Shouldn't this compile?
#include <vector>
#include <algorithm>
#include <functional>
int main()
{
using namespace std;
vector<int> vec(1000, 10);
vector<int>::it erator p= find( vec.begin(), vec.end(),
bind2nd(less<in t>(), 11) );
}
--
Ioannis Vranos http://www23.brinkster.com/noicys 4 2635
Ioannis Vranos wrote: Shouldn't this compile?
#include <vector> #include <algorithm> #include <functional>
int main() { using namespace std;
vector<int> vec(1000, 10);
vector<int>::it erator p= find( vec.begin(), vec.end(), bind2nd(less<in t>(), 11) ); }
You want to use std::find_if() instead of std::find(). The third paramater to std::find() is
expected to be the value you're looking for, where as std::find_if()' s third paramater is a binary
predicate.
Kurt Stutsman wrote: Ioannis Vranos wrote:
Shouldn't this compile?
#include <vector> #include <algorithm> #include <functional>
int main() { using namespace std;
vector<int> vec(1000, 10);
vector<int>::it erator p= find( vec.begin(), vec.end(), bind2nd(less<in t>(), 11) ); } You want to use std::find_if() instead of std::find(). The third paramater to std::find() is expected to be the value you're looking for, where as std::find_if()' s third paramater is a binary predicate.
Make that a Unary Predicate not a Binary Predicate. Sorry.
You are using a predicate, you need to use find_if rather than find.
--
Imanpreet Singh Arora
Ioannis Vranos wrote: Shouldn't this compile?
No.
vector<int>::it erator p= find( vec.begin(), vec.end(), bind2nd(less<in t>(), 11) );
std::find looks for a particular value. To use a predicate, you want to
call std::find_if.
--
Later,
Jerry.
The universe is a figment of its own imagination. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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