MDR  14
New Member
Hello
I have three "for" loops, two nested into the outer one and they depend on each other, like this:
for (x=1; x<100; x++)
{
....
for (i=1; i<10; i++)
{....}
for (j=1; j<10; j++)
{...}
...
}
In the i loop we obtain a result that must be introduced in the j loop. I thought that it would do firstly the loop for i and then the loop for j, but it seems like if it were doing both loops at the same time, because when we cancell the j loop the result for the i one is correct, but with both working simoultaneously the result for i is perturbed by the second loop. Am I correct?
Thak you very much for your time and for your help!
4 1716 
Hello
I have three "for" loops, two nested into the outer one and they depend on each other, like this:
for (x=1; x<100; x++)
{
....
for (i=1; i<10; i++)
{....}
for (j=1; j<10; j++)
{...}
...
}
In the i loop we obtain a result that must be introduced in the j loop. I thought that it would do firstly the loop for i and then the loop for j, but it seems like if it were doing both loops at the same time, because when we cancell the j loop the result for the i one is correct, but with both working simoultaneously the result for i is perturbed by the second loop. Am I correct?
Thak you very much for your time and for your help!
The braces {} should tell you how your loops will behave.
MDR 14
New Member
The braces {} should tell you how your loops will behave.
ok, thanks but this doesn'tanswer my question.
My question is, which loop does it run before, "i" or "j", or they run simoultaneousll y? because they are at the same level within de "x" loop.
ok, thanks but this doesn'tanswer my question.
My question is, which loop does it run before, "i" or "j", or they run simoultaneousll y? because they are at the same level within de "x" loop.
It runs whichever comes first. A for runs everything within its braces so it won't go to the second for loop until the first is finished.
ok, thanks but this doesn'tanswer my question.
My question is, which loop does it run before, "i" or "j", or they run simoultaneousll y? because they are at the same level within de "x" loop.
Think about the answer I gave you again. Maybe it really does answer your question ...
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