how can i pick up largest no from 5 rows by 5 column matrix????
38  2459 
<be************ **@yahoo.co.ins chrieb im Newsbeitrag
news:11******** **************@ x35g2000prf.goo glegroups.com.. .
how can i pick up largest no from 5 rows by 5 column matrix????
By copmaring the first with the send, then the larted of that comparisn with
the 3rd, the larger of that with the 4th and so on until the 25th
Bye, Jojo
On 6 Jun, 10:50, bele_harshad2.. .@yahoo.co.in wrote:
how can i pick up largest no from 5 rows by 5 column matrix????
Step 1. Sort the columns of each row into ascending order.
Step 2. Sort the rows into ascending order using the last column as
the key.
Step 3. Pick the last column of the last row. ma**********@po box.com said:
On 6 Jun, 10:50, bele_harshad2.. .@yahoo.co.in wrote:
>how can i pick up largest no from 5 rows by 5 column matrix????
Step 1. Sort the columns of each row into ascending order.
Step 2. Sort the rows into ascending order using the last column as
the key.
Step 3. Pick the last column of the last row.
I'm sure we can do better than O(c log c + r log r). Perhaps we should
specify a particular sort. That can get us right up to O(c^2 + r^2)
without any major effort. But can anyone find an exponential-time
algorithm?
--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999 http://www.cpax.org.uk
email: rjh at the above domain, - www.
On 6 Jun, 11:29, Richard Heathfield <r...@see.sig.i nvalidwrote:
mark_blue...@po box.com said:
On 6 Jun, 10:50, bele_harshad2.. .@yahoo.co.in wrote:
how can i pick up largest no from 5 rows by 5 column matrix????
Step 1. Sort the columns of each row into ascending order.
Step 2. Sort the rows into ascending order using the last column as
the key.
Step 3. Pick the last column of the last row.
I'm sure we can do better than O(c log c + r log r). Perhaps we should
specify a particular sort. That can get us right up to O(c^2 + r^2)
without any major effort. But can anyone find an exponential-time
algorithm?
There's a big problem here, though - how can we sort anything when we
don't know how to tell whether one thing is larger than another?
<ma**********@p obox.comschrieb im Newsbeitrag
news:11******** *************@o 5g2000hsb.googl egroups.com...
On 6 Jun, 11:29, Richard Heathfield <r...@see.sig.i nvalidwrote:
> mark_blue...@po box.com said:
On 6 Jun, 10:50, bele_harshad2.. .@yahoo.co.in wrote:
how can i pick up largest no from 5 rows by 5 column matrix????
Step 1. Sort the columns of each row into ascending order.
Step 2. Sort the rows into ascending order using the last column as
the key.
Step 3. Pick the last column of the last row.
I'm sure we can do better than O(c log c + r log r). Perhaps we should
specify a particular sort. That can get us right up to O(c^2 + r^2)
without any major effort. But can anyone find an exponential-time
algorithm?
There's a big problem here, though - how can we sort anything when we
don't know how to tell whether one thing is larger than another?
Hmm, the OP talked abut 'no' wich I assume to mean 'number', so it probably
is some integral or floating point number, which are fairly easy to find the
larger.
Bye, Jojo
On 6 Jun, 12:25, "Joachim Schmitz" <nospam.j...@sc hmitz-digital.de>
wrote:
<mark_blue...@p obox.comschrieb im Newsbeitragnews :11************ *********@o5g20 00hsb.googlegro ups.com...
On 6 Jun, 11:29, Richard Heathfield <r...@see.sig.i nvalidwrote:
mark_blue...@po box.com said:
On 6 Jun, 10:50, bele_harshad2.. .@yahoo.co.in wrote:
how can i pick up largest no from 5 rows by 5 column matrix????
Step 1. Sort the columns of each row into ascending order.
Step 2. Sort the rows into ascending order using the last column as
the key.
Step 3. Pick the last column of the last row.
