Is there a way to pass the variable argument list from one function to
another? For example:
void my_func(const char *fmt, ...) {
char str[256];
snprintf(str, 255, fmt, ...);
}
I know that probably won't work, but you get my meaning.
Thanks!
--
-Rob Hoelz 9 2414
you could use a macro, if that solves your purpose
#define my_func(fmt,... ) snprintf(str, 255, fmt, ##__VA_ARGS__)
-Mujoo
Rob Hoelz wrote:
Is there a way to pass the variable argument list from one function to
another? For example:
void my_func(const char *fmt, ...) {
char str[256];
snprintf(str, 255, fmt, ...);
}
I know that probably won't work, but you get my meaning.
Thanks!
--
-Rob Hoelz
Ashwani wrote:
you could use a macro, if that solves your purpose
#define my_func(fmt,... ) snprintf(str, 255, fmt, ##__VA_ARGS__)
1) Please don't top post.
2) I don't believe that feature is standard - IIRC it's a gcc extension.
Rob Hoelz wrote:
Is there a way to pass the variable argument list from one function to
another? For example:
void my_func(const char *fmt, ...) {
char str[256];
snprintf(str, 255, fmt, ...);
}
I know that probably won't work, but you get my meaning.
The FAQ is available online. The part you need is question 15.12 - http://c-faq.com/varargs/handoff.html
Ashwani wrote:
Rob Hoelz wrote:
>Is there a way to pass the variable argument list from one function to another? For example:
void my_func(const char *fmt, ...) { char str[256]; snprintf(str, 255, fmt, ...); }
I know that probably won't work, but you get my meaning.
you could use a macro, if that solves your purpose
#define my_func(fmt,... ) snprintf(str, 255, fmt, ##__VA_ARGS__)
Please don't top-post. I fixed this one. Read the following links.
Variadic macros require a C99 compliant system. Most aren't.
--
Some informative links:
<news:news.anno unce.newusers
<http://www.geocities.c om/nnqweb/>
<http://www.catb.org/~esr/faqs/smart-questions.html>
<http://www.caliburn.nl/topposting.html >
<http://www.netmeister. org/news/learn2quote.htm l>
<http://cfaj.freeshell. org/google/>
CBFalconer <cb********@yah oo.comwrote:
Ashwani wrote:
Rob Hoelz wrote:
Is there a way to pass the variable argument list from one
function to another? For example:
void my_func(const char *fmt, ...) {
char str[256];
snprintf(str, 255, fmt, ...);
}
I know that probably won't work, but you get my meaning.
you could use a macro, if that solves your purpose
#define my_func(fmt,... ) snprintf(str, 255, fmt, ##__VA_ARGS__)
Please don't top-post. I fixed this one. Read the following links.
Variadic macros require a C99 compliant system. Most aren't.
Crap. Two questions following this up:
1) I assume there's a statement (like __cplusplus) that I can check to
see if the compiler's C99 compliant. Does anyone happen to know what
it is?
2) Is there a C89 workaround I can use for non-C99 compilers?
Thanks again!
--
-Rob Hoelz
2006-12-21 <20061221004807 .537ebc65@TheRi ng>,
Rob Hoelz wrote:
Is there a way to pass the variable argument list from one function to
another? For example:
void my_func(const char *fmt, ...) {
char str[256];
snprintf(str, 255, fmt, ...); }
void my_func(const char *fmt, ...) {
char str[256];
va_list ap;
va_start(ap,fmt );
vsnprintf(str,2 55,fmt,va_list) ;
va_end(ap);
} ma**********@po box.com writes:
Ashwani wrote:
>you could use a macro, if that solves your purpose
#define my_func(fmt,... ) snprintf(str, 255, fmt, ##__VA_ARGS__)
1) Please don't top post.
2) I don't believe that feature is standard - IIRC it's a gcc extension.
Both C99 and gcc support variadic macros, but with differing syntax
and semantics. (I don't remember the details.)
--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.
Rob Hoelz <ho***@wisc.edu writes:
CBFalconer <cb********@yah oo.comwrote:
>Ashwani wrote:
Rob Hoelz wrote:
[...]
>Is there a way to pass the variable argument list from one function to another? For example:
void my_func(const char *fmt, ...) { char str[256]; snprintf(str, 255, fmt, ...); }
I know that probably won't work, but you get my meaning.
[snip]
1) I assume there's a statement (like __cplusplus) that I can check to
see if the compiler's C99 compliant. Does anyone happen to know what
it is?
You can test for __STDC_VERSION_ _ >= 199901L.
But beware: "gcc -std=c99", for example, defines __STDC_VERSION_ _ as
199901L, but it doesn't fully implement the C99 standard.)
Most current compilers implement a much simpler test, though:
#if 0
8-)}
2) Is there a C89 workaround I can use for non-C99 compilers?
Take a look at vfprintf() and vsprintf().
--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.
Rob Hoelz wrote:
CBFalconer <cb********@yah oo.comwrote:
>Ashwani wrote:
>>Rob Hoelz wrote:
Is there a way to pass the variable argument list from one function to another? For example:
void my_func(const char *fmt, ...) { char str[256]; snprintf(str, 255, fmt, ...); }
I know that probably won't work, but you get my meaning.
you could use a macro, if that solves your purpose
#define my_func(fmt,... ) snprintf(str, 255, fmt, ##__VA_ARGS__)
.... snip ...
>> Variadic macros require a C99 compliant system. Most aren't.
Crap. Two questions following this up:
1) I assume there's a statement (like __cplusplus) that I can check
to see if the compiler's C99 compliant. Does anyone happen to know
what it is?
#if defined(__STDC_ _) && (__STDC_VERSION __ >= 199901L)
/* This section for C99 up */
#else
/* This section for others */
#endif
>
2) Is there a C89 workaround I can use for non-C99 compilers?
Use gcc. Read its docs.
--
Chuck F (cbfalconer at maineline dot net)
Available for consulting/temporary embedded and systems.
<http://cbfalconer.home .att.net> This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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