A simple 'C' problem

[Aravindh]

A 'C' program that takes two numbers and produces two other numbers.
None of the four numbers must be similar.

printf ("%d%d", & num1, & num2) ;
if (num1 > num2) {
num1 ++ ; num2 -- ;
}
else {
num1 --; num2 ++ ;
}
printf ("%d%d\n", num1, num2) ;

Any better ideas ?

[Eric Sosman]

Aravindh wrote On 03/02/06 13:04,:

A 'C' program that takes two numbers and produces two other numbers.
None of the four numbers must be similar.

printf ("%d%d", & num1, & num2) ;
if (num1 > num2) {
num1 ++ ; num2 -- ;
}
else {
num1 --; num2 ++ ;
}
printf ("%d%d\n", num1, num2) ;

Any better ideas ?

Almost any idea would be better. "Jellybean pizza"
would be better.

(If you want suggestions about a program, post a
program and not a couple randomly-chosen lines of out-
of-context code. Even in the little you've provided
I can see two guaranteed mistakes; who knows how many
the complete program holds?)

--
Er*********@sun .com

[Micah Cowan]

"Aravindh" <ar********@gma il.com> writes:

A 'C' program that takes two numbers and produces two other numbers.
None of the four numbers must be similar.

printf ("%d%d", & num1, & num2) ;
if (num1 > num2) {
num1 ++ ; num2 -- ;
}
else {
num1 --; num2 ++ ;
}
printf ("%d%d\n", num1, num2) ;

Any better ideas ?

The above code is not compileable. Please post complete examples.

I think you meant to use scanf() rather than printf() for the first
one.

Your state problem is *very* vague... the solutions are infinite. You
could even ignore the input numbers and produce the results of rand()
or something.

[Richard Heathfield]

Micah Cowan said:

"Aravindh" <ar********@gma il.com> writes:

A 'C' program that takes two numbers and produces two other numbers.
None of the four numbers must be similar.

<snip>
Your state problem is *very* vague... the solutions are infinite. You
could even ignore the input numbers and produce the results of rand()
or something.

No, he can't (if my understanding of the problem is correct), in case the
result of rand() produces one or other (or even both) of the two input
numbers.

This should do it:

#include <stdio.h>
#include <limits.h>
#include "thirdpartyerro rmodule.h"

void silly(unsigned int m, unsigned int n)
{
unsigned int x = UINT_MAX - m;
unsigned int y = UINT_MAX - n;
if(m == n) { error("input error - numbers are duplicates"); }

/* x is definitely different from m (UINT_MAX is odd) */
/* y is definitely different from n (UINT_MAX is odd) */
/* m is definitely different from n (checked already) */
/* x is definitely different from y (because m != n) */
/* m might equal y, in which case x will equal n */

if(m == y)
{
m += 2; /* still != x, no longer == y, might be == n */
n += 2; /* still != y, no longer == x, no longer == n */
}

printf("%u %u %u %u\n", m, n, x, y);
}

--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999
http://www.cpax.org.uk
email: rjh at above domain (but drop the www, obviously)

[Vladimir S. Oka]

Aravindh wrote:

A 'C' program that takes two numbers and produces two other numbers.
None of the four numbers must be similar.
Could you define "similar"? Or is my non-native English failing me?
printf ("%d%d", & num1, & num2) ;
You either meant `scanf`, or you really have no clue...
if (num1 > num2) {
num1 ++ ; num2 -- ;
}
else {
num1 --; num2 ++ ;
}
printf ("%d%d\n", num1, num2) ;

Any better ideas ?

Define "better". Unless you mean "correct, compilable code"?

Heed other comments given elsethread as well.

--
BR, Vladimir

Marriage is not merely sharing the fettucine, but sharing the
burden of finding the fettucine restaurant in the first place.
-- Calvin Trillin

[Micah Cowan]

Richard Heathfield <in*****@invali d.invalid> writes:

Micah Cowan said:

"Aravindh" <ar********@gma il.com> writes:

A 'C' program that takes two numbers and produces two other numbers.
None of the four numbers must be similar.

<snip>

Your state problem is *very* vague... the solutions are infinite. You
could even ignore the input numbers and produce the results of rand()
or something.

No, he can't (if my understanding of the problem is correct), in case the
result of rand() produces one or other (or even both) of the two input
numbers.

This should do it:

#include <stdio.h>
#include <limits.h>
#include "thirdpartyerro rmodule.h"

void silly(unsigned int m, unsigned int n)
{
unsigned int x = UINT_MAX - m;
unsigned int y = UINT_MAX - n;
if(m == n) { error("input error - numbers are duplicates"); }

/* x is definitely different from m (UINT_MAX is odd) */
/* y is definitely different from n (UINT_MAX is odd) */
/* m is definitely different from n (checked already) */
/* x is definitely different from y (because m != n) */
/* m might equal y, in which case x will equal n */

if(m == y)
{
m += 2; /* still != x, no longer == y, might be == n */
n += 2; /* still != y, no longer == x, no longer == n */
}

You've forgotten that you're now changing the inputs; you ought to
modify x and y instead... also, I'm assuming that last comment was
meant to be ... no longer == m ?

if (x == n)
{
x += 2; /* still != m, no longer == n, might be == y */
y += 2; /* still != n, no longer == m, no longer == x */
}

However, I don't think you need the second one, as the "might be == y"
s/b false. Because, x will only equal n if x != y modulo 2, which
means that also m != n modulo 2, and therefore adding 2 to x will
never let it be equal to y for the same reason that it's still not
equal to m.

I could be having a brain-fart, but ATM I think that's right.

[Richard Heathfield]

Micah Cowan said:

Richard Heathfield <in*****@invali d.invalid> writes:

You've forgotten that you're now changing the inputs; you ought to
modify x and y instead...
Oops, oh yeah...
also, I'm assuming that last comment was
meant to be ... no longer == m ?
Probably.
I could be having a brain-fart, but ATM I think that's right.

I find myself in 100% agreement with you. ;-)

(btw: wb, ltns, hand)

--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999
http://www.cpax.org.uk
email: rjh at above domain (but drop the www, obviously)

[Thad Smith]

Aravindh wrote:

A 'C' program that takes two numbers and produces two other numbers.
None of the four numbers must be similar.

Define similar.

--
Thad

[Micah Cowan]

Richard Heathfield <in*****@invali d.invalid> writes:

(btw: wb, ltns, hand)

^^ ^^^^

Okay, I need these two explained to me: VERA doesn't have 'em...

:-)

[Jordan Abel]

On 2006-03-03, Micah Cowan <mi***@cowan.na me> wrote:

Richard Heathfield <in*****@invali d.invalid> writes:

(btw: wb, ltns, hand) ^^ ^^^^

Okay, I need these two explained to me: VERA doesn't have 'em...

wb: welcome back.
ltns: long time no see.
:-)