pointer to stuct data

[Robert S]

hello,
I am investigating a code,which has data struct deelacration as follow:

typedef struct {
char *infile;
char inoptsbuf[10];
char *outfile;
} cmdoption_a;

cmdoption_a *cmdoption;

and intialization as follow:

cmdoption->infile=1;
cmdoption->outfile=1;
cmdoption->inoptsbuf='\0' ;

I am really confused since an integer is assign to the above variables?!!!!
any help??!!

bob

[Christopher Benson-Manica]

Robert S <b_******@yahoo .com> spoke thus:

So 0 means NULL,however I thought '\0' means NULL

'\0' is NUL, the null character. It is not the same as NULL.

--
Christopher Benson-Manica | I *should* know what I'm talking about - if I
ataru(at)cybers pace.org | don't, I need to know. Flames welcome.

[Fred L. Kleinschmidt]

Robert S wrote:

thanks
It is a transcoder proram which compile and run without a problem
here is the code:

typedef struct {

char *infile;
/* The input image file. */

int infmt;
/* The input image file format. */

char *inopts;
char inoptsbuf[OPTSMAX + 1];

char *outfile;
/* The output image file. */

int outfmt;

char *outopts;
char outoptsbuf[OPTSMAX + 1];

int verbose;
/* Verbose mode. */

int debug;

int version;

int_fast32_t cmptno;

int srgb;

} cmdopts_t;
.
.
.
.
.
cmdopts_t *cmdopts;

cmdopts->infile = 0; This line is still an error, if you have shown the entire code.
cmdopts is a pointer, but does not yet point to anything. You cannot
dereference it.

There should be something like this somewhere:
cmdopts_t xxx;
cmdopts_t *cmdopts = &xxx;
cmdopts->infmt = -1;
cmdopts->inopts = 0;
cmdopts->inoptsbuf[0] = '\0';
cmdopts->outfile = 0;
cmdopts->outfmt = -1;
cmdopts->outopts = 0;
cmdopts->outoptsbuf[0] = '\0';
cmdopts->verbose = 0;
cmdopts->version = 0;
cmdopts->cmptno = -1;
cmdopts->debug = 0;
cmdopts->srgb = 0;
.
.
.
.

"Artie Gold" <ar*******@aust in.rr.com> wrote in message
news:3c******** *****@individua l.net...

Robert S wrote:

hello,
I am investigating a code,which has data struct deelacration as follow:
typedef struct {
char *infile;
char inoptsbuf[10];
char *outfile;
} cmdoption_a;

cmdoption_a *cmdoption;

and intialization as follow:

cmdoption->infile=1;
cmdoption->outfile=1;
cmdoption->inoptsbuf='\0' ;

I am really confused since an integer is assign to the above variables?!!!! any help??!!

You *should* be confused; the code (as you've quoted it) makes no

sense

at all, would (should?) not compile and certainly couldn't possibly

work.

Why not post the *real* code (i.e. cut and paste, don't transcribe)?

I'm

sure someone here could clear up any confusion.

HTH,
--ag

--
Artie Gold -- Austin, Texas
http://it-matters.blogspot.com (new post 12/5)
http://www.cafepress.com/goldsays

--
Fred L. Kleinschmidt
Boeing Associate Technical Fellow
Technical Architect, Common User Interface Services
M/S 2R-94 [phone]

[Richard Bos]

Christopher Benson-Manica <at***@nospam.c yberspace.org> wrote:

Robert S <b_******@yahoo .com> spoke thus:

So 0 means NULL,however I thought '\0' means NULL

'\0' is NUL, the null character. It is not the same as NULL.

All the same, '\0' is a null pointer constant, so it's legal (though
massively unwise) as a value for NULL.

Richard

[pete]

Richard Bos wrote:

Christopher Benson-Manica <at***@nospam.c yberspace.org> wrote:

Robert S <b_******@yahoo .com> spoke thus:

So 0 means NULL,however I thought '\0' means NULL

'\0' is NUL, the null character. It is not the same as NULL.

All the same, '\0' is a null pointer constant, so it's legal (though
massively unwise) as a value for NULL.

'\0' can be used anywhere that NULL can be used,
but NULL can't be used everywhere that '\0' can be used.

--
pete