Replacing a quote by a "\n" ...

[Choi]

Hi !

I wonder how I can replace a quote by a "\n" in a string.

For example my string is rrrrrrr'ttttttt and I want to obtain :

rrrrrrr
ttttttt

I tried the function find, but I don't know how to specify in its
parameters the quote character.

Thanks guys !

[=?UTF-8?B?RXJpayBXaWtzdHLDtm0=?=]

On 2007-11-27 17:54, Choi wrote:

Hi !

I wonder how I can replace a quote by a "\n" in a string.

For example my string is rrrrrrr'ttttttt and I want to obtain :

rrrrrrr
ttttttt

I tried the function find, but I don't know how to specify in its
parameters the quote character.

Does not "'" work?

--
Erik Wikström

[Eric Viloin]

Thanks for your answer, but it did not work ... Have you got another
idea Erik ?


On 27 nov, 18:07, Erik Wikström <Erik-wikst...@telia. comwrote:

On 2007-11-27 17:54, Choi wrote:

Hi !

I wonder how I can replace a quote by a "\n" in a string.

For example my string is rrrrrrr'ttttttt and I want to obtain :

rrrrrrr
ttttttt

I tried the function find, but I don't know how to specify in its
parameters the quote character.

Does not "'" work?

--
Erik Wikström

[=?iso-8859-1?b?VG9t4XMg0yBoyWlsaWRoZQ==?=]

Choi:

I wonder how I can replace a quote by a "\n" in a string.

For example my string is rrrrrrr'ttttttt and I want to obtain :

rrrrrrr
ttttttt

We call that an apostrophe in my part of the world (as opposed to an
inverted comma). I don't know if there's a char replacement function in
the Standard, but it's trivial to write:

void Replace(char *p,char const before,char const after)
{
assert(p); assert(before);

for (; p = strchr(p,before ); *p++ = after);
}

--
Tomás Ó hÉilidhe

[Default User]

Eric Viloin wrote:

Thanks for your answer, but it did not work ... Have you got another
idea Erik ?

Please don't top-post. Your replies belong following or interspersed
with properly trimmed quotes. See the majority of other posts in the
newsgroup, or the group FAQ list:
<http://www.parashift.c om/c++-faq-lite/how-to-post.html>

[peter koch]

On 27 Nov., 17:54, Choi <Evil.C...@gmai l.comwrote:

Hi !

I wonder how I can replace a quote by a "\n" in a string.

For example my string is rrrrrrr'ttttttt and I want to obtain :

rrrrrrr
ttttttt

I tried the function find, but I don't know how to specify in its
parameters the quote character.

Thanks guys !

How about using std::replace? I wonder why noone have suggested that
before?

std::replace(st r.begin(),str.e nd(),'\'','\n') ;

/Peter

[James Kanze]

On Nov 27, 6:07 pm, Erik Wikström <Erik-wikst...@telia. comwrote:

On 2007-11-27 17:54, Choi wrote:

I wonder how I can replace a quote by a "\n" in a string.

For example my string is rrrrrrr'ttttttt and I want to obtain :

rrrrrrr
ttttttt

I tried the function find, but I don't know how to specify in its
parameters the quote character.

Does not "'" work?

std::find, on a string, will want something that is a char, or
convertible to a char. "'" is an array.

What he needs is '\''. (More generally, I'd write "\'" as well.
For reasons of orthorgonality, I always escape both " and ',
both in strings and in character constants.)

--
James Kanze (GABI Software) email:ja******* **@gmail.com
Conseils en informatique orientée objet/
Beratung in objektorientier ter Datenverarbeitu ng
9 place Sémard, 78210 St.-Cyr-l'École, France, [phone]

[James Kanze]

On Nov 27, 6:25 pm, "Alf P. Steinbach" <[e-mail] wrote:

[...]

Again, re optimization: std::string is not well suited for string
handling. It's not even well suited for passing strings around,
technically. But it's standard, and that's one great plus point, so
great that std::string is the default choice for that.

As a summary of std::string, this is actually pretty good. But
to be fair: std::string does define both the copy constructor
and an assignment operator---what else do you need for passing
strings around?

However, if optimization is required, consider some other
string class first, instead of fiddling with std::string-based
code.

More generally: don't use fundamental library types as part of
your application level abstraction. If your abstraction deals
with text, for example, don't use std::string for that text; use
some user defined class. A class which almost certainly uses
std::string in its implementation, at least until the profiler
says otherwise, but a class which defines very exactly the
interface you need. This is a good general rule, as it keeps
your options open. Use std::string directly, or a typedef to
std::string, and you're locked in; use a user defined class with
a narrower interface, and you can change the implementation in
any way that conforms to the interface.

--
James Kanze (GABI Software) email:ja******* **@gmail.com
Conseils en informatique orientée objet/
Beratung in objektorientier ter Datenverarbeitu ng
9 place Sémard, 78210 St.-Cyr-l'École, France, [phone]

[James Kanze]

On Nov 28, 4:01 pm, "Alf P. Steinbach" <[e-mail] wrote:

* James Kanze:

On Nov 27, 6:25 pm, "Alf P. Steinbach" <[e-mail] wrote:

[...]

Again, re optimization: std::string is not well suited for string
handling. It's not even well suited for passing strings around,
technically. But it's standard, and that's one great plus point, so
great that std::string is the default choice for that.

As a summary of std::string, this is actually pretty good. But
to be fair: std::string does define both the copy constructor
and an assignment operator---what else do you need for passing
strings around?

Efficiency, safety and possibly more information.

Most of these really concern creation of strings, rather than
just "passing them around". One point, however:

[...]

- being able to avoid copying for forming substrings

This is a deficiency in most current implementations , but is not
necessary according to the standard. An implementation more or
less like that of Java could be used, in which you don't need a
copy for substrings.

[...]

- e.g. character set.

Achieving this "normality" (what one naturally expect of a
string type, unless exposed to std::string for too long...)
needs a new string interface.

Having had to deal with "bad" string types in other languages
(in the past), I don't naturally expect very much:-). (Or is
that I naturally don't expect very much?)

The lack of information concerning the encoding (character set)
is an awkward problem. It is one, however, that we're used to
dealing with: it affects a lot of other types as well. (Is that
double meters, or millimeters? Is that Decimal Euros, or
Pounds?)

In the end, I think we need both: a "raw" type, for cases where
the "units" are implicitly known, and a more complete type which
associates a unit with each value. (Note that I'm not talking
here about typing issues, where the user assigns a double
representing meters to a variable containing the weight. That's
a different problem---which probably needs solving as well.)

--
James Kanze (GABI Software) email:ja******* **@gmail.com
Conseils en informatique orientée objet/
Beratung in objektorientier ter Datenverarbeitu ng
9 place Sémard, 78210 St.-Cyr-l'École, France, [phone]