Help is need immidiately

[vinod.bhavnani]

Hello all,

I need desperate help

Here is the problem:

My problem today is with multidimensiona l arrays.

Lets say i have an array A[31][130][256][256] this is a 4 dimensional
static array.

How will i declare this same array with same dimensions dynamically and
also after dynamic declaration i want to be able to access contents of
array with indiceslike i should be able to access an elemt after after
dynamic declarartion as
A[23][34][56][78].Is this possible

Please help

Now pls remember that memory space for the array is not a concern and i
cant change this data structure

Thanks

[Robert Gamble]

vi************@ gmail.com wrote:

Hello all,

I need desperate help

Here is the problem:

My problem today is with multidimensiona l arrays.

Lets say i have an array A[31][130][256][256] this is a 4 dimensional
static array.

How will i declare this same array with same dimensions dynamically and
also after dynamic declaration i want to be able to access contents of
array with indiceslike i should be able to access an elemt after after
dynamic declarartion as
A[23][34][56][78].Is this possible

Please help

Now pls remember that memory space for the array is not a concern and i
cant change this data structure

This is an FAQ question. The FAQ can be found at <http://c-faq.com/>,
your question is 6.16. If after reading the answer and trying to
implement the solution to fit your needs you have a specific question,
come back with what you have so far and a clear description of where
your problem lies.

Robert Gamble

[Walter Roberson]

In article <11************ **********@g10g 2000cwb.googleg roups.com>,
<vi************ @gmail.com> wrote:

I need desperate help Now pls remember that memory space for the array is not a concern and i
cant change this data structure
We generally find that people when people don't leave homework
to the last minute, that they don't need desperate immediate help.

Here is the problem: My problem today is with multidimensiona l arrays. Lets say i have an array A[31][130][256][256] this is a 4 dimensional
static array. How will i declare this same array with same dimensions dynamically

If it is the 'same array' then it would have the same properties
of being static and with those exact fixed dimensions. It would be
a contradiction in the question to ask to allocate a static array
dynamically, or to allocate an array with exact fixed dimensions
with variable dimensions.
--
If you lie to the compiler, it will get its revenge. -- Henry Spencer

[vinod.bhavnani]

Hi,

After reading the stuff i still have no idea as to how u would proceed
with a 4 dimensional array.I would really appreiciate it if someone who
actually knows how to assign a dynamic 4-D array in C could please help
me out.

Thanks

[vinod.bhavnani]

Hey,

Okay i havent written that correctly.There arent 2 arrays.I just want
to declare a dynamic array A[31][130][256][256] and access it with
indices like i would a static array.

Thanks

[Eric Sosman]

vi************@ gmail.com wrote On 05/30/06 12:46,:

Hey,

Okay i havent written that correctly.There arent 2 arrays.I just want
to declare a dynamic array A[31][130][256][256] and access it with
indices like i would a static array.

SomeType (*A)[31][130][256][256];
A = malloc(sizeof *A);
if (A == NULL)
abort();
A[1][2][3][4] = 42;

--
Er*********@sun .com

[Default User]

vi************@ gmail.com wrote:

Hi,

After reading the stuff i still have no idea as to how u would proceed
with a 4 dimensional array.I would really appreiciate it if someone
who actually knows how to assign a dynamic 4-D array in C could
please help me out.

Please review the .sig information at the end of this message.

What about the FAQ answer confuses you? You haven't explained why you
are having problems. What have you tried? Have you created a 2-D
dynamic array?

What do you want a dynamic array? Normally that is for when you don't
know the size of the dimensions. This problem smells like homework. You
haven't presented the overall problem, just "how do I do a dynamic 4-D
array." You haven't said WHY you want such a beast, nor have you said
what you mean by such an array.

Brian

--
Please quote enough of the previous message for context. To do so from
Google, click "show options" and use the Reply shown in the expanded
header.

[Barry Schwarz]

On Tue, 30 May 2006 12:50:17 -0400, Eric Sosman <Er*********@su n.com>
wrote:

vi************ @gmail.com wrote On 05/30/06 12:46,:

Hey,

Okay i havent written that correctly.There arent 2 arrays.I just want
to declare a dynamic array A[31][130][256][256] and access it with
indices like i would a static array.

SomeType (*A)[31][130][256][256];
A = malloc(sizeof *A);
if (A == NULL)
abort();
A[1][2][3][4] = 42;

I'm sure you really meant
(*A)[1][2][3][4] = 42;
Remove del for email

[vinod.bhavnani]

this is all good but guys i need to access the arrays like
a static array and not with pointer referencing
like i need to access A with A[][][][].Please is there someone who can
suggest a technique.there have been many qs asked as to why i need the
array ,what about the memory,FAQs i need to read.I thought i can get
some real help here.Is there no one who can actually solve the
problem.Why is there a need to give an alternate solution.I dont
require alternates.This is the problem plain and simple i have a to
declare a 4 dimensional dynamic array and need to then aces it like a
static array with normal array indices like a[][][][] and not
*A(i*j*k).I know the compiler treats it the same .But i need the access
to it through A[][][][].Please anyone.I would really appreciate a
solution then some condesecnding remarks or an alterante solution.

Thanks,
Barry Schwarz wrote:

On Tue, 30 May 2006 12:50:17 -0400, Eric Sosman <Er*********@su n.com>
wrote:

vi************ @gmail.com wrote On 05/30/06 12:46,:

Hey,

Okay i havent written that correctly.There arent 2 arrays.I just want
to declare a dynamic array A[31][130][256][256] and access it with
indices like i would a static array.

SomeType (*A)[31][130][256][256];
A = malloc(sizeof *A);
if (A == NULL)
abort();
A[1][2][3][4] = 42;

I'm sure you really meant
(*A)[1][2][3][4] = 42;
Remove del for email

[Eric Sosman]

Barry Schwarz wrote On 05/30/06 20:48,:

On Tue, 30 May 2006 12:50:17 -0400, Eric Sosman <Er*********@su n.com>
wrote:

vi*********** *@gmail.com wrote On 05/30/06 12:46,:

Hey,

Okay i havent written that correctly.There arent 2 arrays.I just want
to declare a dynamic array A[31][130][256][256] and access it with
indices like i would a static array.

SomeType (*A)[31][130][256][256];
A = malloc(sizeof *A);
if (A == NULL)
abort();
A[1][2][3][4] = 42;

I'm sure you really meant
(*A)[1][2][3][4] = 42;

Good catch, but wrong diagnosis. What I *really*
meant was (ahem, ahem):

SomeType (*A)[130][256][256];
A = malloc(31 * sizeof *A);
if (A == NULL)
abort();
A[1][2[3][4] = 42;

(I guess you can tell who doesn't recall the last time
he used a 4D array ... Thanks for the eagle eye.)

--
Er*********@sun .com