"kaming" <gu***@guest.co m> wrote in message
news:ck******** *@imsp212.netvi gator.com...
Dear all,
Do any one have idea how to obtain the exactly number of seconds in a
month with given month and year using DB2 given functions?
The formula is as simple as "No_of_days_for _a_month" * 60 * 60 * 24 .. but
It is a headache for me to find the No_of_days_for_ a_month... in DB2
Thanks very much!
Look at the days() function in the SQL Reference for your platform.
The days() function expects a single date argument and returns the number of
days between Jan 1, 0001 and the date in the argument. While that is not
particularly interesting with respect to a single date, it gets a lot more
useful if you calculate the days() result on two dates and then subtract one
from the other: that tells you the number of days difference between the
two.
Therefore:
select days('2004-02-01') - days('2004-01-01')
from sysibm.sysdummy 1
returns 31, the number of days in January, 2004.
By the same token:
select days('2004-03-01') -days('2004-02-01') as feb_2004,
days('2003-03-01') - days('2003-02-01') as feb_2003
from sysibm.sysdummy 1;
returns:
FEB_2004 FEB_2003
29 28
In other words, Feb 2004 (which is a leap year) has 29 days while Feb 2003
(which is not a leap year) had 28 days.
Rhino