I'm sure we can do better than O(c log c + r log r). Perhaps we should
specify a particular sort. That can get us right up to O(c^2 + r^2)
without any major effort. But can anyone find an exponential-time
algorithm?
There's a big problem here, though - how can we sort anything when we
don't know how to tell whether one thing is larger than another?
Hmm, the OP talked abut 'no' wich I assume to mean 'number', so it probably
is some integral or floating point number, which are fairly easy to find the
larger.
Finding the largest value in some set is a trivial extension of
finding which of two values is the larger - if the OP wanted us to
write code to do the former, it implies they probably can't do the
latter...
<ma**********@p obox.comschrieb im Newsbeitrag
news:11******** *************@p 47g2000hsd.goog legroups.com...
On 6 Jun, 12:25, "Joachim Schmitz" <nospam.j...@sc hmitz-digital.de>
wrote:
><mark_blue...@ pobox.comschrie b im
Newsbeitragnew s:11*********** **********@o5g2 000hsb.googlegr oups.com...
On 6 Jun, 11:29, Richard Heathfield <r...@see.sig.i nvalidwrote:
mark_blue...@po box.com said:
On 6 Jun, 10:50, bele_harshad2.. .@yahoo.co.in wrote:
how can i pick up largest no from 5 rows by 5 column matrix????
Step 1. Sort the columns of each row into ascending order.
Step 2. Sort the rows into ascending order using the last column as
the key.
Step 3. Pick the last column of the last row.
>I'm sure we can do better than O(c log c + r log r). Perhaps we should
specify a particular sort. That can get us right up to O(c^2 + r^2)
without any major effort. But can anyone find an exponential-time
algorithm?
There's a big problem here, though - how can we sort anything when we
don't know how to tell whether one thing is larger than another?
Hmm, the OP talked abut 'no' wich I assume to mean 'number', so it
probably
is some integral or floating point number, which are fairly easy to find
the
larger.
Finding the largest value in some set is a trivial extension of
finding which of two values is the larger - if the OP wanted us to
write code to do the former, it implies they probably can't do the
latter...
To me it sounds like a homework assignment...
Joachim Schmitz wrote:
<ma**********@p obox.comschrieb im Newsbeitrag
.... snip ...
>>
Finding the largest value in some set is a trivial extension of
finding which of two values is the larger - if the OP wanted us
to write code to do the former, it implies they probably can't
do the latter...
To me it sounds like a homework assignment...
No! I can't imagine a student trying to pull such a scurvy trick.
Couldn't possibly be true!
--
<http://www.cs.auckland .ac.nz/~pgut001/pubs/vista_cost.txt>
<http://www.securityfoc us.com/columnists/423>
<http://www.aaxnet.com/editor/edit043.html>
<http://kadaitcha.cx/vista/dogsbreakfast/index.html>
cbfalconer at maineline dot net
--
Posted via a free Usenet account from http://www.teranews.com ma**********@po box.com wrote:
Richard Heathfield <r...@see.sig.i nvalidwrote:
> mark_blue...@po box.com said:
>>On 6 Jun, 10:50, bele_harshad2.. .@yahoo.co.in wrote:
how can i pick up largest no from 5 rows by 5 column matrix????
>>Step 1. Sort the columns of each row into ascending order.
Step 2. Sort the rows into ascending order using the last column as
the key.
Step 3. Pick the last column of the last row.
I'm sure we can do better than O(c log c + r log r). Perhaps we
should specify a particular sort. That can get us right up to
O(c^2 + r^2) without any major effort. But can anyone find an
exponential-time algorithm?
There's a big problem here, though - how can we sort anything when
we don't know how to tell whether one thing is larger than another?
You apparantly totally missed the humor involved in RH's post.
--
<http://www.cs.auckland .ac.nz/~pgut001/pubs/vista_cost.txt>
<http://www.securityfoc us.com/columnists/423>
<http://www.aaxnet.com/editor/edit043.html>
<http://kadaitcha.cx/vista/dogsbreakfast/index.html>
cbfalconer at maineline dot net
--
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