can anyone help in correcting this code?

[vv1]

Write a C program for reading in a message string (with no blanks)
and decoding the message. Store the decoded message in another string
called outString. After decoding is complete, print the decoded
message. Use the following key for decoding.Conver t any numeric
characters in input (0-9) to a space in the output. Upper case letters
in input/message string are decoded by adding 19 to their
ASCII/Integer value. Lower case characters are decoded by adding 9 to
their ASCII value. All other characters (special) are skipped. Count
numeric characters in the input. They become spaces in the
decoded/output string. You also need to count upper and lower case
characters in the input string. At the end print the count of spaces
in the output ( number of numeric characters in input). Also
calculate and print percentage of spaces (blanks) in the OUTPUT
string.

I have written the following code but i m not able to get the decoded
string. rest everything is okie.
please help in correcting that.

I would really appreciate the help.

#include <stdio.h>
#include <stdlib.h>

// Code for function decodeUpper(... .)
char decodeUpper(cha r in_c1)
{char c1;
if (in_c1 + 19 'Z' )
{c1 = in_c1 - 'Z' + 'A' - 1 ;}
else
c1 = in_c1 + 19;
return(c1);}

// Code for function decodeLower(... .)
char decodeLower(uns igned char in_c2)
{char c2;
if (in_c2 + 9 'z')
c2 = in_c2 - 'z' + 'a' - 1 ;
else
c2 = in_c2 + 9;
return c2;}

// Code for function percent(....)
float percent(int m, int n)
{float i;
i = (float)m/n;
}

// Function main begins here.

main ()
{
// In C, string is just an array of characters terminated by '\0'.

char inString[100];
char outString[100];
int i, j;
char c;
int up_count = 0;
int lo_count = 0;
int num_count = 0;
int length;
char p;
// Read input.

printf("Enter a message string with no blanks.\n",inSt ring);
scanf("%s",inSt ring);

// Write a loop for decoding characters of inString.
for(i=0,j=0; inString[i] != '\0'; i++)
{c = inString[i];
if ( c >= 'A' && c <= 'Z' )
{ up_count++;
outString[j] =decodeUpper(c) ;
j++;}
else{ if ( c >= 'a' && c <= 'z' )
{lo_count++;
outString[j] = decodeLower(c);
j++;}
else {if ( c >= '0' && c <= '9' )
{num_count++;
outString[j] = ' ';
j++;}}}
}
length = num_count + up_count + lo_count;

// Print decoded string.
printf("Decoded Message is :%s\n", outString);

//Print num_count (count of spaces), length of decoded

printf("Length Of Decoded Message is %d\n",length);

printf("Count Of Blanks in Decoded Message is %d \n",num_count );

//Calculate % by calling function percent and print.

printf("%f percent of output is blank\n",100 * percent(num_cou nt ,
length));
}

[T.M. Sommers]

vv1 wrote:

Write a C program for reading in a message string (with no blanks)
and decoding the message. Store the decoded message in another string
called outString. After decoding is complete, print the decoded
message. Use the following key for decoding.Conver t any numeric
characters in input (0-9) to a space in the output. Upper case letters
in input/message string are decoded by adding 19 to their
ASCII/Integer value. Lower case characters are decoded by adding 9 to
their ASCII value. All other characters (special) are skipped. Count
numeric characters in the input. They become spaces in the
decoded/output string. You also need to count upper and lower case
characters in the input string. At the end print the count of spaces
in the output ( number of numeric characters in input). Also
calculate and print percentage of spaces (blanks) in the OUTPUT
string.

I have written the following code but i m not able to get the decoded
string. rest everything is okie.
please help in correcting that.

I would really appreciate the help.

#include <stdio.h>
#include <stdlib.h>

// Code for function decodeUpper(... .)
char decodeUpper(cha r in_c1)
{char c1;
if (in_c1 + 19 'Z' )
{c1 = in_c1 - 'Z' + 'A' - 1 ;}
else
c1 = in_c1 + 19;
return(c1);}

// Code for function decodeLower(... .)
char decodeLower(uns igned char in_c2)
{char c2;
if (in_c2 + 9 'z')
c2 = in_c2 - 'z' + 'a' - 1 ;
else
c2 = in_c2 + 9;
return c2;}

These two functions don't seem to satisfy the requirements given
above. Assuming you were given extra information, and assuming
that you were told that the addition is to wrap around, then your
implementation does not work. For the upper case you want
something like:

c1 = in_c1 + 19;
if ( c1 'Z' )
c1 -= 26;

// Code for function percent(....)
float percent(int m, int n)
{float i;
i = (float)m/n;
}

This function returns nothing, but is declared as returning a
float. If you have the function return i, then it is misnamed.

// Function main begins here.

main ()

int main(void)

{
// In C, string is just an array of characters terminated by '\0'.

char inString[100];
char outString[100];
int i, j;
char c;
int up_count = 0;
int lo_count = 0;
int num_count = 0;
int length;
char p;

p is not used.

// Read input.

printf("Enter a message string with no blanks.\n",inSt ring);

The argument instring does not belong here.

scanf("%s",inSt ring);

What happens if the user types in a string longer than can be
held in inString?

// Write a loop for decoding characters of inString.
for(i=0,j=0; inString[i] != '\0'; i++)
{c = inString[i];
if ( c >= 'A' && c <= 'Z' )

You should include ctype.h and use isupper(), islower(), and
isdigit() instead of making your own tests.

{ up_count++;
outString[j] =decodeUpper(c) ;
j++;}
else{ if ( c >= 'a' && c <= 'z' )

You can say 'else if' here, which will keep all the tests at the
same level.

{lo_count++;
outString[j] = decodeLower(c);
j++;}
else {if ( c >= '0' && c <= '9' )
{num_count++;
outString[j] = ' ';
j++;}}}
}

outString needs a nul at the end.

length = num_count + up_count + lo_count;

// Print decoded string.

This comment is redundant.

printf("Decoded Message is :%s\n", outString);

//Print num_count (count of spaces), length of decoded

printf("Length Of Decoded Message is %d\n",length);

printf("Count Of Blanks in Decoded Message is %d \n",num_count );

You might want to rename the variable num_count so that it more
accurately reflects its use.

>
//Calculate % by calling function percent and print.

printf("%f percent of output is blank\n",100 * percent(num_cou nt ,
length));

main returns an int, so you need a return here.

}

--
Thomas M. Sommers -- tm*@nj.net -- AB2SB