what's wrong?

[questions]

# include <stdio.h>
# include <math.h>
int main()
{ long int x,y;

printf("enter an integer\n");
scanf("%d",&x);

y=x%pow(10,3);

printf("the result is %d",y);

return 0;}

The compiler tell me there is something wrong with the "pow",but I
don't know what's the wrong?

[Kai-Uwe Bux]

questions wrote:

# include <stdio.h>
# include <math.h>
int main()
{ long int x,y;

printf("enter an integer\n");
scanf("%d",&x);

y=x%pow(10,3);

[snip]

The compiler tell me there is something wrong with the "pow",but I
don't know what's the wrong?

pow() returns a floating point (in this case, I guess a double) and x is a
long int. That is not a valid pair of operand types for the % operator.
Best

Kai-Uwe Bux

[Zeppe]

questions wrote:

# include <stdio.h>
# include <math.h>
int main()
{ long int x,y;

printf("enter an integer\n");
scanf("%d",&x);

y=x%pow(10,3);

printf("the result is %d",y);

return 0;}

The compiler tell me there is something wrong with the "pow",but I
don't know what's the wrong?

my compiler says:

testmod.cpp:8: warning: format ‘%d’ expects type ‘int*’, but argument 2
has type ‘long int*’
testmod.cpp:10: error: invalid operands of types ‘long int’ and ‘double’
to binary ‘operator%’
testmod.cpp:12: warning: format ‘%d’ expects type ‘int’, but argument 2
has type ‘long int’

It looks pretty much clear. Listen to your compiler. It's your friend.

Best wishes,

Zeppe

[Juha Nieminen]

questions wrote:

y=x%pow(10,3);

What's wrong with 1000?

[Kai-Uwe Bux]

Juha Nieminen wrote:

questions wrote:

> y=x%pow(10,3);

What's wrong with 1000?

Nit: 1000 does not occur in the above whereas 1000.0 does occur.
Best

Kai-Uwe Bux

[Sjouke Burry]

Kai-Uwe Bux wrote:

Juha Nieminen wrote:

>questions wrote:

>> y=x%pow(10,3);

What's wrong with 1000?

Nit: 1000 does not occur in the above whereas 1000.0 does occur.
Best

Kai-Uwe Bux

Another nit : Seeing the % sign suggests that the intent is to use 1000

[Juha Nieminen]

Kai-Uwe Bux wrote:

Juha Nieminen wrote:

>questions wrote:

>> y=x%pow(10,3);

What's wrong with 1000?

Nit: 1000 does not occur in the above whereas 1000.0 does occur.

But 1000 would work, whereas 1000.0 wouldn't.

[Kai-Uwe Bux]

Juha Nieminen wrote:

Kai-Uwe Bux wrote:

>Juha Nieminen wrote:

>>questions wrote:
y=x%pow(10,3);
What's wrong with 1000?

Nit: 1000 does not occur in the above whereas 1000.0 does occur.

But 1000 would work, whereas 1000.0 wouldn't.

Ah, now I understand your point: you meant to replace pow(10,3) by 1000.
Sorry for the noise.

Kai-Uwe Bux

[questions]

On 10ÔÂ28ÈÕ, ÏÂÎç7ʱ49·Ö, Kai-Uwe Bux <jkherci...@gmx .netwrote:

questions wrote:

# include <stdio.h>
# include <math.h>
int main()
{ long int x,y;

printf("enter an integer\n");
scanf("%d",&x);

y=x%pow(10,3);

[snip]

The compiler tell me there is something wrong with the "pow",but I
don't know what's the wrong?

pow() returns a floating point (in this case, I guess a double) and x is a
long int. That is not a valid pair of operand types for the % operator.

Best

Kai-Uwe Bux

thanks

[questions]

On 10ÔÂ28ÈÕ, ÏÂÎç7ʱ56·Ö, Zeppe
<ze...@remove.a ll.this.long.co mment.yahoo.itw rote:

questions wrote:

# include <stdio.h>
# include <math.h>
int main()
{ long int x,y;

printf("enter an integer\n");
scanf("%d",&x);

y=x%pow(10,3);

printf("the result is %d",y);

return 0;}

The compiler tell me there is something wrong with the "pow",but I
don't know what's the wrong?

my compiler says:

testmod.cpp:8: warning: format '%d' expects type 'int*', but argument 2
has type 'long int*'
testmod.cpp:10: error: invalid operands of types 'long int' and 'double'
to binary 'operator%'
testmod.cpp:12: warning: format '%d' expects type 'int', but argument 2
has type 'long int'

It looks pretty much clear. Listen to your compiler. It's your friend.

Best wishes,

Zeppe- Òþ²Ø±»ÒýÓÃÎÄ×Ö -

- ÏÔʾÒýÓõÄÎÄ×Ö -

thanks