C++ Entering numerals of an integer horizontally

[whodgson]

The following code does everthing required except that because each numeral of the integer has to be entered individually the numbers appear in a vertical column. Question: is there a way of entering the numbers so that they appear on the screen in one row each having been entered individually?

int main ()
{
string s;
char c;
int sum=0,n=0,a[6]={0},num=0;
cout<<"Enter a 6 digit integer \n";
int i=0, fact=100000;
while(i<6)
   {cin>>n;
   a[i]=n;
   num+=a[i]*fact;
   fact/=10;
   i++;
   if(i>5) break;      
  }
cout<<"The integer entered is: "<<num;
 
if(num%3==0)cout<<" and is divisible by 3 (= "<<num/3<<" )";
else cout<<" and is not divisible by 3";
 
for(int i;i<6;i++)
 sum+=a[i];
cout<<"\nSum of numerals is: "<<sum; 
if(sum%3==0)cout<<" and is divisible by 3\n";
else cout<<" and is not divisible by 3\n";
cout<<"\n";
system("pause");
return 0;
}

[whodgson]

i`ve modified the code to include this nexrInt() funct as follows:

int nextInt()
{ 
    int a[6]={0}; 
    char ch;
    int i=0;
    while (cin.get(ch))
       { 
        if (ch>= '0' && ch<='9')//next character is a digit
        a[i]=ch;
        i++;
        if(i>=6) break;
        }     
        for(int i=0;i<6;i++)
        cout<<a[i]<<" ";    
 }  

/*
Enter a 6 digit integer 123698
49 50 51 54 57 56 //this should be same as input but..........
*/
I'm obviously doing something wrong and illegal which is probably the while arguement.

[weaknessforcats]

It's the cin.get() echoing the enter key you used to enter the character.

Maybe you could try getchar().

[Simonius]

That'll still have to same problem.
A possible solution might be a variant of gotoxy but that'll be a bit cumbersome and you'll have to take into account some constraints.

[weaknessforcats]

You will have to stop echoing the enter key. I don't remember if there is a way to do that.

[oler1s]

You would have to play around with the console functions (assuming Windows) and change the way the console worked. And add in some additional code yourself. Have fun...

[mac11]

i`ve modified the code to include this nexrInt() funct as follows:

int nextInt()
{ 
    int a[6]={0}; 
    char ch;
    int i=0;
    while (cin.get(ch))
       { 
        if (ch>= '0' && ch<='9')//next character is a digit
        a[i]=ch;
        i++;
        if(i>=6) break;
        }     
        for(int i=0;i<6;i++)
        cout<<a[i]<<" ";    
 }  

/*
Enter a 6 digit integer 123698
49 50 51 54 57 56 //this should be same as input but..........
*/
I'm obviously doing something wrong and illegal which is probably the while arguement.

I don't know about the echoing thing, but your cramming a char into an int, thats not gonna work the way you want it to.
Say somebody puts in 9 - Ascii '9' isn't the same as int( 9 ) so when you do a[i] = ch your not storing 9, your storing the character '9', which has int value of 57.

Or maybe I'm confused...

[whodgson]

Thank you for your comments--wish i had your insights.
I couldn`t see the wood for the trees.
This is what i finally came up with which works fine.

int intManip(int n)
{ int m=0,sum=0;
 int a[6]= {0};  
 for (int i=0;i<6;i++)       
    { a[i]=n%10;
      m=n/10;
      n=m;
      sum+=a[i];
    }
     return sum;
 
}              

/*
Enter a 6 digit integer 369258

Sum of digits: 33
*/
Thank you all