Hi everybody!
I have this function:
int Scan(char String[])
{
printf("%s", String);
}
it works but when I try to pass a dotted string o separetad with (" ",
"_" , "-" ...ecc)
it return only first word.
I pass the string in this way:
char CString[] = "I.am.an.exampl e";
Scan(CString);
What's wrong?
Help me please!
Thx! 28 2939 fe************* *@tiscali.it wrote:
Hi everybody!
I have this function:
int Scan(char String[])
{
printf("%s", String);
}
You declared the function as returning as int but you don't return
anything. Consider changing it to:
void Scan(char String[]);
it works but when I try to pass a dotted string o separetad with (" ",
"_" , "-" ...ecc)
it return only first word.
Well it should print all the characters in the array upto the first
null character. Certainly dots and dashes should be printed.
Have you checked that your array doesn't contain any null characters
embedded before the end of valid data?
I pass the string in this way:
char CString[] = "I.am.an.exampl e";
Scan(CString);
What's wrong?
Until you can show us a complete, compilable example that exhibits your
problem, (copy & paste the code, don't retype it), we can do much more
than keep guessing. fe************* *@tiscali.it wrote:
int Scan(char String[])
{
printf("%s", String);
}
it works but when I try to pass a dotted string o separetad with (" ",
"_" , "-" ...ecc)
it return only first word.
It returns nothing; presumably you mean that it prints that.
I pass the string in this way:
char CString[] = "I.am.an.exampl e";
Scan(CString);
What's wrong?
Something else.
Post a small, compilable sample of code that demonstrates the problem.
It is not in the uncompilable snippets you posted above.
For example, when I compile and run this program:
#include <stdio.h>
int Scan(char String[])
{
printf("%s", String);
}
int main(void)
{
char CString[] = "I.am.an.exampl e";
Scan(CString);
getchar();
return 0;
}
the result is that I.am.an.example is printed, in its entirety.
Richard
Richard Bos wrote:
fe************* *@tiscali.it wrote:
int Scan(char String[])
{
printf("%s", String);
}
it works but when I try to pass a dotted string o separetad with (" ",
"_" , "-" ...ecc)
it return only first word.
It returns nothing; presumably you mean that it prints that.
I pass the string in this way:
char CString[] = "I.am.an.exampl e";
Scan(CString);
What's wrong?
Something else.
Post a small, compilable sample of code that demonstrates the problem.
It is not in the uncompilable snippets you posted above.
For example, when I compile and run this program:
#include <stdio.h>
int Scan(char String[])
{
printf("%s", String);
}
int main(void)
{
char CString[] = "I.am.an.exampl e";
Scan(CString);
getchar();
return 0;
}
the result is that I.am.an.example is printed, in its entirety.
I don't believe that! (I mean, from you, this little slip.)
(Look at http://snipurl.com/iqxx)
"Suman" <sk*****@gmail. comwrote:
>
Richard Bos wrote:
fe************* *@tiscali.it wrote:
int Scan(char String[])
{
printf("%s", String);
}
>
it works but when I try to pass a dotted string o separetad with (" ",
"_" , "-" ...ecc)
it return only first word.
It returns nothing; presumably you mean that it prints that.
I pass the string in this way:
>
char CString[] = "I.am.an.exampl e";
Scan(CString);
>
What's wrong?
Something else.
Post a small, compilable sample of code that demonstrates the problem.
It is not in the uncompilable snippets you posted above.
For example, when I compile and run this program:
#include <stdio.h>
int Scan(char String[])
{
printf("%s", String);
}
int main(void)
{
char CString[] = "I.am.an.exampl e";
Scan(CString);
getchar();
return 0;
}
the result is that I.am.an.example is printed, in its entirety.
I don't believe that!
You are free to disbelieve that the earth is pentangular, for all I
care. I wrote that when _I_ run that program, it prints the entire
string; and it does. As for the final newline, the cursor does indeed
start after the printed string, without a newline in between, and a
newline is only printed when I press enter; this is one legal result of
the program.
Richard
As you want, the original source is...
File Sample.h
void Scan(char String[])
{
printf("%s", String); // this return only 1 word
}
File main.c
#include <stdio.h>
#include "Sample.h"
int main()
{
char SampleString[] = "I.am.a.sample. string";
Scan(SampleStri ng);
return 0;
}
Help me! fe************* *@tiscali.it wrote:
As you want, the original source is...
File Sample.h
void Scan(char String[])
{
printf("%s", String); // this return only 1 word
}
Why are putting the function definition in a header file? Place the
definition in main.c and only the declaration in Sample.h
By the way, you don't provide a function declaration at all.
Also include a newline character at the end of your printf() format
string. Otherwise, the output is not guaranteed to appear on the output
device.
File main.c
#include <stdio.h>
#include "Sample.h"
int main()
Use the form int main(void)
{
char SampleString[] = "I.am.a.sample. string";
Scan(SampleStri ng);
return 0;
}
The program should print the string correctly. Your code compiles and
behaves as it should on my system. I suggest adding a newline at the
end of the printf() statement in Scan(). What is the exact output that
you're getting?
On 2006-07-04, Richard Bos <rl*@hoekstra-uitgeverij.nlwr ote:
fe************* *@tiscali.it wrote:
>int Scan(char String[]) { printf("%s", String); }
it works but when I try to pass a dotted string o separetad with (" ", "_" , "-" ...ecc) it return only first word.
It returns nothing; presumably you mean that it prints that.
Actually, I wouldn't doubt that some register issue is causing it
to in fact return the first word. Since dropping off the end of a
non-void function is undefined, this is more than plausible.
That and the fact that if this were true, he would be returning a
pointer as an int... the implications of UB are very interesting.
--
Andrew Poelstra <http://www.wpsoftware. net/blog>
To email me, use "apoelstra" at the above address.
"You people hate mathematics." -- James Harris fe************* *@tiscali.it wrote:
As you want, the original source is...
File Sample.h
void Scan(char String[])
{
printf("%s", String); // this return only 1 word
}
File main.c
#include <stdio.h>
#include "Sample.h"
int main()
{
char SampleString[] = "I.am.a.sample. string";
Scan(SampleStri ng);
return 0;
}
Help me!
No problem here. The program just prints the entire string
'I.am.a.sample. string' and exits.
So what do you think is wrong with it? Have you tested this
code snippet be yourself? Only this snippet, not embedded in
a greater project. Maybe you have some function overloading,
because by the name Scan seems to do something different
than only printing.
Bart
On 2006-07-04, fe************* *@tiscali.it <fe************ **@tiscali.itwr ote:
As you want, the original source is...
File Sample.h
void Scan(char String[])
You should declare, not define, functions in headers. The below belongs
in your .c file.
{
printf("%s", String); // this return only 1 word
I can't imagine how you know that, being as you don't check printf()'s
return value. Also, // is a syntax error in C89, which no doubt you are
supposed to be using.
Also, that statement is equivilant to puts (string); which is likely more
efficient, not to mention easier to read.
}
File main.c
#include <stdio.h>
#include "Sample.h"
int main()
int main(void) is clearer.
{
char SampleString[] = "I.am.a.sample. string";
Indent properly with 2 or 4 spaces.
Scan(SampleStri ng);
This function would be better-named Print, no?
return 0;
}
Help me!
Other than that, it compiles cleanly. And it behaves exactly as
others have said that it does.
However, SampleString does not have a \n at the end, and so you
have no guarantee that anything will display at all.
--
Andrew Poelstra <http://www.wpsoftware. net/blog>
To email me, use "apoelstra" at the above address.
"You people hate mathematics." -- James Harris This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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