java.io.FileNot FoundException: while reading the file from client to server

252 Contributor

Hi,
I am trying to read a file sent from client to server. Here is how I am trying it ....

Expand|Select|Wrap|Line Numbers

 
String filePath = request.getParameter("SelectCSVFile"); 

System.out.println("path:::---> "+filePath);

String fileName = filePath.substring(filePath.lastIndexOf("/")+1);

System.out.println("File Name:\t"+fileName);
 
try {

File file = new File(filePath);

URL serverURL = new URL(SERVER_URL);

URLConnection serverCon = serverURL.openConnection();

// setup connection

serverCon.setDoInput(true);

serverCon.setDoOutput(true);

serverCon.setUseCaches(false);

serverCon.setRequestProperty(FILENAME_HEADER, fileName); // send the filename through HTTP header

System.out.println("Successfully set the header");

// POST the file's bytes to the connections OutputStream

OutputStream toServer = serverCon.getOutputStream();

System.out.println("Successfully get the servlet output Stream");

FileInputStream fromFile = new FileInputStream(file);//at this line it is throwing the exception

It is throwing the exception ..... here is the server log

Expand|Select|Wrap|Line Numbers

  
path:::---> C:/Documents and Settings/harbeer.kadian/My Documents/bugs-2007-09-07.csv//here separators are '/'

File Name: bugs-2007-09-07.csv

Successfully get the servlet output Stream

java.io.FileNotFoundException: C:\Documents and Settings\harbeer.kadian\My Documents\bugs-2007-09-07.csv //here separators are '\'(The system cannot find the path specified)

        at java.io.FileInputStream.open(Native Method)

        at java.io.FileInputStream.<init>(FileInputStream.java:106)

        at com.spi.defecttracker.controller.RequestHandler.uploadCSVFileData(RequestHandler.java:1486)

        at com.spi.defecttracker.controller.RequestHandler.processRequest(RequestHandler.java:164)

        at com.spi.defecttracker.controller.RequestHandler.doPost(RequestHandler.java:348)

        at javax.servlet.http.HttpServlet.service(HttpServlet.java:709)

        at javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

        at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:252)

        at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:173)

        at org.netbeans.modules.web.monitor.server.MonitorFilter.doFilter(MonitorFilter.java:368)

        at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:202)

        at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:173)

        at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:213)

        at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:178)

        at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:126)

        at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:105)

        at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:107)

        at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:148)

        at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:869)

        at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:664)

        at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:527)

        at org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:80)

        at org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:684)

        at java.lang.Thread.run(Thread.java:595)

The file path I am sending is using '/'(forward slash) as separator while the path exception is showing is using '\'(backward slash). How is it happening. How can I resolve it.

Sep 18 '07 #1

Subscribe Reply

18809

Nepomuk

3,112

Recognized Expert Specialist

Hi,
I am trying to read a file sent from client to server. Here is how I am trying it ....

Expand|Select|Wrap|Line Numbers

String filePath = request.getParameter("SelectCSVFile");

System.out.println("path:::---> "+filePath);

String fileName = filePath.substring(filePath.lastIndexOf("/")+1);

System.out.println("File Name:\t"+fileName);

try {

File file = new File(filePath);

URL serverURL = new URL(SERVER_URL);

URLConnection serverCon = serverURL.openConnection();

// setup connection

serverCon.setDoInput(true);

serverCon.setDoOutput(true);

serverCon.setUseCaches(false);

serverCon.setRequestProperty(FILENAME_HEADER, fileName); // send the filename through HTTP header

System.out.println("Successfully set the header");

// POST the file's bytes to the connections OutputStream

OutputStream toServer = serverCon.getOutputStream();

System.out.println("Successfully get the servlet output Stream");

FileInputStream fromFile = new FileInputStream(file);//at this line it is throwing the exception

It is throwing the exception ..... here is the server log

Expand|Select|Wrap|Line Numbers

path:::---> C:/Documents and Settings/harbeer.kadian/My Documents/bugs-2007-09-07.csv//here separators are '/'

