Dear all,
consider the following program
#include<stdio. h>
#include<unistd .h>
main()
{
int pid,*i,j;
i = &j;
*i= 10;
pid = fork();
if(pid == 0)
{
printf("\n address of i = %p",i);
printf("\n initially i value in child = %d",*i);
*i = *i +10;
printf("\n after incrementation i value in child = %d",*i);
puts("Child terminated...." );
}
else
{
wait( (int*) 0);
printf("\n address of i = %p",i);
printf("\n value of i in parent = %d",*i);
}
i am getting o/p as:-
address of i = 0xbfe6c01c
initially i value in child = 10
after incrementation i value in child = 20
Child terminated....
address of i = 0xbfe6c01c
value of i in parent = 10
the address of i is same in both parent and child process but
the change made in child process is not reflected in the
parent process why ?
Nov 25 '07
33  1821 
"Marco Manfredini" <ok**********@p hoyd.netwrote in message
news:fi******** **@aioe.org...
I'm just a curios visitor, bewildered by the customs of the local natives.
It's simple: if it's not ANSI/ISO C or K&R C, it's considered off-topic
here, though most people who will give that answer also provide a reference
to a group where the question is likely to be on-topic. For POSIX-y things,
e.g. fork(), that's usually comp.unix.progr ammer.
Anyway, I could point out that this question *is* on-topic, because
the OP found an external library function which seems to undermine C's
memory model *completely*, an inexplicable
behavior.
It's only inexplicable if that external library function is in conforming
ISO C. Of course, since ISO C does not permit fork() to do what it does,
that's obviously not correct. Specifically, ISO C does not acknowledge that
multiple programs can be running at the same time, therefore it has _no_
model of how the behavior of one program can (or can't) affect the behavior
of another running concurrently.
<OT>However, I find fork() an interesting example, because the program
before the call and the two programs after the call appear to be conforming;
they simply have two independent instances of the ISO C memory model,
initially inherited from the single initial instance but potentially
diverging. Without other non-portable interactions (e.g. IPC), they do not
interact in any way that is detectable by a conforming program.</OT>
S
--
Stephen Sprunk "God does not play dice." --Albert Einstein
CCIE #3723 "God is an inveterate gambler, and He throws the
K5SSS dice at every possible opportunity." --Stephen Hawking
<so**********@g mail.comwrote in message
news:7f******** *************** ***********@e23 g2000prf.google groups.com...
#include<unistd .h>
<unistd.hisn' t ISO C; it's probably POSIX, which means you'll get better
answers in comp.unix.progr ammer.
i am getting o/p as:-
address of i = 0xbfe6c01c
initially i value in child = 10
after incrementation i value in child = 20
Child terminated....
address of i = 0xbfe6c01c
value of i in parent = 10
the address of i is same in both parent and child process but
the change made in child process is not reflected in the
parent process why ?
<OT>
The short answer is that the parent and child each have their own copy of i
after fork() returns. That means you can change one but the other will stay
the same. On most modern machines, they will have the same virtual address
(what you see), but that's just a trick of the OS; they will have different
physical addresses*. You can't compare pointers from different processes,
since they're in different virtual address spaces.
</OT>
S
* Well, at least after one is modified. Some OSes use "copy on write" to
make forking faster. That's a minor detail; unless you're a kernel hacker,
it's fine to act as if all objects are duplicated at the time of forking.
--
Stephen Sprunk "God does not play dice." --Albert Einstein
CCIE #3723 "God is an inveterate gambler, and He throws the
K5SSS dice at every possible opportunity." --Stephen Hawking
In article <sl************ ********@snail. stack.nl>,
Willem <wi****@stack.n lwrote:
>Kenny wrote:
) In article <sl************ ********@snail. stack.nl>,
) Willem <wi****@stack.n lwrote:
)>Marco wrote:
)>) Then please give an implementation of fork() in ISO-C.
)>
)>Why does the implementation have to be in ISO-C ?
)
) If it isn't, we can't talk about it here.
The original claim was that fork() somehow *broke* standard-C.
I don't see how having to implement it in C has anything to do with it.
Then you haven't been around here long enough. Stick around, kid,
you'll get it soon enough.
Stephen Sprunk wrote:
Of course, since ISO C does not permit fork() to do what it
does,
We don't know what the OP's fork() usually does. We only know what it
did in this specific instance.
that's obviously not correct. Specifically, ISO C does not
acknowledge that multiple programs can be running at the same time,
therefore it has _no_ model of how the behavior of one program can (or
can't) affect the behavior of another running concurrently.
From the description of the OP is does not follow, that two programs ran
at the same time. Also, ISO-C allows the communication with a command
processor via "system" and leaves the details to the implementation
>
<OT>However, I find fork() an interesting example, because the program
before the call and the two programs after the call appear to be
conforming; they simply have two independent instances of the ISO C
memory model, initially inherited from the single initial instance but
potentially
diverging. Without other non-portable interactions (e.g. IPC), they
do not interact in any way that is detectable by a conforming
program.</OT>
The most interesing thing is, that in fact I *can* write a ISO-C program
which *may* show the observed behavior. Put this into a file named
"unistd.h":
/* implementation requirements according to 7.40.2.6/2:
works only if
- system("./f") starts the same program which calls fork()
- system("./f") does not return until said program terminates
- system("./f") continues the calling program in a conforming manner
- the file "state" is available for reading to the program which
system("./f") starts.
