveX, or else other (standards compliant) browsers won't work
with your page.

Andrew [ knocte ]

--

[Jambalaya]

Append a random number after the url that's being called. The browser
will not use the cache. Just make sure to use a different random number
for each call.

http.open("GET" ,"Gensparql.asp x?nocache=46873 2156795431",fal se);

[Randy Webb]

Jambalaya said the following on 10/12/2005 10:25 AM:

Append a random number after the url that's being called.
And what is that for?
The browser will not use the cache.
It will if I tell it to.
Just make sure to use a different random number for each call.
Each call of what?

http.open("GET" ,"Gensparql.asp x?nocache=46873 2156795431",fal se);

Oh wait, I see now. If you had bothered to quote what you were replying
to it would be easier to see that your approach has a simple flaw in it.
Instead of just trying to guess at a random number, you append the
current time in milliseconds.

--
Randy
comp.lang.javas cript FAQ - http://jibbering.com/faq & newsgroup weekly
Answer:It destroys the order of the conversation
Question: Why?
Answer: Top-Posting.
Question: Whats the most annoying thing on Usenet?

[Jambalaya]

>Oh wait, I see now. If you had bothered to quote what you were replying

to it would be easier to see that your approach has a simple flaw in it.
Instead of just trying to guess at a random number, you append the
current time in milliseconds.

There was no flaw. Just a different method to accomplish the goal.

--
Jambalaya
Question: What's the #2 most annoying thing on Usenet?
Answer: Netiquette Nazis.

[Randy Webb]

Jambalaya said the following on 10/13/2005 12:22 AM:

Oh wait, I see now. If you had bothered to quote what you were replying
to it would be easier to see that your approach has a simple flaw in it.
Instead of just trying to guess at a random number, you append the
current time in milliseconds.

There was no flaw. Just a different method to accomplish the goal.

And what method is that? Since you did not elaborate and your code was
hard-coded and showed no signs of being generated, it indicated that one
should hard-code that random number. That is a flaw in the approach -
not a different method to accomplish the same goal.

--
Randy
comp.lang.javas cript FAQ - http://jibbering.com/faq & newsgroup weekly
Answer:It destroys the order of the conversation
Question: Why?
Answer: Top-Posting.
Question: Whats the most annoying thing on Usenet?

[Jambalaya]

>>>Oh wait, I see now. If you had bothered to quote what you were replying

to it would be easier to see that your approach has a simple flaw in it.
Instead of just trying to guess at a random number, you append the
current time in milliseconds.

There was no flaw. Just a different method to accomplish the goal.

And what method is that?
You really do seem smarter than this, Randy. I was showing the end
result of the concatenation so that the original poster would
understand the concept. I wasn't writing the code for him. I assume
since he is using xmlhttp that he has sufficient javascript knowledge
to be able to generate a random number and append it to a string.
Since you did not elaborate and your code was
hard-coded and showed no signs of being generated, it indicated that one
should hard-code that random number.
No, if you will reread my first post, it indicates the opposite. I
quote myself, "Just make sure to use a different random number for each
call."
That is a flaw in the approach -
not a different method to accomplish the same goal.

I guess I'll admit there was a flaw. And that is that I didn't write
all the javascript for the original poster. I guess I'm more of a
teach-a-man-to-fish sort of guy versus a give-a-man-a-fish guy.

J

[Andrew Stephanoff]

1.You must generate XML-content on php or ASP and set th header with
following info: "Content-type: application/xml; Cache-control:
no-cache;". If you use "clear" XML, the content will be cached.
2. Code in javascript will be follow:

var http;
if (window.XMLHttp Request) {
try {http = new XMLHttpRequest( );}
catch(e){http = false;}
} else if (window.ActiveX Object("Microso ft.XMLHTTP")) {
try {http = new window.ActiveXO bject("Microsof t.XMLHTTP");}
catch(e) {
try {http = new window.ActiveXO bject("Msxml2.X MLHTTP");}
catch(e){http = false;}
} else {
http = false;
}
http.open("GET" ,"Gensparql.asp x",true);
http.onreadysta techange = function() {
if (http.readyStat e == 4)
if (http.status == 200) {
//my process
}
}
http.send(null) ;

[Randy Webb]

Jambalaya said the following on 10/13/2005 4:30 AM:

Oh wait, I see now. If you had bothered to quote what you were replying
to it would be easier to see that your approach has a simple flaw in it.
Instead of just trying to guess at a random number, you append the
current time in milliseconds.
There was no flaw. Just a different method to accomplish the goal.

And what method is that?

You really do seem smarter than this, Randy. I was showing the end
result of the concatenation so that the original poster would
understand the concept. I wasn't writing the code for him. I assume
since he is using xmlhttp that he has sufficient javascript knowledge
to be able to generate a random number and append it to a string.

Now it makes sense :)

Since you did not elaborate and your code was
hard-coded and showed no signs of being generated, it indicated that one
should hard-code that random number.

No, if you will reread my first post, it indicates the opposite. I
quote myself, "Just make sure to use a different random number for each
call."

Fair enough.

That is a flaw in the approach -
not a different method to accomplish the same goal.

I guess I'll admit there was a flaw. And that is that I didn't write
all the javascript for the original poster. I guess I'm more of a
teach-a-man-to-fish sort of guy versus a give-a-man-a-fish guy.

That's probably why I didn't write the script either, huh? <g>

--
Randy
comp.lang.javas cript FAQ - http://jibbering.com/faq & newsgroup weekly

[Richard Cornford]

Jambalaya wrote:
<snip>

... , it indicated that
one should hard-code that random number.
No, if you will reread my first post, it indicates the
opposite. I quote myself, "Just make sure to use a
different random number for each call."

It is considerably easier to say "just make sure to use a different
random number for each call" (assuming "call" is acceptable terminology
here (which it probably isn't)) than to actually do it. Remember that
you would have to be keeping track of which random numbers had been
used, even between sessions, as it would not be too good if the browser
decided to deliver content that it had downloaded in a previous session
from its cache in response to a request in a later one.

That is why using the millisecond time in this context has been
proposed, as each time will be unique (at least so long as no two times
are requested within about 60 milliseconds, at most) and it is in the
nature of time that is does not repeat itself. That is; what is wanted
is a unique number rather than a random one, and each item in a sequence
of increasing integer values is unique within that sequnce.

That is a flaw in the approach -
not a different method to accomplish the same goal.

I guess I'll admit there was a flaw.

Yes it is. At lest in part because the proposal that the OP should "make
sure" that no two random numbers be the same is considerably more
troublesome than an available alternative.
And that is that I didn't write
all the javascript for the original poster.
I guess I'm more of a teach-a-man-to-fish sort
of guy versus a give-a-man-a-fish guy.

"Fishing" in an HTTP context would be better mastered with an
understanding of HTTP, and specifically the way in which various HTTP
headers can be configured to discourage client-side caching of various
resources (and possibly the different ways in which POST and GET
requests are handled with regard to caching). With the correct header
configuration it is possible that the URL hack would be unnecessary,
else you would see such "random numbers" on the end of every URL on
every dynamic site.

Richard.