File Name: bugs-2007-09-07.csv

Successfully get the servlet output Stream

java.io.FileNotFoundException: C:\Documents and Settings\harbeer.kadian\My Documents\bugs-2007-09-07.csv //here separators are '\'(The system cannot find the path specified)

        at java.io.FileInputStream.open(Native Method)

        at java.io.FileInputStream.<init>(FileInputStream.java:106)

        at com.spi.defecttracker.controller.RequestHandler.uploadCSVFileData(RequestHandler.java:1486)

        at com.spi.defecttracker.controller.RequestHandler.processRequest(RequestHandler.java:164)

        at com.spi.defecttracker.controller.RequestHandler.doPost(RequestHandler.java:348)

        at javax.servlet.http.HttpServlet.service(HttpServlet.java:709)

        at javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

        at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:252)

        at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:173)

        at org.netbeans.modules.web.monitor.server.MonitorFilter.doFilter(MonitorFilter.java:368)

        at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:202)

        at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:173)

        at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:213)

        at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:178)

        at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:126)

        at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:105)

        at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:107)

        at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:148)

        at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:869)

        at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:664)

        at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:527)

        at org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:80)

        at org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:684)

        at java.lang.Thread.run(Thread.java:595)

The file path I am sending is using '/'(forward slash) as separator while the path exception is showing is using '\'(backward slash). How is it happening. How can I resolve it.

Hi madhoriya22!
Is there any specific reason known to you, why

Expand|Select|Wrap|Line Numbers

System.out.println("Successfully set the header"); // line 15

doesn't create an output? Also, what does

Expand|Select|Wrap|Line Numbers

System.out.println("File exists: " + file.exists());

say? And why are you using '/' as a file separator, when the standard file separator under Windows is '\\'?

Greetings,
Nepomuk

*QUESTION TO THE ADMINS & CO: What is this code-tag-bug? It didn't let me create a java-code-section with some code but it did allow a text-code-section with the same code. Weird...*

Sep 18 '07 #2

r035198x

13,262

MVP

..
Greetings,
Nepomuk

*QUESTION TO THE ADMINS & CO: What is this code-tag-bug? It didn't let me create a java-code-section with some code but it did allow a text-code-section with the same code. Weird...*

The code tags bug (as I know it) is that when you quote a post with long lines of code posted under code tags then chances are high that that post that you make will appear as a blank post.

Edit: As evidenced by snowfall's second post here. The first post was also hit by the bug but I removed the quote from it through the edit facility.

Sep 18 '07 #3

madhoriya22

252

Contributor

Hi madhoriya22!
Is there any specific reason known to you, why

Expand|Select|Wrap|Line Numbers

System.out.println("Successfully set the header"); // line 15

doesn't create an output? Also, what does

Expand|Select|Wrap|Line Numbers

System.out.println("File exists: " + file.exists());

say? And why are you using '/' as a file separator, when the standard file separator under Windows is '\\'?

Greetings,
Nepomuk

*QUESTION TO THE ADMINS & CO: What is this code-tag-bug? It didn't let me create a java-code-section with some code but it did allow a text-code-section with the same code. Weird...*

Hi nepomuk,
By mistake I copied that line. //line 15

Expand|Select|Wrap|Line Numbers

System.out.println("File exists: " + file.exists());

and its not working .. means not able to find the file .....
Thats what I want to ask ......
How can i make it to find the file in client's system(The file I am supplying is on client's machine).

'/' separator I was using because while while getting the file name from the path supplied ... it was giving compile time error here

Expand|Select|Wrap|Line Numbers

 
String fileName = filePath.substring(filePath.lastIndexOf("/")+1);//here it was not taking back slash(\)

But now I have resolved it .... by doing like this ..

Expand|Select|Wrap|Line Numbers

String fileName = filePath.substring(filePath.lastIndexOf("\\")+1);

So pls give ur suggestions on that ..