*/
int get_state()
{
int v;
FILE *p=fopen("state ","r");
if (p==0) return 0;
v=fgetc(p);
fclose(p);
return v;
}
void set_state(int c)
{
FILE *p=fopen("state ","w");
fputc(c,p);
fclose(p);
}
int fork()
{
FILE *p=0;
int pid;
int parent=0;
if (get_state()!=0 ) return 0;
set_state(1);
system("./f");
set_state(0);
return 1;
}
int wait(void *q)
{
}
--
IYesNo yes=YesNoFactor y.getFactoryIns tance().YES;
yes.getDescript ion().equals(ar ray[0].toUpperCase()) ;
Marco Manfredini wrote:
Kelsey Bjarnason wrote:
>Marco Manfredini wrote:
>>I'm just a curios visitor, bewildered by the customs of the local
natives. Anyway, I could point out that this question *is* on-topic,
because the OP found an external library function which seems to
undermine C's memory model *completely*, an inexplicable behavior.
Not really.
[...]
Then please give an implementation of fork() in ISO-C.
There is no such thing. fork() is not defined in ISO-C. If it was
defined it would not be implementable within the language (assuming
the usual meaning).
--
Chuck F (cbfalconer at maineline dot net)
<http://cbfalconer.home .att.net>
Try the download section.
--
Posted via a free Usenet account from http://www.teranews.com
In article <47************ ***@yahoo.com>,
CBFalconer <cb********@mai neline.netwrote :
>Marco Manfredini wrote:
>Kelsey Bjarnason wrote:
>>Marco Manfredini wrote:
I'm just a curios visitor, bewildered by the customs of the local
natives. Anyway, I could point out that this question *is* on-topic,
because the OP found an external library function which seems to
undermine C's memory model *completely*, an inexplicable behavior.
Not really.
[...]
Then please give an implementation of fork() in ISO-C.
There is no such thing. fork() is not defined in ISO-C. If it was
defined it would not be implementable within the language (assuming
the usual meaning).
No, no, no. You've got it all wrong. As far as anyone in this NG is
concerned, the following is a perfectly good implementaion of "fork()"
and is absolutely to be considered as good or better than any other
implementation of "fork()":
int fork(void) { puts("Try a spoon instead!"); }
On Nov 27, 10:54 pm, gaze...@xmissio n.xmission.com (Kenny McCormack)
wrote:
In article <474C85F5.5D82D ...@yahoo.com>,
CBFalconer <cbfalco...@mai neline.netwrote :
Marco Manfredini wrote:
Then please give an implementation of fork() in ISO-C.
There is no such thing. fork() is not defined in ISO-C. If it was
defined it would not be implementable within the language (assuming
the usual meaning).
No, no, no. You've got it all wrong. As far as anyone in this NG is
concerned, the following is a perfectly good implementaion of "fork()"
and is absolutely to be considered as good or better than any other
implementation of "fork()":
int fork(void) { puts("Try a spoon instead!"); }
This invokes undefined behavior if the caller attempts to use the
return value of a call to fork().
On Tue, 27 Nov 2007 15:08:09 -0800, Francine.Neary wrote:
On Nov 27, 10:54 pm, gaze...@xmissio n.xmission.com (Kenny McCormack)
wrote:
>int fork(void) { puts("Try a spoon instead!"); }
This invokes undefined behavior if the caller attempts to use the return
value of a call to fork().
No, it is the attempt to use the return value of a call to fork() that
invokes undefined behaviour. "This", the function, is entirely valid.
In article <81************ *************** *******@w34g200 0hsg.googlegrou ps.com>,
<Fr************ @googlemail.com wrote:
....
>This invokes undefined behavior if the caller attempts to use the
return value of a call to fork().
Fixing this is left as an exercise for the reader. I'm sure you'll be
up to the task. Fr************@ googlemail.com wrote:
gaze...@xmissio n.xmission.com (Kenny McCormack) wrote:
>CBFalconer <cbfalco...@mai neline.netwrote :
>>Marco Manfredini wrote:
Then please give an implementation of fork() in ISO-C.
>>There is no such thing. fork() is not defined in ISO-C. If it
was defined it would not be implementable within the language
(assuming the usual meaning).
No, no, no. You've got it all wrong. As far as anyone in this
NG is concerned, the following is a perfectly good implementaion
of "fork()" and is absolutely to be considered as good or better
than any other implementation of "fork()":
int fork(void) { puts("Try a spoon instead!"); }
This invokes undefined behavior if the caller attempts to use the
return value of a call to fork().
Since puts always returns a non-zero int, it is easily corrected.
--
Chuck F (cbfalconer at maineline dot net)
<http://cbfalconer.home .att.net>
Try the download section.
--
Posted via a free Usenet account from http://www.teranews.com This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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