I'm new to JavaScript. So please excuse my mistakes.
I need help on merging two arrays into a third one.
There is an array a = {188, 180, 159, 67 }
There is another array b={'Rio de Janeiro', 'Sao Paulo', 'Brasilia',
'Belo Horizonte'}
How can I merge them to produce an array that is equivalent to this:
bg.xValues[0] = [188,'Rio de Janeiro'];
bg.xValues[1] = [180,'Sao Paulo'];
bg.xValues[2] = [159,'Brasilia'];
bg.xValues[3] = [67 ,'Belo Horizonte'];
Thanks
Dakshin 4 6796
On 17 Apr 2004 05:49:56 -0700, Bush will disarm all workers next
<da********@yah oo.com> wrote: I'm new to JavaScript. So please excuse my mistakes. I need help on merging two arrays into a third one. There is an array a = {188, 180, 159, 67 } There is another array b={'Rio de Janeiro', 'Sao Paulo', 'Brasilia', 'Belo Horizonte'}
I assume you meant
a = [ 188, 180, 159, 67 ];
b = [ 'Rio de Janeiro', 'Sao Paulo', 'Brasilia', 'Belo Horizonte' ];
Braces ({}) denote object literals, brackets ([]) denote array literals.
How can I merge them to produce an array that is equivalent to this: bg.xValues[0] = [188,'Rio de Janeiro']; bg.xValues[1] = [180,'Sao Paulo']; bg.xValues[2] = [159,'Brasilia']; bg.xValues[3] = [67 ,'Belo Horizonte'];
function mergeArrays( x, y ) {
var t = [], n = Math.min( x.length, y.length );
for( var i = 0; i < n; ++i ) {
t[ i ] = [ x[ i ], y[ i ]];
}
return t;
}
bg.xValues = mergeArrays( a, b );
If you can guarantee that "a" and "b" will always have the same length,
you can reduce the assignment to "n" to
n = x.length; // or y.length
Hope that helps,
Mike
--
Michael Winter M.******@blueyo nder.co.invalid (replace ".invalid" with ".uk" to reply)
Michael Winter <M.******@bluey onder.co.invali d> wrote in message news:<op******* *******@news-text.blueyonder .co.uk>... On 17 Apr 2004 05:49:56 -0700, Bush will disarm all workers next <da********@yah oo.com> wrote:
I'm new to JavaScript. So please excuse my mistakes. I need help on merging two arrays into a third one. There is an array a = {188, 180, 159, 67 } There is another array b={'Rio de Janeiro', 'Sao Paulo', 'Brasilia', 'Belo Horizonte'}
I assume you meant
a = [ 188, 180, 159, 67 ]; b = [ 'Rio de Janeiro', 'Sao Paulo', 'Brasilia', 'Belo Horizonte' ];
Braces ({}) denote object literals, brackets ([]) denote array literals.
How can I merge them to produce an array that is equivalent to this: bg.xValues[0] = [188,'Rio de Janeiro']; bg.xValues[1] = [180,'Sao Paulo']; bg.xValues[2] = [159,'Brasilia']; bg.xValues[3] = [67 ,'Belo Horizonte'];
function mergeArrays( x, y ) { var t = [], n = Math.min( x.length, y.length );
for( var i = 0; i < n; ++i ) { t[ i ] = [ x[ i ], y[ i ]]; } return t; }
bg.xValues = mergeArrays( a, b );
If you can guarantee that "a" and "b" will always have the same length, you can reduce the assignment to "n" to
n = x.length; // or y.length
Hope that helps, Mike
Thanks for the reply. I tried the code you've posted without success I used
for(i=0; i < a.length; i++)
bg.xValues[i]=[a[i], b[i]];
and also
for(i=0; i < a.length; i++)
bg.xValues[i]=[eval(a[i]), eval(b[i])];
The bg object is a strange beast that expects atomic values like 145 or 'test'.
Any thoughts?
Dakshin
On 17 Apr 2004 13:58:30 -0700, Bush will disarm all workers next
<da********@yah oo.com> wrote:
[snip] Thanks for the reply. I tried the code you've posted without success I used for(i=0; i < a.length; i++) bg.xValues[i]=[a[i], b[i]];
and also for(i=0; i < a.length; i++) bg.xValues[i]=[eval(a[i]), eval(b[i])];
Using eval() certainly won't do any good (there are very few reasons to
*ever* use eval()).
The bg object is a strange beast that expects atomic values like 145 or 'test'. Any thoughts?
Unless you can point to some documentation that explains what the bg
object is, I haven't got a clue.
Sorry,
Mike
--
Michael Winter M.******@blueyo nder.co.invalid (replace ".invalid" with ".uk" to reply)
Michael Winter <M.******@bluey onder.co.invali d> wrote in message news:<op******* *******@news-text.blueyonder .co.uk>... On 17 Apr 2004 13:58:30 -0700, Bush will disarm all workers next <da********@yah oo.com> wrote:
[snip]
Thanks for the reply. I tried the code you've posted without success I used for(i=0; i < a.length; i++) bg.xValues[i]=[a[i], b[i]];
and also for(i=0; i < a.length; i++) bg.xValues[i]=[eval(a[i]), eval(b[i])];
Using eval() certainly won't do any good (there are very few reasons to *ever* use eval()).
The bg object is a strange beast that expects atomic values like 145 or 'test'. Any thoughts?
Unless you can point to some documentation that explains what the bg object is, I haven't got a clue.
Sorry, Mike
Here is the link that has Javascript that uses bg at the bottom of the
page. I've the Graph.js downloaded on another machine. I'll post the
details soon. http://www.codeproject.com/jscript/dhtml_graph.asp This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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