Hi,
Could you tell me whether the following two statement are the same?
Derived class is derived from Base class.
1. Base* ptr1;
2. Derived * ptr2;
Does it mean ptr1 is the same as ptr2?
Thanks in advance,
Michael
5  1961 
"Michael" <mi*******@gmai l.comwrote in message
news:11******** **************@ i42g2000cwa.goo glegroups.com.. .
Hi,
Could you tell me whether the following two statement are the same?
Derived class is derived from Base class.
1. Base* ptr1;
2. Derived * ptr2;
Does it mean ptr1 is the same as ptr2?
No.
The only thing you have listed are declarations. They could be set to point
the same address space, namely an address of an object of type Derived.
Then you could call any member functions of Base from the Base point and any
members of Derived from the derived pointer.
Note: Any virtual functions called from the address contained in Base* would
run from the derived classes data.
--
LTP
:)
Michael wrote:
...
Could you tell me whether the following two statement are the same?
Derived class is derived from Base class.
1. Base* ptr1;
2. Derived * ptr2;
No, they are not the same.
Does it mean ptr1 is the same as ptr2?
I don't understand what you mean here. Types of 'ptr1' and 'ptr2'? Values of
'ptr1' and 'ptr2'? Something else?
--
Best regards,
Andrey Tarasevich
Luc The Perverse wrote:
"Michael" <mi*******@gmai l.comwrote in message
news:11******** **************@ i42g2000cwa.goo glegroups.com.. .
Hi,
Could you tell me whether the following two statement are the same?
Derived class is derived from Base class.
1. Base* ptr1;
2. Derived * ptr2;
Does it mean ptr1 is the same as ptr2?
No.
The only thing you have listed are declarations. They could be set to point
the same address space, namely an address of an object of type Derived.
Then you could call any member functions of Base from the Base point and any
members of Derived from the derived pointer.
Note: Any virtual functions called from the address contained in Base* would
run from the derived classes data.
--
LTP
:)
So a Base point could point to either Base object (complete object) or
Derived object (incomplete object). A Derived point could only point to
Derived object? Right?
Why not use Base* points to Base object and Derived points to Derived
object?
"Michael" <mi*******@gmai l.comwrote in message
news:11******** *************@m 79g2000cwm.goog legroups.com
Luc The Perverse wrote:
>"Michael" <mi*******@gmai l.comwrote in message
news:11******* *************** @i42g2000cwa.go oglegroups.com. ..
>>Hi,
Could you tell me whether the following two statement are the same?
Derived class is derived from Base class.
1. Base* ptr1;
2. Derived * ptr2;
Does it mean ptr1 is the same as ptr2?
No.
The only thing you have listed are declarations. They could be set
to point the same address space, namely an address of an object of
type Derived.
Then you could call any member functions of Base from the Base point
and any members of Derived from the derived pointer.
Note: Any virtual functions called from the address contained in
Base* would run from the derived classes data.
--
LTP
:)
So a Base point could point to either Base object (complete object) or
Derived object (incomplete object). A Derived point could only point
to Derived object? Right?
Why not use Base* points to Base object and Derived points to Derived
object?
Suppose you want to store pointers to Base objects and pointers to Derived
objects in the same container --- or, more likely, pointers to Derived1
objects and pointers to Derived2 objects. How would you do it, given that
the container will only store one type of pointer? Answer: by making the
container store base Base pointers.
--
John Carson
Michael wrote:
Hi,
Could you tell me whether the following two statement are the same?
Derived class is derived from Base class.
1. Base* ptr1;
2. Derived * ptr2;
Does it mean ptr1 is the same as ptr2?
Thanks in advance,
Michael
You can assign a Derived* to ptr1, but you cannot assign a Base* to ptr2. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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