public boolean equals(Object o) {
if (!(o.equals(nul l))) { // *
if (o instanceof foo) {
if (this.equals(o) ) {
return true;
}
}
}
return false;
}
I have the above method in a class foo. When I run the following code:
f.equals(f)
where f is an object of class foo, then I get a nullpointerexce ption in this
method. The reason is that since f is of type foo, in line * it recursively
calls the equals method and then o becomes null, and of course I can't
dereference null.
So how can I check if an object is null or not?
Thanks. 3 16931
On Fri, 31 Oct 2003 16:20:48 GMT, "Asad Khan" <uo**********@y ahoo.com>
wrote: public boolean equals(Object o) { if (!(o.equals(nul l))) { // * if (o instanceof foo) { if (this.equals(o) ) { return true; } } } return false; }
I have the above method in a class foo. When I run the following code:
f.equals(f)
where f is an object of class foo, then I get a nullpointerexce ption in this method. The reason is that since f is of type foo, in line * it recursively calls the equals method and then o becomes null, and of course I can't dereference null.
So how can I check if an object is null or not?
Did you try if (o != null)
Further to this answer different objects implement the method equals
differently. For example String objects implement it as a stright
comparrison of the contents of the string. So the equals method does not
tell you if one object is the same as another object. For this you need to
use the = = operator(withou t the space).
"Bryce (Work)" <sp******@berze rker-soft.com> wrote in message
news:ro******** *************** *********@4ax.c om... On Fri, 31 Oct 2003 16:20:48 GMT, "Asad Khan" <uo**********@y ahoo.com> wrote:
public boolean equals(Object o) { if (!(o.equals(nul l))) { // * if (o instanceof foo) { if (this.equals(o) ) { return true; } } } return false; }
I have the above method in a class foo. When I run the following code:
f.equals(f)
where f is an object of class foo, then I get a nullpointerexce ption in
thismethod. The reason is that since f is of type foo, in line * it
recursivelycalls the equals method and then o becomes null, and of course I can't dereference null.
So how can I check if an object is null or not?
Did you try if (o != null)
You can collapse it to:
public boolean equals(Object o) {
if(!(o instanceof foo)) {return false;} //this catches the null case
too
foo f = (foo)o; //f will _never_ be null here
// else check for whatever attributes makes foos equal
// if you do this.equals(f) like in your original example it will be an
infinite loop
// and [probably] have a StackOverFlow exception
}
"Bryce (Work)" <sp******@berze rker-soft.com> wrote in message
news:ro******** *************** *********@4ax.c om... On Fri, 31 Oct 2003 16:20:48 GMT, "Asad Khan" <uo**********@y ahoo.com> wrote:
public boolean equals(Object o) { if (!(o.equals(nul l))) { // * if (o instanceof foo) { if (this.equals(o) ) { return true; } } } return false; }
I have the above method in a class foo. When I run the following code:
f.equals(f)
where f is an object of class foo, then I get a nullpointerexce ption in
thismethod. The reason is that since f is of type foo, in line * it
recursivelycalls the equals method and then o becomes null, and of course I can't dereference null.
So how can I check if an object is null or not?
Did you try if (o != null) This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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