Sep 19 '07 #4

Nepomuk

3,112

Recognized Expert Specialist

Hi nepomuk,
By mistake I copied that line. //line 15

Expand|Select|Wrap|Line Numbers

System.out.println("File exists: " + file.exists());

and its not working .. means not able to find the file .....

OK, that reduces the possibilities of what the mistake might be, as it's something with the Path.

How can i make it to find the file in client's system(The file I am supplying is on client's machine).

This program is running on the client's computer, isn't it? If it's running on server side, you'll not be able to do it like that. (And I don't know, how you could do it at all with Java, but maybe someone else does?)

'/' separator I was using because while while getting the file name from the path supplied ... it was giving compile time error here

Expand|Select|Wrap|Line Numbers

String fileName = filePath.substring(filePath.lastIndexOf("/")+1);//here it was not taking back slash(\)

But now I have resolved it .... by doing like this ..

Expand|Select|Wrap|Line Numbers

String fileName = filePath.substring(filePath.lastIndexOf("\\")+1);

The path on a windows system is normally separated with '\\', but as far as I know, '/' is possible. However, new File("this.txt" ).getAbsolutePa th() for example will supply a Path using '\\'.

If you don't know, what separator will be used, you can't do it quite like that - you'll have to check:

Expand|Select|Wrap|Line Numbers

 
String fileName;

if(filePath.indexOf('/') != -1) fileName = filePath.substring(filePath.lastIndexOf("/")+1);

else if(filePath.indexOf('\\') != -1) fileName = filePath.substring(filePath.lastIndexOf("\\")+1);

else fileName = filePath; // just to make sure

or (and this might solve your problem for you):

Expand|Select|Wrap|Line Numbers

 
filePath = filePath().replace('\\', '/');

String fileName = filePath.substring(filePath.lastIndexOf("\\")+1);

With this, you make sure, that there will only be '\\'s and no '/'s in your path.

Does that help?

Greetings,
Nepomuk

Sep 19 '07 #5

madhoriya22

252

Contributor

OK, that reduces the possibilities of what the mistake might be, as it's something with the Path.
This program is running on the client's computer, isn't it? If it's running on server side, you'll not be able to do it like that. (And I don't know, how you could do it at all with Java, but maybe someone else does?)
The path on a windows system is normally separated with '\\', but as far as I know, '/' is possible. However, new File("this.txt" ).getAbsolutePa th() for example will supply a Path using '\\'.

If you don't know, what separator will be used, you can't do it quite like that - you'll have to check:

Expand|Select|Wrap|Line Numbers

String fileName;

if(filePath.indexOf('/') != -1) fileName = filePath.substring(filePath.lastIndexOf("/")+1);

else if(filePath.indexOf('\\') != -1) fileName = filePath.substring(filePath.lastIndexOf("\\")+1);

else fileName = filePath; // just to make sure

or (and this might solve your problem for you):

Expand|Select|Wrap|Line Numbers

filePath = filePath().replace('\\', '/');

String fileName = filePath.substring(filePath.lastIndexOf("\\")+1);

With this, you make sure, that there will only be '\\'s and no '/'s in your path.

Does that help?

Greetings,
Nepomuk

Hi,
Thanks buddy .... I got your point :)

Does anyone know how to get the file from client to server?

Sep 19 '07 #6

Nepomuk

3,112

Recognized Expert Specialist

Hi,
Thanks buddy .... I got your point :)

Does anyone know how to get the file from client to server?

If you're prepared to use another language for that task, this thread might help you.

Greetings,
Nepomuk

Sep 19 '07 #7

madhoriya22

252

Contributor

If you're prepared to use another language for that task, this thread might help you.

Greetings,
Nepomuk

Hi,
I can not use other language. I have to do this in java. I wish I could make use of MultipartReques t.. But my html form is not using the encoding type which is required for multipart/form-data.
Anyway thanks for your suggestion :)

Sep 19 '07 #8

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