Convert a large number of file to another name in java

[lokanath60]

 
 
 
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
 
 
 
 
/*Step1 :-nake sure that u have ur project loc path other wise it ll show exception
 Step2:run this java code 
 */
 
 
public class fileNameChanger {
 
 
 
 
    public static void main(String[] args) {
        String oldName, newName, num = null;
        File folder = new File("C:\\demo");
 
        String projectLoc="C:\\demo\\"; //write your project location 
 
 
        File[] listOfFiles = folder.listFiles();
        for (int i = 0; i < listOfFiles.length; i++) {
 
            if (listOfFiles[i].isFile()) {
 
                File oldFile = new File(projectLoc + listOfFiles[i].getName());
 
                makeNewFile(oldFile);
 
            }
 
        }
    }
 
    public static boolean makeNewFile(File oldFile) {
        String newProjectLoc="C:\\demo\\new\\";
        String oldName = oldFile.getName();
        System.out.println("OldFileName :" + oldName);
        String subFileName = oldName.substring(0, oldName.indexOf('.'));
        int num = subFileName.charAt(subFileName.length() - 1);
        String newFileName = subFileName.replace((char) num, (char) ++num);
        System.out.println("NewFileName :" + newFileName + ".html");
                File newName = new File(newProjectLoc + newFileName + ".html");
        try {
            copyFile(oldFile, newName);
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        return true;
 
    }
 
    private static void copyFile(File source, File dest)
 
    throws IOException {
 
        InputStream input = null;
 
        OutputStream output = null;
 
        try {
 
            input = new FileInputStream(source);
 
            output = new FileOutputStream(dest);
 
            byte[] buf = new byte[1024];
 
            int bytesRead;
 
            while ((bytesRead = input.read(buf)) > 0) {
 
                output.write(buf, 0, bytesRead);
 
            }
            dest.createNewFile();
 
        } finally {
 
            input.close();
 
            output.close();
 
        }
 
    }
 
}
 
 
 
 

[audrey45]

in C# we have GUID but i think in java you have UUID . UUID will generate filename for you depends on your filename you want to change :)

[Nepomuk]

What exactly is your question? The code you provided certainly looks like you've thought about it quite a bit.