Hello all,
If c is a char then is there any difference between
c = '\0'
and
c = 0
?
Regards,
August
Nov 14 '05
39 4482
August Karlstrom wrote: Malcolm wrote: Lint is of limited value. '\0' is the character constant NUL that represents a terminated string, whilst 0 is the integer value of nothing.
(The literal 0 can also denote the nil pointer)
A nil pointer? Perhaps you mean NULL pointer constant, but this would
not apply to type char which is being discussed here...
Rob Gamble
Robert Gamble wrote: August Karlstrom wrote:
Malcolm wrote:
Lint is of limited value. '\0' is the character constant NUL that represents a terminated string, whilst 0 is the integer value of nothing.
(The literal 0 can also denote the nil pointer)
A nil pointer? Perhaps you mean NULL pointer constant, but this would not apply to type char which is being discussed here...
I used "nil pointer" to emphasize the distinction between the "points to
nothing" concept and the C macro constant NULL. In Oberon for instance,
NIL is a keyword (typeless constant) used for pointers and variables of
procedure type.
-- August
August Karlstrom wrote on 29/05/05 : If c is a char then is there any difference between c = '\0' and c = 0
The Lint program Splint thinks there is a difference: int main(void) { char c;
c = '\0'; c = 0; return 0; } $ splint test.c Splint 3.1.1 --- 15 Jun 2004
test.c: (in function main) test.c:6:4: Assignment of int to char: c = 0 Types are incompatible. (Use -type to inhibit warning)
Finished checking --- 1 code warning
It's true that and int is not a char. Why in the world are you using a
char ? The cases where a single char is necessary are extremely rare
(only scanf("%c", &c) comes to my mind, and scanf() is not a
recommended function...)
That said, Lint seems to consider that '\0' is a char that is wrong in
C. (Or maybe, Lint is checking in C++ mode, in that case 0 is an int
and '\0' is a char). Your extension seems to be .c, that is correct for
a C-program. Check the Lint configuration.
--
Emmanuel
The C-FAQ: http://www.eskimo.com/~scs/C-faq/faq.html
The C-library: http://www.dinkumware.com/refxc.html
"Mal nommer les choses c'est ajouter du malheur au
monde." -- Albert Camus.
Robert Gamble wrote on 29/05/05 : (The literal 0 can also denote the nil pointer)
A nil pointer? Perhaps you mean NULL pointer constant, but this would not apply to type char which is being discussed here...
'nil pointer' is a generic term used in Computer Science. Its
C-implementation is null pointer constant or NULL.
--
Emmanuel
The C-FAQ: http://www.eskimo.com/~scs/C-faq/faq.html
The C-library: http://www.dinkumware.com/refxc.html
..sig under repair
August Karlstrom wrote: Robert Gamble wrote: August Karlstrom wrote:
Malcolm wrote:
Lint is of limited value. '\0' is the character constant NUL that represents a terminated string, whilst 0 is the integer value of nothing.
(The literal 0 can also denote the nil pointer)
A nil pointer? Perhaps you mean NULL pointer constant, but this would not apply to type char which is being discussed here...
I used "nil pointer" to emphasize the distinction between the "points to nothing" concept and the C macro constant NULL.
You said that literal 0 can denote the "nil pointer". There is no nil
pointer in C, but there is a NULL pointer constant which can be
expressed as a literal 0 in a pointer context. I don't see any
distinction in your statement, on the contrary it looks like you are
confused. In C, the NULL pointer "points to nothing", there is no
seperate concept of nil in C.
In Oberon for instance, NIL is a keyword (typeless constant) used for pointers and variables of procedure type.
This is C and there is no such thing.
-- August
Rob Gamble
"Emmanuel Delahaye" <em***@YOURBRAn oos.fr> writes:
[...] That said, Lint seems to consider that '\0' is a char that is wrong in C. (Or maybe, Lint is checking in C++ mode, in that case 0 is an int and '\0' is a char). Your extension seems to be .c, that is correct for a C-program. Check the Lint configuration.
I wouldn't say that Splint (the particular lint implementation that
generates the message) is wrong to issue a warning. It's not required
to limit itself to complaining about violations of the standard. It's
diagnosting (what its authors see as) a style issue -- which is part
of what lint is supposed to do. I happen to agree with it in this
case; initializing a char object with '\0' is clearer than using 0,
even though it's semantically identical.
On the other hand, the error message itself is probably incorrect.
The message is:
test.c:6:4: Assignment of int to char: c = 0 Types are incompatible. (Use -type to inhibit warning)
In fact, types int and char are compatible for assignment (but not for
some other purposes). A naive programmer might infer from the message
that implicit conversions are a bad thing; this is a dangerous
assumption, since the obvious way to avoid them is to use casts, which
can be far more dangerous. And using the "-type" option would
probably inhibit some useful warnings.
A digression: In my opinion, C depends too heavily on implicit
conversions. If I were designing the language from scratch, most
conversions that are implicit in C would probably be explicit -- but
most of them would be expressed by some mechanism less heavyweight
than a cast. The resulting code would probably be more verbose than
typical C. If you like extreme terseness, be glad that I don't
actually design programming languages. But given the actual design of
C, it almost always makes sense to use implicit conversions rather
than explicit casts, which tend to swat flies with sledgehammers.
Implicit conversions are bad from a language design point of view, but
good (or at least far better than the alternative) from a C
programming point of view.
--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.
"August Karlstrom" <fu********@com hem.se> wrote I used "nil pointer" to emphasize the distinction between the "points to nothing" concept and the C macro constant NULL. In Oberon for instance, NIL is a keyword (typeless constant) used for pointers and variables of procedure type.
Conventionally C uses all bits zero to represent an invalid pointer. On a
few machines this isn't useful (maybe because of hardware traps or something
like that) so a different bit pattern will be used. The constant zero and
the definition NULL always represent this pointer, however.
There is no reason you cannot use other addresses to represent invalid
pointers internally, however. I cannot think of a good reason for so doing,
but it would be perfectly possible to set up a global somewhere and then
test against it before reading or writing. These would be nil pointers but
not null pointers.
(The situation isn't quite as simple as I have painted it because it is
illegal to do any sort of calculation with an invalid pointer, except a null
pointer. So strategies along the lines of
#define MYNULL 12345678
will work on some compliers but not all. The act of loading this address
into a rgister may trigger an error.).
"Malcolm" <re*******@btin ternet.com> writes: "August Karlstrom" <fu********@com hem.se> wrote I used "nil pointer" to emphasize the distinction between the "points to nothing" concept and the C macro constant NULL. In Oberon for instance, NIL is a keyword (typeless constant) used for pointers and variables of procedure type.
Conventionally C uses all bits zero to represent an invalid pointer. On a few machines this isn't useful (maybe because of hardware traps or something like that) so a different bit pattern will be used. The constant zero and the definition NULL always represent this pointer, however.
I would state this differently, to de-emphasize the idea that
all-bits-zero is "convention al".
C uses some specific pointer representation to represent a null
pointer. This is represented in source by a null pointer constant,
such as a literal 0 or the macro NULL. On many (most?)
implementations the internal representation happens to be
all-bits-zero, but well written C code does not know or care what the
actual representation is; it can even be different for different
pointer types.
(If you had written "typically" rather than "conventionally ", I
wouldn't have had any quarrel.)
--
Keith Thompson (The_Other_Keit h) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
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