I need to recreate the following formula in java:
INT((A2^3 + B2^3) / 100)) + MOD((A2^3 + B2^2), 100)
Can someone show me how to do this in java?
-Thanks
4  21766 
Fred wrote: I need to recreate the following formula in java:
INT((A2^3 + B2^3) / 100)) + MOD((A2^3 + B2^2), 100)
Can someone show me how to do this in java?
-Thanks
What do you mean by int? you mean integrate or what?
Mod is % in java. so int i = 10 %5 = 0. 11 % 5 = 1 (if i remember
correctly)
To do powers you simply do Math.pow() look it up in your java api docs.
Look for the Math class.
int answer = ((int)(pow(a2,3 ) + pow(b2,3)) / 100) +
((pow(a2,3) + pow(b2,2)) % 100);
Fred <it****@cdw.com > wrote in message news:<pa******* *************** ******@cdw.com> ... I need to recreate the following formula in java:
INT((A2^3 + B2^3) / 100)) + MOD((A2^3 + B2^2), 100)
Can someone show me how to do this in java?
-Thanks
All you need to do is to spend 10 mins reading your textbook, rather than
posting your homework and waiting somebody to do it for you.
HD
"Fred" <it****@cdw.com > wrote in message
news:pa******** *************** *****@cdw.com.. .
I need to recreate the following formula in java:
INT((A2^3 + B2^3) / 100)) + MOD((A2^3 + B2^2), 100)
Can someone show me how to do this in java?
-Thanks
"Yoyoma_2" wrote: Fred wrote: I need to recreate the following formula in java:
INT((A2^3 + B2^3) / 100)) + MOD((A2^3 + B2^2), 100)
Can someone show me how to do this in java?
-Thanks
What do you mean by int? you mean integrate or what?
Mod is % in java. so int i = 10 %5 = 0. 11 % 5 = 1 (if i remember
correctly)
Nitpick:
% in Java is actually remainder, not Modulus.
True Modulus produces a result from 0 to the divisor-1.
% can produce negative results.
"the % operator is not a true mod operator, but computes the remainder,
which may be negative"
http://java.sun.com/docs/books/jls/assert-spec.html
To do powers you simply do Math.pow() look it up in your java api docs.
Look for the Math class. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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